Hi, The HTTP 407 code means that you need some authorization for a proxy: http://www.checkupdown.com/status/E407.html. Does it help? Thanks. Best regards,
Jérôme LELEU Founder of CAS in the cloud: www.casinthecloud.com | Twitter: @leleuj Chairman of CAS: www.jasig.org/cas | Creator of pac4j: www.pac4j.org 2014-06-10 15:37 GMT+02:00 MrCrowley <mrcrowley...@yahoo.it>: > Hi there, > I have CAS 3.4.3 working in production envirovment within a cluster and > apache as webserver in front of Websphere 6.1. > Now for some reasons I have to put two application on a development > environment which for a lot of reasons is quite different. > Basically I have the CAS war and myApplication.The two are deployed on > same WAS 6.1 singlenode. > Keep in mind I use spring security in the app and I want to go in plain > HTTP for now. > So when I request a protected URL in myApplication I'm correctly > redirected to CAS webapp, I go through the login process and I'm granted a > ticket, but when I close the trip with the request back to myAPP with the > ticket i get this exception: > > 2014-06-10 15:24:04,429 INFO > [org.jasig.cas.authentication.AuthenticationManagerImpl] - > <AuthenticationHandler: > org.jasig.cas.adaptors.jdbc.QueryDatabaseAuthenticationHandler successfully > authenticated the user > which provided the following credentials: [username: usrname]> > [10/06/14 15:24:04:444 CEST] 00000501 SystemOut O 2014-06-10 > 15:24:04,429 INFO [org.jasig.cas.CentralAuthenticationServiceImpl] - > <Granted service ticket [ST-2-LY6mdKFA4RODJUo0WLH2-cas] for service > [http://theserver:9080/myApplication/j_spring_cas_security_check] for > user [usrname]> > [10/06/14 15:24:04:476 CEST] 00000501 Cas20ServiceT E > org.jasig.cas.client.validation.AbstractCasProtocolUrlBasedTicketValidator > retrieveResponseFromServer java.io.IOException: Server returned HTTP > response code: 407 for URL: > > http://theserver:9080/CAS/serviceValidate?service=http%3A%2F%2Ftheserver%3A9080%myApplication%2Fj_spring_cas_security_check&ticket=ST-2-LY6mdKFA4RODJUo0WLH2-cas&; > java.io.IOException: Server returned HTTP > response code: 407 for > URL: > http://theserver:9080/CAS/serviceValidate?service=http%3A%2F%2Ftheserver%3A9080%2FmyApplication%2Fj_spring_cas_security_check&ticket=ST-2-LY6mdKFA4RODJUo0WLH2-cas&; > at > sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1179) > at > org.jasig.cas.client.validation.AbstractCasProtocolUrlBasedTicketValidator.retrieveResponseFromServer(AbstractCasProtocolUrlBasedTicketValidator.java:35) > at > org.jasig.cas.client.validation.AbstractUrlBasedTicketValidator.validate(AbstractUrlBasedTicketValidator.java:178) > at > org.springframework.security.cas.authentication.CasAuthenticationProvider.authenticateNow(CasAuthenticationProvider.java:131) > at > org.springframework.security.cas.authentication.CasAuthenticationProvider.authenticate(CasAuthenticationProvider.java:117) > at > org.springframework.security.authentication.ProviderManager.doAuthentication(ProviderManager.java:130) > at > org.springframework.security.authentication.AbstractAuthenticationManager.authenticate(AbstractAuthenticationManager.java:48) > at > org.springframework.security.cas.web.CasAuthenticationFilter.attemptAuthentication(CasAuthenticationFilter.java:111) > at > org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.doFilter(Abs > > > > Any IDEAS?I'm going crazy! > Thanks a lot > > -- > You are currently subscribed to cas-user@lists.jasig.org as: lel...@gmail.com > To unsubscribe, change settings or access archives, see > http://www.ja-sig.org/wiki/display/JSG/cas-user > > -- You are currently subscribed to cas-user@lists.jasig.org as: arch...@mail-archive.com To unsubscribe, change settings or access archives, see http://www.ja-sig.org/wiki/display/JSG/cas-user
