Re: [PHP] changing unix password in php?

2002-01-22 Thread Mehmet Kamil ERISEN

I have not done it, but i can be done by using a form and
calling the shell script that does the job.
Of course shell script has to be executable by everybody.
It may be a security concern.
or, you can add the shell script to your cron tab.
and keep the password change requests in a file and change
the passwords every 10 minutes or so. 

--- Charlie Grosvenor [EMAIL PROTECTED]
wrote:
 Hi
 I would like to create a page in php where a user can
 change their unix password, does anybody know how i can
 do this?
 
 Thankyou
 
 Charlie
 


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[PHP] Edit program

2002-01-20 Thread Mehmet Kamil ERISEN


Dear List member,

Plesae forgive me for asking and OT question.  Can you please recommend an edit 
program, (Freely downloadable).

Thanks,

Erisen


Mehmet Erisen
http://www.erisen.com


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Re: [PHP] Passing PHP Variables

2002-01-17 Thread Mehmet Kamil ERISEN

If you are using sessions, use it as a session variable.

--- John (News) [EMAIL PROTECTED] wrote:
 I need to pass a variable e.g. $var1 from one PHP page to
 another. The
 only conditions are that the variable cannot be shown in
 the source
 code on the end users machine nor can it be passed
 visibly within the
 url. Does anyone have any suggestions on how I can
 accomplish this?
 
 Hippie. 
 
 
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Re: [PHP] PHP as a cron job

2002-01-16 Thread Mehmet Kamil ERISEN

Hi,
I have to sweat my way through
/usr/bin/php if that does not work try /usr/local/bin/php
or ask the Unix Sysadmin.

one problem I still have to overcome is that everything
works,( I mean DB Connection etc.) but I can not use mail()
function. 

Any body have any ideas why I can't use mail()?
--- mike cullerton [EMAIL PROTECTED] wrote:
  Unable to open /home/admin/webmin-0.85/ in Unknown on
 line 0
 
 this is possibly a path or env issue. have you tried
 using absolute
 filenames?
 
 mike
 
 on 1/16/02 10:07 AM, Tiago Luchini at
 [EMAIL PROTECTED] wrote:
 
  I am trying to run directly via PHP.
  
  I have tried setting 755 to the script and adding
 #!/usr/bin/php -q to it
  and also tried to change my cron line to run
 /usr/bin/php sending the script
  as a parameter. Both options run normally when logged
 on a TTY.
  
  Tiago
  
  
  - Original Message -
  From: Dennis Moore [EMAIL PROTECTED]
  To: Tiago Luchini [EMAIL PROTECTED];
 [EMAIL PROTECTED]
  Sent: Wednesday, January 16, 2002 12:18 PM
  Subject: Re: [PHP] PHP as a cron job
  
  
  Please provide more information on how you have set up
 PHP to run your
  cron
  jobs.  Are you trying to execute via LYNX or directly
 via a PHP script?
  
  /dkm
  
  
  - Original Message -
  From: Tiago Luchini [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Sent: Wednesday, January 16, 2002 8:20 AM
  Subject: [PHP] PHP as a cron job
  
  
  I have been trying to use some PHP scripts as a Linux
 cron job.
  
  It tries to run but replies that:
  Unable to open /home/admin/webmin-0.85/ in Unknown on
 line 0
  
  I have no idea why PHP parser is making this
 confusion.
  Could anyone bring some light to this mistery please?
  
