i tried a solution ..
int A
{
spin_lock a
x=0
func A()
x=1;
spin_unlock a
}
int B
{
done = false;
while(done == false)
{
spin_lock a;
if(x==1){
func B()
spin_unlock a;
done = true;
}
In data lunedì 08 febbraio 2010 17:50:29, Mulyadi Santosa ha scritto:
> First idea that crosses my mind is:
>
> create an atomic (maybe 64 bit one?) counter. Increase it every time
> funcA() is executed. then, create same type of counter, let;s name it
> old_counter...
LOL, Exactly what I tried.
Hi!
On 13:45 Mon 08 Feb , Andrea Gasparini wrote:
> Hi,
> Let's say I have two kind of interrupt: IntA e IntB
> After the former, I should do something, let's say "funcA()".
> and after the second I should do (guess what?) funcB().
>
> My constraints are that funcB have to be called after th
Hi,
Let's say I have two kind of interrupt: IntA e IntB
After the former, I should do something, let's say "funcA()".
and after the second I should do (guess what?) funcB().
My constraints are that funcB have to be called after the relative funcA,
and *not* viceversa, and funcA have to be called
