How about XmlParser?
def node = new XmlParser().parse(new File('path-to-xml-file')
println node.parent.child1.first().attributes()
On Wed, Oct 14, 2015 at 10:49 AM, Balachandran Sivakumar <
benignb...@gmail.com> wrote:
> Hi,
>
> On Wed, Oct 14, 2015 at 8:46 PM, Schalk Cronjé <ysb...@gmail.com> wrote:
>
>>
>>> Use
>>
>> root.parent.child.@id
>>
>> or
>>
>> root.parent.child.'@id'
>>
>> to access the attribute you want.
>>
>>
>>
> Thanks, but I want all the attributes on the node returned as a
> ma, not just a specific attribute. Thanks.
>
>
>> --
>> Schalk W. Cronjé
>> Twitter / Ello / Toeter : @ysb33r
>>
>>
>
>
> --
> Thank you
> Balachandran Sivakumar
>
>