  Atenciosamente,
  
  Tiago Luchini
  Diretor Técnico-Comercial
  Galluch Soluções Internet
  Tel.: 0xx11 6912-3255
  Cel.: 0xx11 7839-7740
  
  
 
 
  -- mike cullerton   michaelc at cullerton dot com
 
 
 
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RE: [PHP] sql question

2002-01-15 Thread Mehmet Kamil ERISEN


 Hi do you care about case sensitivity?
  Nathan Cassano [EMAIL PROTECTED] wrote: 
select * from tbl_lit where lit_source like 'c%';

Check out http://www.sqlcourse.com/

-Original Message-
From: Wolf-Dietrich von Loeffelholz [mailto:[EMAIL PROTECTED]] 
Sent: Tuesday, January 15, 2002 12:09 PM
To: [EMAIL PROTECTED]
Subject: [PHP] sql question


i want that a select query display me all words beginning with an a ..
like select * from tbl_lit where lit_source = 'c*' .. 

thnx bSue


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Re: [PHP] Mysql

2002-01-14 Thread Mehmet Kamil ERISEN

Hi,
Sorry if I am being a rude, but you need to read the
document on how to create a table:
www.mysql.com
and 
www.php.net (assuming that you will use php)

thx.

--- -=LukA=- [EMAIL PROTECTED] wrote:
 Hello php-general,
 
   Hi everybody
   Please help me.
   If i want to create a table in some database what
 should I do.
   The database is on server.
 
 -- 
 Best regards,
  -=LukA=-  mailto:[EMAIL PROTECTED]
 
 
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Re: [PHP] help with include

2002-01-12 Thread Mehmet Kamil ERISEN

I have installed phpBB several times. Your problem should
not be the password protected directory.
The install.php script tries to wright into the config
file.
so, you have to chmod your file and give r/w access to
everybody.
once insallation is completed, then change it the was it
was originally.
if you give me the url, i can better understand your
problem.
erisen
--- Brian's News [EMAIL PROTECTED] wrote:
 Hi, I need some help with the include function.
 I have a phpBB script and want to put the config.inc.php
 file in a password
 protected directory, Easy peasy you might say, and I know
 it is, but the
 problem comes because the password protected directory
 isn't on the site the
 script is on, mainly because the host says I've got to
 upgrade my account to
 use password protected dir's.
 I've got one site with a password protected dir available
 and would like to
 put it on there.
 
 Any idea's how to do it would be appreciated.
 
 Many thanks
 
 Brian
 
 
 
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[PHP] ENUM COL to php

2002-01-11 Thread Mehmet Kamil ERISEN

Hi,
If I have en ENUM column in a mysql table, can I leverage
this through PHP to restrict user entry with a list?
Other option that I have is to create a lookup table, or
use an array.

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[PHP] two mysql issues :)

2002-01-11 Thread Mehmet Kamil ERISEN


Hi All,

I am in sql mode today. Two issues that bother me:

1- I had a script

select user_id, username from users having user_id = max(user_id)

my max user_id = 150 or something, but script kept bringing 122 

I fixed the issue by using a select max(user_id) and select username from users where 
user_id = $v_user_id

 

2- select max(commission) where territory=1 and salesperson=2232;

this query should return 0 zero b/c it's a sum. but it returns null.  

any comments how I can work around this!!! 

thanks.


Mehmet Erisen
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[PHP] cron job problem.

2002-01-10 Thread Mehmet Kamil ERISEN

Hello All,
I have a php script that i tested first through my browser.
If has a simple mail() command.
It workd fine and I received the email.
not I tried to run it as a cron job by adding 
#!/usr/local/bin/php -q
My webmaster account receives the confirmation that cron
job has run, but I do not receive the emails that the
program is 
supposed to send.
This is the code:
Thanks for the help...

#!/usr/local/bin/php -q
?php
$subject=Cron Job has run;
$body=test.php is running now;
$sendtome = [EMAIL PROTECTED];
mail($sendtome, $subject, $body);
?
--- mike cullerton [EMAIL PROTECTED] wrote:
 #!/usr/local/bin/php -q
 
 on 1/10/02 12:16 PM, Mark at [EMAIL PROTECTED]
 wrote:
 
  I've got this problem that won't go away.
  
  The headers are showing up at the top of the page when
 I run php in
  cgi mode. any ideas?
 
 
  -- mike cullerton 
 
 
 
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Re: SV: [PHP] cron job problem.

