Don't put the question marks in the expression. What you want is just
[:space:][:space:][:space:][:space:][:space:][:space:][:space:][:space:].
A question mark means "match this character 0 times or 1 time only".
What is happening for you is that for every space character in your
document, one
On Wednesday, January 26, 2005, 3:00:30 PM, Mark Kirchner wrote:
>> [:space:]?[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?
>
> [:space:]? means: One OR zero spaces (because of the "?"). So the
> complete expression will match anything from 0 to 8 spaces.
Ugh, copy & paste error: Th
On Wednesday, January 26, 2005, 2:38:53 PM, David Teague wrote:
> I want to replace the leading 8 spaces with 4. If I use eight of the
> regular expression [:space:]?, as
>
> [:space:]?[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?
[:space:]? means: One OR zero spaces (because of the
Hi David,
I want to replace the leading 8 spaces with 4. If I use eight of the
regular expression [:space:]?, as
[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?
In regular expressions, normally the ? cardinality means 0 or 1
occurrence, so that expression would match any num
I have some C++ code with annoyingly many spaces of
indentation.
I want to replace the leading 8 spaces with 4. If I use eight of the
regular expression [:space:]?, as
[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?
and replace with say four of them, the find button in
