=> $thevalue){
$defaultValues['ib_article'][$thevalue] = 'true';
}
I'm not sure if the indices line up exactly with what you had in mind,
but
I'm confident you can play with it to get what you want.
-Original Message-
From: Charles Kline [mailto:[EMAIL
in the loop
> I have no idea what is being pulled from where, so I can't really give
> a
> good example
>
> -----Original Message-
> From: Charles Kline [mailto:[EMAIL PROTECTED]
> Sent: Monday, March 31, 2003 1:25 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] usi
---
From: Charles Kline [mailto:[EMAIL PROTECTED]
Sent: Monday, March 31, 2003 1:25 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] using a variable as values in an array
I am trying to build an array from the results of a query on a mySQL
table.
I am using a loop to create this string in a vari
bject: [PHP-DB] using a variable as values in an array
I am trying to build an array from the results of a query on a mySQL
table.
I am using a loop to create this string in a variable $mystring:
'30'=>true, '20'=>true
I then need to use it like this:
$defaul
I am trying to build an array from the results of a query on a mySQL
table.
I am using a loop to create this string in a variable $mystring:
'30'=>true, '20'=>true
I then need to use it like this:
$defaultValues['ib_article'] = array($mystring);
It isn't working. I am sure there is a better