2002-01-10 Thread Mehmet Kamil ERISEN

Hi,
thanks for the reply.  I did setup the crontab already to
run every minute.
the webmaster account receives the report.
Here is the output that I get when I remove the
#!/usr/local/bin/php -q


/home/webvoire/www/cm/test.php: ?php: No such file or
directory
/home/webvoire/www/cm/test.php: =Cron Job has run: command
not found
/home/webvoire/www/cm/test.php: =test.php is running now:
command not found
/home/webvoire/www/cm/test.php: =: command not found
/home/webvoire/www/cm/test.php: syntax error near
unexpected token `mail($sendtome,'
/home/webvoire/www/cm/test.php:
/home/webvoire/www/cm/test.php: line 6: `   
mail($sendtome, $subject, $body);'
--- Daniel_Alsen [EMAIL PROTECTED] wrote:
 Hmm...don?t you have to actually create a job in crontab?
 
 Saying that you want a mail every day at 6:00 you would
 want to create
 something like:
 
 * 6 * * * php /usr/local/bin/php  /dev/null
 
 in crontab and lose #!/usr/local/bin/php -q in your
 script.
 
 # Daniel Alsen| www.mindbash.com #
 # [EMAIL PROTECTED]  | +46 704 86 14 92 #
 # ICQ: 63006462   | +46 8 694 82 22  #
 # PGP: http://www.mindbash.com/pgp/  #
 
 
  Hello All,
  I have a php script that i tested first through my
 browser.
  If has a simple mail() command.
  It workd fine and I received the email.
  not I tried to run it as a cron job by adding
  #!/usr/local/bin/php -q
  My webmaster account receives the confirmation that
 cron
  job has run, but I do not receive the emails that the
  program is
  supposed to send.
  This is the code:
  Thanks for the help...
 
  #!/usr/local/bin/php -q
  ?php
  $subject=Cron Job has run;
  $body=test.php is running now;
  $sendtome = [EMAIL PROTECTED];
  mail($sendtome, $subject, $body);
  ?
  --- mike cullerton [EMAIL PROTECTED] wrote:
   #!/usr/local/bin/php -q
  
   on 1/10/02 12:16 PM, Mark at [EMAIL PROTECTED]
   wrote:
  
I've got this problem that won't go away.
   
The headers are showing up at the top of the page
 when
   I run php in
cgi mode. any ideas?
  
  
-- mike cullerton
  
  
  
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Re: AW: AW: [PHP] MORE QUESTION - Editing Database

2002-01-10 Thread Mehmet Kamil ERISEN

hi,
download one of the php forum programs and look into their
code.
www.phpBB.com should be a good reference.
--- Dani [EMAIL PROTECTED] wrote:
 Hi !
 
 How do I allow HTML entries into my database?
 
 I tried to insert a pre-formated text into my database.
 When I pull the
 data out and  put it in a text field the formating is
 still there,
 HOWEVER  when I retrive the record from the database
 using echo  all
 the text formating is gone and it became just a straigh
 line. What
 function should I use in this case???
 
 
 Could anybody please help?
 
 Thank you!
 Dani
 
  Hi Dani,
 
  For sure you can use a database. There are two ways of
 using your pr
  formatted text.
 
  1)Allow HTML-entries for your database. Because the
 bullets you have
  used in your mail are from a list-tag (li/li),
 aren’t they? By
  that way you the user has two know HTML.
 
  2)Use simple entries. For example: Instead of the
 bullets you have
  used, just use “-“ as prefix for your list-item. Don’t
 use HTML-tags!
 
  Putting into the database is very easy. Because it
 doesn’t matter if
  there’s any whitespace in the entry. In my opinion you
 should use as
  type something like tinytext or text (MySQL !!!). The
 text-type allows
  entries with a size of about 65.000 bytes (65.000
 letters !!).
 
  I hope I could help you again.
 
  Bye, Marcel
 
  P.S.: Sorry for my bad english, but the last time I
 really needed it
  was in school (about 7 years ago !!!)
 
