ested in, see
http://rgeneticprogramming.blogspot.com/
Atte Tenkanen
University of Turku
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.htm
TNX Hadley!
Atte
- Original Message -
From: hadley wickham <[EMAIL PROTECTED]>
Date: Sunday, July 15, 2007 11:04 pm
Subject: Re: [R] Break during the recursion?
> On 7/15/07, Atte Tenkanen <[EMAIL PROTECTED]> wrote:
> > Here is now more elegant function for ino
3
[1] 7
Yours faithfully ;-)
Atte
- Original Message -
From: hadley wickham <[EMAIL PROTECTED]>
Date: Sunday, July 15, 2007 6:58 pm
Subject: Re: [R] Break during the recursion?
> On 7/15/07, Duncan Murdoch <[EMAIL PROTECTED]> wrote:
> > On 15/07/2007 11:36 AM, Att
> On 15/07/2007 10:33 AM, Atte Tenkanen wrote:
> >> On 15/07/2007 10:06 AM, Atte Tenkanen wrote:
> >>> Hi,
> >>>
> >>> Is it possible to break using if-condition during the recursive
> >> function?
> >> You can do
> >>
&g
> On 15/07/2007 10:06 AM, Atte Tenkanen wrote:
> > Hi,
> >
> > Is it possible to break using if-condition during the recursive
> function?
> You can do
>
> if (condition) return(value)
>
> >
> > Here is a function which almost works. It is for
LL
> NULL
> [1] 8 4
> [1] 8 4
> [1] 8 4 9 2
> [1] 8 4 9 2
> [1] 8 4 9 2
> [1] 8 4 9 2 10 5
> [1] 8 4 9 2 10 5
> [1] 8 4 9 2 10 5 11 1
> [1] 8 4 9 2 10 5 11 1
> [1] 8 4 9 2 10 5 11 1 3
> Error in if (is.na(v[i]) == FALSE & is.null(u
9 2 10 5
[1] 8 4 9 2 10 5
[1] 8 4 9 2 10 5 11 1
[1] 8 4 9 2 10 5 11 1
[1] 8 4 9 2 10 5 11 1 3
Error in if (is.na(v[i]) == FALSE & is.null(unlist(v[i])) == FALSE) { :
argument is of length zero
Regards,
Atte Tenkanen
University of Turku, Finland
_
Hi,
What's wrong here?:
> v=c(`-`,`+`,1,`^`,`^`,NA,NA,"X",9,"X",2)
> i2=16
> v[i2]
[[1]]
NULL
> is.null(v[i2])
[1] FALSE
Is it a bug or have I misunderstood something?
Atte Tenkanen
University of Turku, Finland
__
Seems to work, if I unlist the argument at first ;-)
Atte
> Hi,
>
> What's wrong here?:
>
> > v=c(`-`,`+`,1,`^`,`^`,NA,NA,"X",9,"X",2)
> > i2=16
> > v[i2]
> [[1]]
> NULL
>
> > is.null(v[i2])
> [1] FALSE
>
> Is
Thanks Sundar!
I wonder that - when evaluating F1 - the right mathematical formula is now also
printed!
> F1
function (x)
x^3 + x^2 - 1
Atte
>
>
> Atte Tenkanen said the following on 7/7/2007 8:41 AM:
> > Dear R users,
> >
> > I wonder if it is possible to fo
;
> S
[1] `-`(`+`(`^`(x,3),`^`(x,2)),1) # Here is the same as a character string.
Now I'd like to create a function using this string, something like this, but
of course, this doesn't work:
S=as.expression(S)
F1<-function(x){S}
Is there some way to do this?
Cheers,
Atte Tenkane
Hi everybody,
I'm still interesting the possibility to use R for genetic programming (see
https://stat.ethz.ch/pipermail/r-help/2007-April/128782.html)
and I'd like to know, how to express for instance this kind of functions
(x^2+3x+1 etc, see the picture) using some kind of tree structures and
Hi,
I couldn't find the 'transfer entropy' implemented in any R packages. I can't
follow the math needed here
(www.macalester.edu/~kaplan/knoxville/PRL00461.pdf). If it is not implemented,
could somebody do it? Or write a "garage level code" for te
---
> > ---
> >
> > Ravi Varadhan, Ph.D.
