gt; convert that to a formula using the as.formula function.
>
> --
> Gregory (Greg) L. Snow Ph.D.
> Statistical Data Center
> Intermountain Healthcare
> greg.s...@imail.org
> 801.408.8111
>
>
>> -Original Message-
>> From: Matthew Douglas [mailto:mat
> are 0/1 then use solve. A lot depends on what you are doing and what
> questions you are trying to answer.
>
> --
> Gregory (Greg) L. Snow Ph.D.
> Statistical Data Center
> Intermountain Healthcare
> greg.s...@imail.org
> 801.408.8111
>
>
>> -Original M
hcare
> greg.s...@imail.org
> 801.408.8111
>
>
>> -----Original Message-
>> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
>> project.org] On Behalf Of Matthew Douglas
>> Sent: Monday, February 28, 2011 1:32 PM
>> To: r-help@r-project.org
&g
Hi,
I am trying use lm() on some data, the code works fine but I would
like to use a more efficient way to do this.
The data looks like this (the data is very sparse with a few 1s, -1s
and the rest 0s):
> head(adj0708)
MARGIN Poss P235 P247 P703 P218 P430 P489 P83 P307 P337
1 64.2857
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