$PHP_SELF returns the filename with the full path. from there, you can use
split to split the string wherever a / occurs, then call count, to get the
total number of values in the array, decrememnt the count by 1 (Arrays begin
at 0) then, set a variable to store just the filename, like so:
$fullpath = split('/',$PHP_SELF);
$c = count($fullpath);
$c--;
$filename = $fullpath[$c];
There may be a better way to do it, but this works for me, and it's only 4
lines. :)
JB
----- Original Message -----
From: "Reuben D Budiardja" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, July 17, 2001 7:48 AM
Subject: [PHP] Get filename in php command line
Hello,
How do I get the filename or script name if I run it in php comamnd line?
For
example, if I run this
bash$ php test.php
I want to get something inside test.php that tells me the filename is
test.php, but *without* the actual path.
Thanks
Reuben D. Budiardja
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
