On 2016-08-18 14:10, GP wrote:
On Thursday, August 18, 2016 at 5:59:43 PM UTC+5:30, Peter Otten wrote:
GP wrote:
[snip]
However, when you really want to remove all items you instead assign a new
empty list
for item in items:
print(item)
items = []
Thanks Peter for the information. It
On Thursday, August 18, 2016 at 5:59:43 PM UTC+5:30, Peter Otten wrote:
> GP wrote:
>
> The error and your second snippet aren't compatible, so I assume the
> exception is raised by
>
> > for k in range(0,len(shelf)):
> > q1=ListDictItem[k]
> > q2 = ListDictItem.pop(k) #deletes the i
GP wrote:
The error and your second snippet aren't compatible, so I assume the
exception is raised by
> for k in range(0,len(shelf)):
> q1=ListDictItem[k]
> q2 = ListDictItem.pop(k) #deletes the items that are packed.
> Error message:Traceback (most recent call last):
> File "C:\P
I have a list dictionary of items:
ListDictItem = [ {'Item No': 1,'Weight':610,'Quantity':2},{'Item No':
2,'Weight':610,'Quantity':2},{'Item No': 3,'Weight':500,'Quantity':2},{'Item
No': 4,'Weight':484,'Quantity':2},{'Item No':
5,'Weight':470,'Quantity':2},{'Item No': 6,'Weight':440,'Quantity