  -Ursprüngliche Nachricht-
 
  Von: Dani [mailto:[EMAIL PROTECTED]]
  Gesendet: Donnerstag, 10. Januar 2002 18:57
  An: Marcel Besancon
  Betreff: Re: AW: [PHP] MORE QUESTION - Editing Database
  Wichtigkeit: Hoch
 
  Hi Marcel !
 
  if for example I have got a pre formated text like
 this:
 
  Tour
  Adventure Tour
 
 * Adult   $123
 * Children  $123
 * etc
 
  Because later when a user edit this online, the text
 will be displayed
  on a web form (input text). I'm not sure that we can
 still preserved
  the format of the text when we try to insert it back to
 database.
 
  so...is it still possible
 
  Should I use BLOB as the type of the data in my
 database or
  ..
 
  Thank you so much for your reply! It helps me to
 understand more
 
  Sincerely,
  Dani
 
 


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[PHP] me and my CRON JOB

2002-01-10 Thread Mehmet Kamil ERISEN

hi,
here is the question:
I know I need to add a line like:
#!/usr/local/bin/php
to the begining of my php page followed by
?php
my code
?

Then set a cron job, so it runs.

I have done all that. aslo made the php file executable.
The file is executing.
First I did not put the line #!/usr/local/bin/php
and I received an email with error messages.

now I added the line with #!/usr/local/bin/php
and I am receiving an error message:
/bin/sh: /home/webvoire/www/cm/test.php: No such file or
directory

any input?

how can I find out the correct #!/usr/bin/... to put. is
there any way to figure it our from phpinfo();?



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Re: [PHP] me and my CRON JOB

2002-01-10 Thread Mehmet Kamil ERISEN

hi,
thanks for the tip.  I was wondering about it too 
I do not have access to everywhere on the server.
I tried /usr/bin/php and it worked.. :)

I tested the following script for connection to database,
executing my functions etc...
everything seems to work but mail.
any ideas?

Thanks for the help.
erisen

btw: at last, I added the die to my mail command, and fair
enough, I got the Can not send this as output.

So, now the question is, how can I send mail with php /
cron config.

please note that the script worked fine on the browser.
thx.

code:
#!/usr/bin/php -q


?php

include (application.php);

$subject=Cron Job has run;
$body=test.php is running now;
$sendtome = [EMAIL PROTECTED];
mail([EMAIL PROTECTED], $subject, $body,$sendtome)
or die ('Can not send this');
echo $sendtome;
echo hello world;

echo turk_now() ;

$array = get_user_stat($CONF) ;
while (list($key,$value)=each($array)) {
echo $key $valueBR;
}
   

?



--- Rasmus Lerdorf [EMAIL PROTECTED] wrote:
 Well, does /usr/local/bin/php exist?
 
 On Thu, 10 Jan 2002, Mehmet Kamil ERISEN wrote:
 
  hi,
  here is the question:
  I know I need to add a line like:
  #!/usr/local/bin/php
  to the begining of my php page followed by
  ?php
  my code
  ?
 
  Then set a cron job, so it runs.
 
  I have done all that. aslo made the php file
 executable.
  The file is executing.
  First I did not put the line #!/usr/local/bin/php
  and I received an email with error messages.
 
  now I added the line with #!/usr/local/bin/php
  and I am receiving an error message:
  /bin/sh: /home/webvoire/www/cm/test.php: No such file
 or
  directory
 
  any input?
 
  how can I find out the correct #!/usr/bin/... to put.
 is
  there any way to figure it our from phpinfo();?
 
 
 
  =
  Mehmet Erisen
  http://www.erisen.com
 
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Re: [PHP] Delete on exit

2002-01-09 Thread Mehmet Kamil ERISEN

Hi,
You can store all shopping cart activites in a cookie until
it is written to your database. 
When they login, call the cookie and insert the cookie SC
to the database
 

--- Ryan Kelley [EMAIL PROTECTED] wrote:
 I am writing an online store and  have setup sessions to
 run when a user
 enters the site they can shop around and browse without
 logging in. They
 only have to login when the want to checkout. But if a
 user a) closes the
 browser or b)leaves the site without buying anything then
 i need it to empty
 their cart.
 