> >
> > Assistant Professor, The Center on Aging and Health
> >
> > Division of Geriatric Medicine and Gerontology
> >
> > Johns Hopkins University
> >
> > Ph: (410) 502-2619
>
Hi,
Is there a function for raising a matrix to a power? For example if you like to
compute A%*%A%*%A, is there an abbreviation similar to A^3?
Atte Tenkanen
> A=rbind(c(1,1),c(-1,-2))
> A
[,1] [,2]
[1,]11
[2,] -1 -2
> A^3
[,1] [,2]
[1,]11
[2,] -1
Hello R-users,
I'd like to know if there is an autocorrelation function for cases when the
time differences between the observations vary? I want to give both the time
points (x) and values (y) for the function and get as an output an estimation
of autocorrelation.
Atte Tenkanen
Universi
our]) # This works!
>
> # But this doesn't!
>a1=a1+1
>PointsMatrix[a1,]=c(x,y,colour)
> }
> }
>
> #???
> plot(PointsMatrix[,1], PointsMatrix[,2], xlim=Limits, ylim=Limits,
> col=cl[PointsMatrix[,3]], pch=&q
for(y in Step)
{
z1=x+y*1i
n=0
z=z1
while(n Atte Tenkanen wrote:
> > Hi,
> >
> > That is of counter for web page. Do you get some pop-up windows?
> >
> >
> > Atte
>
> Hi Atte,
>
> On Wed, 18 Apr 2007, Atte Tenkanen wrote:
>
> > I often get a following error with R
> >
> > *** caught segfault ***
> > address 0x78807e00, cause 'memory not mapped'
> >
> > Possible actions:
> > 1: abort (with core dump)
> &g
version 2.4.1.
Is there something to d0?
Atte Tenkanen
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, s
Hi Jeff,
Thank you for the nice page. I also have done some "R-videos" combining jpeg's
in video editor (or with mjpegtools) but this kind of command in R would be
useful. Unfortunately I couldn't install NRart-package but got a lot of fun
when playing with your Start Making Art!-page.
I haven
Hi,
That is of counter for web page. Do you get some pop-up windows?
Atte
> kone wrote:
> > Hi everybody,
> >
> > I put some R-code to a web page for drawing fractals. See
> >
> > http://fractalswithr.blogspot.com/
> >
> > If you have some R-code for fractal images, I'm willing to
> includ
>
>
> Duncan Murdoch wrote:
> > On 1/23/2007 6:38 AM, Atte Tenkanen wrote:
> >> Hi,
> >>
> >> Does somebody know if there is some trick to betoken the
> starting points ("on the floor") of the vertical lines in
> scatterplot3d-plots.
&
option be added? Sometimes it is not easy
to distinguish objects behind the others and for instance in this example
picture the case nr. 21 is important.
Atte Tenkanen
University of Turku, Finland
__
R-help@stat.math.ethz.ch mailing list
https://stat.
Oh, it was nearer than I have thought! Thanks.
Atte
>
> > I have tried to develop multidimensional scaling for 3D space
> using PCA
> > without success, yet;-) Is there some application ready in R?
>
> Yes.
>
> stats has cmdscale. MASS has sammon and isoMDS. All three have a 'k'
> argument
...and my system is OSX 10.4.
Atte
>
> > Hi,
> >
> > I have tried to develop multidimensional scaling for 3D space
> using
> > PCA without success, yet;-) Is there some application ready in R?
> >
> > Cheers,
> >
> > Atte
> >
>
> I found xgobi, but when I try to run example I get some com
> Hi,
>
> I have tried to develop multidimensional scaling for 3D space using
> PCA without success, yet;-) Is there some application ready in R?
>
> Cheers,
>
> Atte
>
I found xgobi, but when I try to run example I get some command not found
-errors.
Atte
> data(morsecodes) ## from the
Hi,
I have tried to develop multidimensional scaling for 3D space using PCA without
success, yet;-) Is there some application ready in R?
