verma wrote: > Thanks Ali for your response. > Ali wrote: >> I may be missing something, but if foo() is >> your entry point, what are you returning to? > Yes foo() is my entry point. > >> I think exit(0) is your only way out. > Ok but why exit(0) is required. Why I can not use return 0. >
Because the code that makes that work is the code you pushed out of the way by specifying your own entry point. This was the point of my original question: What would foo() be returning to? In a normal executable, the entry point is _start. _start sets things up, and then calls your main() function (note that main() is not your entry point). When main() returns, it is returning to _start(). That code calls exit() for you. Changing your entry point to foo() pushes all of that code aside. Sorry, but I don't know what you have to supply to replace it. You could dig into the code for ld.so.1 to figure out why your code core dumps on exit from foo(). - Ali