 Any ideas?
 
 Thanks,
 
 Ryan Kelley
 
 
 
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Re: [PHP] need help looping through each record with a query - stumped

2002-01-09 Thread Mehmet Kamil ERISEN

Hi,
If I am not missing anything, you are not sorting 
SELECT Month, Score 
FROM scores 
WHERE Username = '$Username'

Also, the requirement is not three consecutive test in a
month, so I would not break the loop into months.
once you have it ordered it by the date :

   while (list($Month, $Score) = mysql_fetch_row($result2))
{


/* 
here we initialize a counter which we'll use to tally how
many tests the
user has passed over the past 3 months
*/

$tally = 0;

if ($Score = 75) {
 
$tally++ ;

   }  else {
$tally = 0;
// here you are bringing the tally back to 0 if they missed
one.
}
 
   if ($tally=3) { $certified=1 } ;

This should do it. In this loop, if there are three consc.
over 75 scores, then $certified will equal to 1.  Even
$tally goes back to 0, if the student misses a test after
being certified, $certified will not change.


At the end, instead of using $tally=3 use $certified=='1'


I hope this helps.





I would sort this by date or test_id or whatever.



--- Brian Tully [EMAIL PROTECTED] wrote:
 hey folks - 
 
 i'm stumped. been working on what i thought would be a
 simple script to
 cycle through users' records and perform a query. But I
 can't get the loops
 right, it seems like only one or two records get updated.
 
 Using MySQL, we have about 2000 students enrolled. each
 month they take a
 test. if they pass the most recent 3 tests
 (consecutively) they earn
 Certified status and get a few perks.
 
 Somehow the certification status' got messed up. So I'm
 trying to create a
 script that will look through each user's test records to
 see if they've
 passed the last 3 tests, and if so, change their
 certification status in the
 database.
 
 Not very elegant since there are so many records in the
 database (2000
 users), but I don't think i have a choice.
 
 Anyways, I've tried to loop through each user, and for
 each user loop
 through their scores. But the loops aren't working. I'm
 sure it's something
 simple and obvious I'm missing but my brain is fried!
 
 I'd appreciate it if someone could take a look and offer
 any advice. It's
 about 65 lines of code (with comments).
 
 thanks in advance!
 brian
 
 
 
 ?php
 
 include(/home/includes/.connect.inc);
 
 // Select each Username and start a loop of queries for
 each user
 
 $query = (SELECT Username, Certification FROM users);
 
 $result = mysql_query($query)
 or die (Cannot execute query . mysql_error ());
 
 /*
 here starts the loop - for each user in the database we
 look at their test
 records and try to establish if they have passed the last
 3 tests
 consecutively
 */
 
 while (list($Username, $Certification) =
 mysql_fetch_row($result)) {
 
 $query2 = (SELECT Month, Score FROM scores WHERE
 Username =
 '$Username');
 
 $result2 = mysql_query($query2) or die (Cannot
 execute query .
 mysql_error ());
 
 
 /*
 for each score record the user has, check to see if
 they've passed the last
 3 tests
 */
 
 while (list($Month, $Score) =
 mysql_fetch_row($result2)) {
 
 
 /* 
 here we initialize a counter which we'll use to tally how
 many tests the
 user has passed over the past 3 months
 */
 
