That's perfect. Thanks!
On Thursday, 10 April 2014 11:38:24 UTC+1, Simon King wrote:
>
> You can also use sqlalchemy.literal, which returns an object that you
> can treat like a column:
>
> sqlalchemy.literal('string').like('whatever')
>
> You may also be interested in the 'startswith' shortc
You can also use sqlalchemy.literal, which returns an object that you
can treat like a column:
sqlalchemy.literal('string').like('whatever')
You may also be interested in the 'startswith' shortcut, which calls
.like under the hood
sqlalchemy.literal('string').startswith(yourcolumn)
Simon
O
I'm sorry, forget my last response, I see what you mean now.
Thanks a lot!
On Thursday, 10 April 2014 11:31:23 UTC+1, Gunnlaugur Briem wrote:
>
> Hi,
>
> See ColumnElement docs:
>
>
> http://docs.sqlalchemy.org/en/rel_0_9/core/sqlelement.html#sqlalchemy.sql.expression.ColumnElement
>
> ... for yo
Hi, thanks but I'm not talking about calling like on a column - I need to
call like on a string literal. I tried doing text('string').like() but that
doesn't work either.
On Thursday, 10 April 2014 11:31:23 UTC+1, Gunnlaugur Briem wrote:
>
> Hi,
>
> See ColumnElement docs:
>
>
> http://docs.sq
Hi,
See ColumnElement docs:
http://docs.sqlalchemy.org/en/rel_0_9/core/sqlelement.html#sqlalchemy.sql.expression.ColumnElement
... for your specific example you can call .like(...) on column clauses:
>>> print Column('foo', Text).like('bar%baz')
foo LIKE :foo_1
More generally, if you wanted so
I can't seem to find a way to do this without passing raw SQL to .filter()
I could just do:
.filter(column == func.substring('string', 1, func.char_length(column)))
but is it possible to do it with LIKE?
I.e. I need to return all rows that match the beginning of a string, so for
'string' I cou
