I am have a real problem with HTML FORMS and I cannot see where I am going
wrong. I make a MySQL call and bring back the required data and populate a
HTML page (all working OK) At the bottom of the page I open an HTML FORM the
idea being the user may enter what they want and when they hit "SUBMIT" the
info is POSTED to an UPDATE_DB subroutine. The HTML FORMS just does not work
and I cannot see why not.
<?PHP session_start(); ob_start(); $access = $_SESSION['access']; PHP?>
<HTML>
<?PHP include("count.js"); ?>
</SCRIPT>
HTML & PHP CODING
HTML & PHP CODING
HTML & PHP CODING
HTML & PHP CODING
EVERYTHING WORKING AS EXPECTED AND REQUIRED UPTO THIS POINT
At this point I want the users to enter data and click "SUBMIT" which all
happens as expected. AT this point here is the FORMS coding
<FORM ACTION="tp_update_tr.php" ID="primary" METHOD="post">
<TABLE BOARDER="0">
<TBODY> <TR bgcolor="#cccccc">
<TD width="180">DESCRIPTION</TD>
<TD width="50"> </TD>
<TD width="740"><CENTER>MAXIMUM FIELD LENGTHS
APPLY</CENTER></TD></TR>
<TR><TD>ACTUAL OUTPUT:</TD>
<TD><INPUT disabled="count" name="actualdata_ct" size="2"
value="128"></TD>
<TD><TEXTAREA name="actualdata" cols="106"
rows="2"></TEXTAREA></TD></TR>
<TR><TD>ACTUAL RESULT:</TD>
<TD><INPUT disabled="count" name="actualresult_ct" size="2"
value="255"></TD>
<TD><TEXTAREA name="actualresult" cols="106"
rows="3"></TEXTAREA></TD></TR>
<TR><TD>TEST NOTE :</TD>
<TD><INPUT disabled="count" name="testnote_ct" size="2"
value="255"></TD>
<TD><TEXTAREA name="testnote" cols="106"
rows="3"></TEXTAREA></TD></TR>
</TBODY>
</TABLE>
<?PHP
echo("<tr><td align='right' colspan=2>$prv");
if ($cps == $nr0)
{ echo " | <font color='CCCCCC'> Next - 135</font>"; }
else
{ if ($nr0 > 1)
{ echo(" | <a href='help_tp_update.php?cps=$cps&lps=$lps'><BUTTON>Next
138</BUTTON></a>"); }
}
echo(" - <B>(Record $x of $y)</B>");
$_SESSION['testno'] = $h;
$actualdata = $_POST['actualdata'];
$actualresult = $_POST['actualresult'];
$testnote = $_POST['testnote'];
$_SESSION['actualdata'] = $actualdata;
$_SESSION['actualresult'] = $actualresult;
$_SESSION['testnote'] = $testnote;
if ($v != null)
{ echo("<BR><B>PREVIOUS TESTNOTE: </B>" . $v . "<BR>");}
?>
</TABLE>
<TABLE BOARDER="0">
<TBODY> <TR><TD width="180"> </TD>
<TD width="50" > </TD>
<TD width="760"> </TD></TR>
<TR><TD><a href="tp_mainmenu.php"
><BUTTON>EXIT</BUTTON></a>
<a href="#" onclick="window.print()"><?PHP echo(' |
'); PHP?><BUTTON>Print</BUTTON></a></TD>
<TD><input value="UPDATE - 163"
type="submit"></TD></TR>
</TBODY>
</BODY>
</TABLE>
</FORM>
</HTML>
----- Original Message -----
From: "Michael Southwell" <[EMAIL PROTECTED]>
To: "NYPHP Talk" <[email protected]>
Sent: Sunday, November 18, 2007 9:02 PM
Subject: Re: [nyphp-talk] Passing info entered into HTML FORMS into
SESSIONvariables.
PaulCheung wrote:
$t = $row['data']; $u = $row['result']; $v = $row['note'];
How are you populating the $row array? I would have expected this to be:
$t = $_POST['data'];
Doing it this way you should have no problem. And by the way, you don't
need the $t etc variables unless you are using them elsewhere. That would
make it this:
$_SESSION['data'] = $_POST['data'];
--
=================
Michael Southwell
Vice President, Education
NYPHP TRAINING: http://nyphp.com/Training/Indepth
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