 $tally = 0;
 
 if (($Month == 'January')  ($Score = 75)) {

 $tally++;
 }
 
 if (($Month == 'December')  ($Score = 75)) {

 $tally++;
 }
 
 if (($Month == 'November')  ($Score = 75)) {

 $tally++;
 }
 
 if (($Month == 'October')  ($Score = 75)) {

 $tally++;
 }
 
 }
 
 /*
 the concept is that if a user has taken and passed the
 last 3 tests, they
 become certified. so we look at the current month first
 and go back 3
 months, since it may be the beginning of the month and
 they may not have
 taken the current months test yet. Since we increase the
 counter for each
 passed test, if the counter equals 3 or more this means
 they have passed 3
 tests and are thereby certified. So we update their
 certification status in
 the database.
 */
 
 
 if ($tally = 3) {
 
 $query1 = (UPDATE users SET Certification = 'Y'
 WHERE Username =
 '$Username');

 $result1 = mysql_query($query1) or die (Cannot
 update user to
 Certified . mysql_error ());

 }
 }
 
 print (Update complete!);
 
 ?
 
 
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RE: [PHP] need help looping through each record with a query - st umped

2002-01-09 Thread Mehmet Kamil ERISEN

If you are querying the Score = 75 how are you ging to
take the Consecutive requirement into the account.
--- Martin Towell [EMAIL PROTECTED] wrote:
 could you change this
 
 $query2 = (SELECT Month, Score FROM scores WHERE
 Username =
 '$Username');
 
 to
 
 $query2 = (SELECT count(*) FROM scores WHERE
 Username = '$Username' and
 Score = 75 and Month in ('January', 'December',
 'November', 'October'));
 $result2 = mysql_query($query2) or die (Cannot
 execute query .
 mysql_error ());
 $tally = mysql_fetch_row($result2);
 
 take out the while loop (the one with all the if's in it)
 and, if I haven't
 stuffed up somewhere, all will be okay - (btw, I haven't
 had experience
 using mysql, but I'm assuming that it's sql is compatable
 with interbase and
 oracle)
 
 Hope that helps
 Martin
 
 -Original Message-
 From: Brian Tully [mailto:[EMAIL PROTECTED]]
 Sent: Thursday, January 10, 2002 8:59 AM
 To: PHP DB; PHP
 Subject: [PHP] need help looping through each record with
 a query -
 stumped
 
 
 hey folks - 
 
 i'm stumped. been working on what i thought would be a
 simple script to
 cycle through users' records and perform a query. But I
 can't get the loops
 right, it seems like only one or two records get updated.
 
 Using MySQL, we have about 2000 students enrolled. each
 month they take a
 test. if they pass the most recent 3 tests
 (consecutively) they earn
 Certified status and get a few perks.
 
 Somehow the certification status' got messed up. So I'm
 trying to create a
 script that will look through each user's test records to
 see if they've
 passed the last 3 tests, and if so, change their
 certification status in the
 database.
 
 Not very elegant since there are so many records in the
 database (2000
 users), but I don't think i have a choice.
 
 Anyways, I've tried to loop through each user, and for
 each user loop
 through their scores. But the loops aren't working. I'm
 sure it's something
 simple and obvious I'm missing but my brain is fried!
 
 I'd appreciate it if someone could take a look and offer
 any advice. It's
 about 65 lines of code (with comments).
 
 thanks in advance!
 brian
 
 
 
 ?php
 
 include(/home/includes/.connect.inc);
 
 // Select each Username and start a loop of queries for
 each user
 
 $query = (SELECT Username, Certification FROM users);
 
 $result = mysql_query($query)
 or die (Cannot execute query . mysql_error ());
 
 /*
 here starts the loop - for each user in the database we
 look at their test
 records and try to establish if they have passed the last
 3 tests
 consecutively
 */
 
 while (list($Username, $Certification) =
 mysql_fetch_row($result)) {
 
 $query2 = (SELECT Month, Score FROM scores WHERE
 Username =
 '$Username');
 
 $result2 = mysql_query($query2) or die (Cannot
 execute query .
 mysql_error ());
 
 
 /*
 for each score record the user has, check to see if
 they've passed the last
 3 tests
 */
 
 while (list($Month, $Score) =
 mysql_fetch_row($result2)) {
 
 
 /* 
 here we initialize a counter which we'll use to tally how
 many tests the
 user has passed over the past 3 months
 */
 
