Hi all,
I just stumbled on the following behavior:
>>> type(eye(2))
>>> type(sympify(eye(2)))
Is this supposed to work that way or is it a (minor) Bug?
Best regards,
Carsten
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How about adding a check for a _sympify_ attribute in the sympify
routine. It will permit 3rd party classes usage in sympy. At the
moment if someone want something nontrivial, he needs to add it to
sympify. But this is not pythonic. In python just having the same
interface should be enough.
It wil
Note that internally, the expression actually is expressed this way:
In [54]: print S("x1^-1*x2^-1").args
(1/x1, 1/x2)
In [55]: srepr(S("x1^-1*x2^-1"))
Out[55]: Mul(Pow(Symbol('x1'), Integer(-1)), Pow(Symbol('x2'), Integer(-1)))
It's only the printer that represents it as 1/(x1*x2), which is don
When symbols are non-commutative they will always appear with negative exponent:
>>> var('A B', commutative=False)
>>> 1/A/B
A**(-1)*B**(-1)
Beyond this, I'm not sure of an option other than symbol-trickery (or
writing your won printer):
>>> a=symbols('(-1)')
>>> y**a
y**(-1)
.c
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Hi,
sympifying the expressions "x1^-1*x2^-1" gives "1/(x1*x2)" which is of
course correct, but I was wondering whether one can tell sympify to
write it as "x1**(-1)*x2**(-1). I am using the expression in a context
where the latter form would be more appropriate.
Best,
Akin
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Thanks for reporting this. Can you open an issue in our issue tracker
(http://code.google.com/p/sympy/issues/list) for it? I bisected the
regression to the commit
commit d00c8b214520604fb65bde426cbaf4f4b30dbba0
Author: Mateusz Paprocki
Date: Tue Jun 7 01:55:11 2011 -0700
Use new parse_ex
Hi,
I was using SymPy 0.6.7 (on Ubuntu, etc) and now I have installed
version 0.7.1.
Until SymPy v0.6.7, the following was working well :
sympify(u'Limit(sin(x),x,0,dir=\"-\")')
But with SymPy 0.7.0 or 0.7.1, it gives
"SympifyError: SympifyError: 'could not parse u\'Limit(sin(x),x,
It could be useful to be able to pass assumptions to sympify which
would be applied to any symbols created. Open an issue for it if you
want it.
Note that this could have unintendent consequences. If you pass a
locals() dict to sympify, e.g., sympify(somestr, locals=locals()),
then any symbols i
Hi,
On 12 August 2011 04:51, Tomo Lazovich wrote:
> Hi sympy-folk,
>
> If I want to sympify some strings to get symbols from them, but I'd also
> like to have assumptions along with those symbols (in this case, that they
> are real). Is it possible to pass along assumptions to sympify like you
>
Hi sympy-folk,
If I want to sympify some strings to get symbols from them, but I'd also
like to have assumptions along with those symbols (in this case, that they
are real). Is it possible to pass along assumptions to sympify like you
could to symbols?
Thanks!
Tomo
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There is already some function in sympy/parsing/mathematica.py that is supposed
to handle the spaces. As far as I remember, though, it isn't integrated in
sympify, (and also it could use some improvement).
+1 for better parsers for other computer algebra systems. A good Maple parser
would b
I copied an alt field of the expression displayed at wolfram alpha. It
contained escaped slashes so S() failed. Perhaps S could filter those
out:
h[5] >>> S('1\/2')
Traceback (most recent call last):
File "", line 1, in
File "sympy\core\sympify.py", line 214, in sympify
return ast_parser.
Hi,
I think sympify should work on tuples, lists and Matrices and just
return tuples, lists and Matrices, with elements converted to sympy
expressions. See:
http://code.google.com/p/sympy/issues/detail?id=883
What do you think?
Ondrej
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You
Hi,
In [16]: sympy.__version__
Out[16]: '0.5.15-hg'
In [19]: K = sympy.Matrix(nm.array(1, ndmin = 2))
In [20]: sympy.sympify(K)
...
NotImplementedError: matrix support
Is there a reason for this? Why a Matrix instance is not just passed
along, since it is already a sympy object?
Then, what is
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