Or you may calculate manually:
Dim nNum As Long = 32768
Dim nHour As Long
Dim nMin, nSec As Byte
nHour = Int(nNum / 3600)
nMin = Int(nNum / 60) - nHour * 60
nSec = nNum - (nHour * 3600 + nMin * 60)
>
> Hello.
> It was good to use Time(0, 0, seconds) but for now I need to use more
> seconds.
>
Le 29/07/2013 18:22, abbat81 a écrit :
> Benoît Minisini wrote
>> Format(nSeconds / 3600 / 24, "hh:nn:ss")
>
>
> Benoît, I cant understand how to use this.
>
> All I got - "bad format string"
>
Sorry, I meant: Format(CDate(nSeconds / 3600 / 24), "hh:nn:ss")
--
Benoît Minisini
-
Benoît Minisini wrote
> Format(nSeconds / 3600 / 24, "hh:nn:ss")
Benoît, I cant understand how to use this.
All I got - "bad format string"
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Le 29/07/2013 17:42, abbat81 a écrit :
>
> Hello.
> It was good to use Time(0, 0, seconds) but for now I need to use more
> seconds.
>
> So, now I get:
>
> Print Time(0, 0, 32767) => 09:06:07
> Print Time(0, 0, 32768) => 14:53:52 (00/00/ 14:53:52)
>
> How can I get Format("hh:nn:ss") from se
Hello.
It was good to use Time(0, 0, seconds) but for now I need to use more
seconds.
So, now I get:
Print Time(0, 0, 32767) => 09:06:07
Print Time(0, 0, 32768) => 14:53:52 (00/00/ 14:53:52)
How can I get Format("hh:nn:ss") from seconds?
Thanks.
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