 $tally = 0;
 
 if (($Month == 'January')  ($Score = 75)) {

 $tally++;
 }
 
 if (($Month == 'December')  ($Score = 75)) {

 $tally++;
 }
 
 if (($Month == 'November')  ($Score = 75)) {

 $tally++;
 }
 
 if (($Month == 'October')  ($Score = 75)) {

 $tally++;
 }
 
 }
 
 /*
 the concept is that if a user has taken and passed the
 last 3 tests, they
 become certified. so we look at the current month first
 and go back 3
 months, since it may be the beginning of the month and
 they may not have
 taken the current months test yet. Since we increase the
 counter for each
 passed test, if the counter equals 3 or more this means
 they have passed 3
 tests and are thereby certified. So we update their
 certification status in
 the database.
 */
 
 
 if ($tally = 3) {
 
 $query1 = (UPDATE users SET Certification = 'Y'
 WHERE Username =
 '$Username');

 $result1 = mysql_query($query1) or die (Cannot
 update user to
 Certified . mysql_error ());

 }
 }
 
 print (Update complete!);
 
 ?
 
 
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To 

Re: [PHP] How MySQL Query and Fetch work?

2002-01-08 Thread Mehmet Kamil ERISEN

Hi,
Suppose you have a table students:
student_id / student_name / GPA

here is the code:

$sql = select * 
from students;

$result = mysql_query($sql);
 while(list($student_id,
$student_name,$gpa)=mysql_fetch_array($result) {

echo $student_name. has a GPA of.$gpa.BR;

}
 
btw, this is something really basic, you should be able to
go to the php.net and read the documentation. there are
great examples.



--- Alex Shi [EMAIL PROTECTED] wrote:
 Yesterday I posted a question yet got response. The
 question 
 is regarding to how Query works. Now I repost it in a
 more 
 specific way.
 
 I am just wondering how MySQL API functions work. Let's
 look
 at following two functions:
 
 1. mysql_query(), 
 2. mysql_fetch_array()
 
 To my understanding, mysql_query() will definately to its
 job with
 MySQL server. But how about the latter? Does it just
 fetch data
 from client/local buffer, which is previously put in by
 mysql_query(), 
 or still has to goto server side to fetch data?
 
 Alex
 
 
 
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[PHP] Arrays

2002-01-07 Thread Mehmet Kamil ERISEN

Hi,
Can anybody suggest a good reading on how to work with
arrays with multiple keys?


thanks.

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Re: [PHP] bcc

2002-01-06 Thread Mehmet Kamil ERISEN


 Dear List,
I is always a good idea to check out the manual before asking questions.
The answer to Leon's question about files is in the manual as well as the answer to 
this questions.  I hope the following links help.
File Operations:
http://www.php.net/manual/en/ref.filesystem.php
Bcc can be found in this section:
http://www.php.net/manual/en/ref.mail.php
Copying from the manual:
/* recipients */$to  = Mary [EMAIL PROTECTED] . ,  ; //note the comma$to .= 
Kelly [EMAIL PROTECTED];/* subject */$subject = Birthday Reminders for August;/* 
message */$message = 'htmlhead titleBirthday Reminders for 
August/title/headbodypHere are the birthdays upcoming in August!/ptable 
tr  thPerson/ththDay/ththMonth/ththYear/th /tr tr  
tdJoe/tdtd3rd/tdtdAugust/tdtd1970/td  
tdSally/tdtd17th/tdtdAugust/tdtd1973/td 
/tr/table/body/html';/* To send HTML mail, you can set the Content-type 
header. */$headers  = MIME-Version: 1.0\r\n;$headers .= Content-type: text/html; 
charset=iso-8859-1\r\n;/* additional headers */$headers .= From: Birthday Reminder 
[EMAIL PROTECTED]\r\n;$headers .= Cc: [EMAIL PROTECTED]\r\n;$headers 
.= Bcc: [EMAIL PROTECTED]\r\n;/* and now mail it */mail($to, $subject, 
$message, $headers);

 
  Bogdan Stancescu [EMAIL PROTECTED] wrote: What do you mean? Supported in what way? (I take 
it you're referring to
the e-mail blind carbon copy feature).