Cheers,
Atte
__
R-help@stat.math.ethz.ch mailing list
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PLEASE do rea
with Finale or other music notation
program.
Atte
> Hi, Atte
>
> > De : [EMAIL PROTECTED]
> > [mailto:[EMAIL PROTECTED] De la part de Atte
> Tenkanen> Envoyé : mercredi 3 janvier 2007 09:17
> > Hi,
> >
> > I'd like to know if it is possible
ine(h=i)
}
it is enough.
Best wishes,
Atte Tenkanen
University of Turku, Finland
___
P.S.
By the way, right now the demo(Hershey) seems not to work in OSX version R
2.4.1. ...
I get a message
> i <- i + 1
Error in deparse(
123
> > [3,]31231
> > [4,]12312
> >
> > in which rows 1 and 4 are similar, I want to find that vector c
> > (1,2,3,1,2).
> >
> > Atte Tenkanen
> > University of Turku, Finland
> >
> > ___
astle.edu.au/R/help/05/04/3709.html
>
> On 10/6/06, Atte Tenkanen <[EMAIL PROTECTED]> wrote:
> > Hi,
> > Can somebody tell me, which is the fastest way to make
> comparisons between all rows in a matrix (here A) and put the
> results to the new symmetric matrix? I
uct here:
>
> http://tolstoy.newcastle.edu.au/R/help/05/04/3709.html
>
> On 10/6/06, Atte Tenkanen <[EMAIL PROTECTED]> wrote:
> > Hi,
> > Can somebody tell me, which is the fastest way to make
> comparisons between all rows in a matrix (here A) and put the
> results to the new s
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Atte Tenkanen
> Sent: Friday, October 06, 2006 1:54 PM
> To: r-help@stat.math.ethz.ch
> Subject: [R] Row comparisons to a new matrix?
>
> Hi,
> Can somebody tell me, which is the fastest way to make comparison
),c(-1,2),c(5,6))
M=matrix(nrow=length(A[,1]),ncol=length(A[,1]))
for(i in 1:length(A[,1]))
{
for(j in 1:length(A[,1]))
{
M[i,j]=cosine(A[i,],A[j,])
}
}
Atte Tenkanen
University of Turku, Finland
__
R-help
Hi,
Is there some package or function for 2- or 3 -dimensional geometric pattern
matching with R? It should be measure similarities between patterns in a fuzzy
way, so not exact similarities are demanded.
Atte Tenkanen
University of Turku, Finland
eturned in the case
> that VECTOR has zero length and in the case that VECTOR
> has fewer than 5 unique elements.
>
>
> On 8/26/06, Atte Tenkanen <[EMAIL PROTECTED]> wrote:
> > Again my example was't very clear: there were not enough same
> numbers in t
6 8
So, there are no duplicates in rows.
VECTOR is always scanned forward as long as the number of items (here 5)
becomes full.
Atte
> Try:
>
> embed(VECTOR, 5)[,5:1]
>
> On 8/25/06, Atte Tenkanen <[EMAIL PROTECTED]> wrote:
> > Hi,
> >
> > Here is a
n advance!
Atte Tenkanen
University of Turku
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, rep
RESSES=c();
>
> You do not need the semicolons, and they just confuse readers.
>
> > for(i in 1:(length(VECTOR)-4)){
> > ADDRESSES[i]=paste(VECTOR[i:(i+4)],collapse="")
> > }
> >
> > > ADDRESSES
> > [1] "14265" "42650
Thanks for both, tapply seems to be a fast and delicate solution. I had appr.
150 000 rows and it took few seconds to get the result. Till now I have been
too tied by for-loops. I will make acquaintance with "An Introduction to R".
Atte
- Original Message -
From: "Richard M. Heiberger"
RIX[,2][MATRIX[,1]==i]))
RESULTMATRIX=rbind(RESULTMATRIX,RESULTVECTOR)
}
row.names(RESULTMATRIX)<-INDEXES;
RESULTMATRIX=RESULTMATRIX[,2];
> RESULTMATRIX
1 2 5
8 1 1
Atte Tenkanen
University of Turku, Finland
__
R-help@stat.math.ethz.ch mailing list
https://st
> will get you what you want.
