its an 0.5 paradigm. in 0.4 you do the more manual practice of selecting from joins you create with the expression language:
query(X).select_from( table1.outerjoin(table2, and_(table1.c.foo==table2.c.bar, table2.c.x=='y')) ) On Jan 8, 2009, at 3:41 AM, ml wrote: > > this is what I'm looking for but it doesn't work in 0.4.8. 0.5 is > fine? > > Michael Bayer napsal(a): >> do you perhaps mean to say, query(Sortment).outerjoin((Translation, >> and_(Sortiment.id==Translation.sortiment_id, >> Translation.langauge=='en'))) ? >> >> >> On Jan 7, 2009, at 4:04 PM, ml wrote: >> >>> That is a solution but it is not very efficient. It involves a >>> sequential scanning of the result of the join inside the database. >>> >>> >>> Michael Bayer napsal(a): >>>> On Jan 7, 2009, at 11:49 AM, ml wrote: >>>> >>>>> Hi! >>>>> >>>>> I have 2 tables: >>>>> >>>>> sortiment(id, ...) <---- translations(id, id_sortiment, language, >>>>> text) >>>>> >>>>> The query >>>>> >>>>> query >>>>> (Sortiment >>>>> ).outerjoin >>>>> (Sortiment.translations).filter(Translation.language="en") >>>>> >>>>> will never return sortiment item with missing "en" translation >>>>> because >>>>> the filter (useless outerjoin). I need the >>>>> Translation.language="en" >>>>> embed into the outerjoin but the language must be variable. This >>>>> is a >>>>> general problem of creating variable joins on session queries. >>>>> Is there any simple way? >>>>> >>>> you'd filter on or_(Translation.language=="en", >>>> Translation.language==None) >>>> >> >> >>> >> > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
