Re: [...@ntau-net] OOT: Matematika 22 (Jawaban)

2010-05-29 Terurut Topik hanifah daman
banyak bil ganjil antaro 1 sampai 201 ... lai agak ragu juo katiko itu .. 100 atau 101 ?? Salam Hanifah --- On Sun, 5/30/10, zul_...@yahoo.com wrote: From: zul_...@yahoo.com Subject: Re: [...@ntau-net] OOT: Matematika 22 (Jawaban) To: rantaunet@googlegroups.com Date: Sunday, May 30, 2010

Re: [...@ntau-net] OOT: Matematika 22 (Jawaban)

2010-05-29 Terurut Topik zul_tan
Bu Ifah, Apo artinyo tando paga ko: =1/1 +(1#2+2+1^2)/3+(1#2+4+2^2)/5 Ambo alun paham. Baa dek 101 karano X td 101 suku. Y td dari 100 suku. Sado suku Y bisa dipasangkan dengan suku X yg masiang2 banilai 1. Sisa X nan ndak bapasangan adolah suku partamo nan banilai 1 juo. Mako dek nantu

Re: [...@ntau-net] OOT: Matematika 22 (Jawaban)

2010-05-29 Terurut Topik hanifah daman
salah ??? Wass Hanifah --- On Sat, 5/29/10, zul_...@yahoo.com wrote: From: zul_...@yahoo.com Subject: Re: [...@ntau-net] OOT: Matematika 22 (Jawaban) To: rantaunet@googlegroups.com Date: Saturday, May 29, 2010, 8:34 PM Buk Ifah jo dunsanak sadonyo, Nampaknyo ndak jawaban tambahan nan masuak

Re: [...@ntau-net] OOT: Matematika 22 (Jawaban)

2010-05-29 Terurut Topik zul_tan
Buk Ifah jo dunsanak sadonyo, Nampaknyo ndak jawaban tambahan nan masuak. Ko jawaban ambo. X = 1^2/1 + 2^2/3 + 3^2/5 + ... + 101^2/201 Y = 1^2/3 + 2^2/5 + 3^2/7 + ... + 100^2/201 X - Y = 1 + (2^ - 1^2)/3 + (3^2 - 2^2)/5 + ... + (101^2 - 100^2)/201 = X - Y = 1 + 1 + 1 + ... + 1 = 101 (101 suk