q.all()._asdict()
It does not work. It is a kind of a mental shortcut (sorry for that!). It
is only possible in (like you said):
for r in q.all():
r._as_dict()
Thank you for your reply! I had hope that I don't have to do any casting or
explicity query enumerate.
W dniu czwartek, 20 paź
q.all() returns me a result in format:
[('one', {'t2c2': 'qwe',
't2c1': '11',
't2c3': '1'}),
('two', {'t2c2': 'rty',
't2c1': '22',
't2c3': '2'}),
..]
The result of
q.all()._asdict()
is
[{
't1c2': 'one',
'table2': {
't2c2': 'qwe',
't2c1': '11',
't2c3': '1'
}
},
{
't1c2'
Hi!
There is any option to select JOIN result as dict?
For example I have:
*table1*
t1c1| t1c2
-+
1 | one
2 | two
3 | three
*table2*
t2c1 | t2c2 | t2c3
-+---+---
11 | qwe | 1
22 | rty | 2
33 | zxcvb| 1
where
t2c3 from *table2 *is a foreign key
