Message -
From: "Graeme B. Davis" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, October 10, 2003 2:12 PM
Subject: Converting GMT stored data into other zones
| I was wondering if anyone had any tricks on the best way to handle
| localizing time zones in
27;t know how to work around this...
Regards,
Graeme
| On 10 Oct 2003 at 14:12, Graeme B. Davis wrote:
|
| > BUT, I've run into a problem when you want to GROUP BY
| > DAYOFYEAR(datefield) for example, I want it to do the grouping by
EDT
| > and not GMT -- is this possible?
|
| You
I was wondering if anyone had any tricks on the best way to handle
localizing time zones in MySql?
For example, all my datetime data is stored as GMT. I have written
tools to query the data based upon whatever local time zone you want
to use. So, for example if I query for 2003-10-1 to 2003-10-2
I'm having a problem in a query that I'm trying to do.
I have a database of tickets and I want to get "the average numbers of
tickets created per agent per hour over a date range" in the format:
Hour | Avg per agent
This is what I have so far:
SELECT HOUR(created) AS hourcreated, COUNT(*) AS
Does anyone have a quick tip on how to format a float/numeric in the
following currency format with a query?
$xx,xxx.xx
Thanks!
Graeme
-
Before posting, please check:
http://www.mysql.com/manual.php (the manual)
http
Evans" <[EMAIL PROTECTED]>
To: "Graeme B. Davis" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Tuesday, May 22, 2001 1:04 PM
Subject: Re: Average of all NON-NULL columns in a ROW?
> Select avg(id1) from where id1 is not null; ?
>
> - Original Message
Is there a way to get the AVG of all specified NON-NULL columns in one row?
Right now I am doing this in a little script, but it would be nice if I
could do something like this:
DATA
-
id1044NULL3NULL
I want the average of 0,4,4,3 ie (0+4+4+3)/4
is there a way to
From: "Dibo Chen" <[EMAIL PROTECTED]>
To: "Graeme B. Davis" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Friday, May 18, 2001 2:53 PM
Subject: Re: Hierarchy Queries - Multiple LEFT JOINs of the same table?
> try:
>
> select s3.name from staff
I have a staff database which contains a column that has a "reports to"
field.
If I have a table like this:
IDNameReports To
1 Graeme 5
3 Bob 6
5 Sue 3
How can I (in one query) find the next 2 levels of people that Graeme
reports to?
Ie, I
Ok now I understand -- it's on a per-connection basis =)
thanks,
graeme
- Original Message -
From: "Graeme B. Davis" <[EMAIL PROTECTED]>
To: "Gerald Clark" <[EMAIL PROTECTED]>; "Braxton Robbason"
<[EMAIL PROTECTED]>
Cc: <[EMAIL PRO
one line for each row
> of 'outages'
>
> Leave out the "from outages"
>
> Graeme B. Davis wrote:
>
> > mysql> INSERT INTO outages (status) VALUES ('Open');
> > mysql> SELECT LAST_INSERT_ID() AS lid FROM outages;
> > +-+
&g
mysql> INSERT INTO outages (status) VALUES ('Open');
mysql> SELECT LAST_INSERT_ID() AS lid FROM outages;
+-+
| lid |
+-+
| 101 |
| 101 |
| 101 |
+-+
3 rows in set (0.00 sec)
Why would MYSQL do this? Any ideas?
Thanks,
Graeme
p.s. DESCRIBE outages;
+---+---
Is it possible to have the following situation:
Schema:
id
first
last
optional_id
I want to do a select like this:
SELECT D.id, D.first, D.last, D.optional_id, db1.first, db1.last
FROM db1 AS D
LEFT JOIN db1 ON D.optional_id=db1.id;
and have it return:
|id|first|last|optional_id|first|last|
Mascon is sweet, but it's not free :)
> can anyone suggest a good GUI client to suggest to MySQL hosting
> customers?
-
Before posting, please check:
http://www.mysql.com/manual.php (the manual)
http://lists.mysql.com/
I have a GROUPing question on the following query:
SELECT HOUR(closedtime) AS hour, COUNT(assignedto) AS count FROM db WHERE
(closedtime >='2001-01-01' AND closedtime <= '2001-01-31 23:59:59') AND
assignedto='person' GROUP BY hour;
give something like this:
+--++---+
| hour
Any ideas on this error? I'd love to use fulltext, but the last server that
compiled for me was 3.23.14 :(
c++ -DMYSQL_SERVER -DDEFAULT_MYSQL_HOME="\"/var/home/ap
psweb/newmysql\"" -DDATADIR="\"/var/home/appsweb/newmysql/
var\"" -DSHARE
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