>
> Patrick Burns
> [EMAIL PROTECTED]
> +44 (0)20 8525 0696
> http://www.burns-stat.com
> (home of S Poetry and "A Guide for the Unwilling S User")
>
> Atte Tenkanen wrote:
>
> >Is there some (much) more efficient way to do
6 6
> NEWVECTOR
[1] 3 2 4 5 3 5 1 6
___
Atte Tenkanen
University of Turku, Finland
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/p
TNX Brian!
Atte
- Original Message -
From: Prof Brian Ripley <[EMAIL PROTECTED]>
Date: Monday, June 19, 2006 10:33 am
Subject: Re: [R] Border line width?
> On Mon, 19 Jun 2006, Atte Tenkanen wrote:
>
> > Is there some way to change the line widths of plot borders?
&
Is there some way to change the line widths of plot borders?
I couldn't find any parameters for that purpose.
Atte Tenkanen
University of Turku, Finland
__
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PLEA
is=2);
> mtext("sd of consecutive pc intervals", side=2, line=0,
> padj=-1.8,at=1.2, cex=3)
> lines(Compo_SD_succ_int_array_vector,col=1,lty=1,lwd=2);
> text(2,0.93,labels="*",cex=3) # "an asterisk..."
> dev.off();
>
> What do I do next?
>
>
uot;,ylab="", cex.lab=3, cex.axis=2);
mtext("sd of consecutive pc intervals", side=2, line=0,
padj=-1.8,at=1.2, cex=3)
lines(Compo_SD_succ_int_array_vector,col=1,lty=1,lwd=2);
text(2,0.93,labels="*",cex=3) # "an asterisk..."
dev.off();
What do I do nex
m=as.vector(m[,rev(order(b))[1]])
Pf=c() # the winner set is transposed to prime form
Pf[1]=0
for(i in 1:(length(succ_i_arr)-1))
{
Pf[1+i]=Pf[i]+m[i]
}
}
return(Pf)
Thank you for answering, both Roger and Henrik
There are only 5 cases which need divisions, so I inserted \n to them and
now everything works.
Atte
> On 3/18/06, Atte Tenkanen <[EMAIL PROTECTED]> wrote:
>> Is there any possibility to divide too long text in a plot to two or
&
)]) # according to Larry
Solomon's table http://solomonsmusic.net/pcsets.htm
Chordnames is a long vector with long character strings.
Atte Tenkanen
University of Turku
Finland
__
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Question 1) I want to read many csv-tables and run the same commands for
all of them. Is there some simpler solution than this below to solve this
problem?
for (g in 1:6)
{
if (g==1){k="kt1_0057"}
if (g==2){k="kt1_0101"}
if (g==3){k="kt1_0613"}
if (g==4){k="staten"}
if (g==5){k="tenpenny"}
if (g
> If I calculate a transition probability matrix, first order markov 12x12
> or second order 144x144 from musical pitch classes (0-11), is it possible
> to generate pitch class strings similar as those original strings using
> those probability matrix with R? If, how?
>
> At
If I calculate a transition probability matrix, first order markov 12x12
or second order 144x144 from musical pitch classes (0-11), is it possible
to generate pitch class strings similar as those original strings using
those probability matrix with R? If, how?
Atte Tenkanen, Turku, Finland
- Phil Spector
>Statistical Computing Facility
>Department of Statistics
>UC Berkeley
>[EMAIL PROTEC
Hi,
I have a column (V4) in a midi event list which includes tone pitch names,
i.e. "A4, E4, C#4, A3...":
> compo[1:10,]
V1 V2 V3 V4 V5 V6 V7
1 1 1 0 A4 96 2 0
2 1 1 0 E4 96 2 0
3 1 1 0 C#4 96 2 0
4 1 1 0 A3 96 2 0
5 1 3 0 B4 96 1 0
6 1 3 0 E4 96
Is it possible to input data from sound card of the computer to R? What
do I need to know about my computer (it's linux pc)? Can I get some real
time graphical information this way, spektrum for example?
Atte
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