Bogdan

Deependra B. Tandukar wrote:

 Greetings !

 Is Bcc supported in PHP?

 Looking forward to hearing from you.

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Re: [PHP] IF in mysql query results problem

2002-01-06 Thread Mehmet Kamil ERISEN


Hi Jason,
I am not too familiar with IF statements in SQL, but one thing may be the reason you 
see the incorrect results:

You have three tables, player, coach and co_bookmarks, but you only join player and 
coach.  Shouldn't you join coach with co_bookmarks.

I hope this helps.

erisen


SELECT p.id AS player_id, p.name, p.hs, c.id AS coach_id, co.cid AS college,
IF(co.pid=31,1,0) AS is_bookmarked
FROM player p, coach c, co_bookmarks co
WHERE p.id=31 AND p.hs=c.id AND co.cid=2


  Jason Dulberg [EMAIL PROTECTED] wrote: I am working on a program that allows users 
to bookmark a particular item
that they view. The bookmarks are stored in the database.

I would like to use an IF statement in the mysql query so when the user logs
in and views the items, the option to bookmark the record has been removed
if they have already bookmarked it.

Here's an example query:

SELECT p.id AS player_id, p.name, p.hs, c.id AS coach_id, co.cid AS college,
IF(co.pid=31,1,0) AS is_bookmarked
FROM player p, coach c, co_bookmarks co
WHERE p.id=31 AND p.hs=c.id AND co.cid=2

When I use the above query in a search, it comes up with 3 results, 1 of
which is correct. If I GROUP BY p.id, there is only 1 result but its
incorrect. The search should only come up with 1 correct result in this
case.

+---+-++--+-+---+
| player_id | name | hs | coach_id | college | is_bookmarked |
+---+-++--+-+---+
| 31 | Paul Mantle | 24 | 24 | 2 | 0 |
| 31 | Paul Mantle | 24 | 24 | 2 | 1 |
| 31 | Paul Mantle | 24 | 24 | 2 | 0 |
+---+-++--+-+---+

+---+-++--+-+---+
| player_id | name | hs | coach_id | college | is_bookmarked |
+---+-++--+-+---+
| 31 | Paul Mantle | 24 | 24 | 2 | 0 |
+---+-++--+-+---+

The row with is_bookmarked = 1 is the only correct one. I am assuming that
for some reason, its displaying 3 results because there are 3 id's
associated with cid=2. But if I group them by the id, it takes the wrong
row:

If anyone has any suggestions as to what I'm doing wrong, please let me know
as I'm tapped out on ideas.

Thanks a TON!!

__
Jason Dulberg
Extreme MTB
http://extreme.nas.net


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Re: [PHP] MySQL error... but it works!!??

2002-01-05 Thread Mehmet Kamil ERISEN


 Hi,
So far the best way to troubleshoot mysql+php for me has been to add an or die after 
the sql exec.
$crdate = date(Y-m-d);
$result = mysql_query(SELECT * FROM sites WHERE creation_date = '$crdate'
AND status = 'T') or die ('CAN NOT EXEC SQL');

Or you can do 

$sql = SELECT * FROM sites WHERE creation_date = '$crdate'
AND status = 'T';

echo $sql;

$result = mysql_query($sql) or die .;

and try to run your sql against mysql directly to make sure your sql is fine.

one thing to always check is your connection to the database. did you connect?


 

  Simon Kimber [EMAIL PROTECTED] wrote: Does anyone have any idea why this is giving 
me a Warning: Supplied
argument is not a valid MySQL result resource in... error?

The funny thing is that apart from that error message it works perfectly!!

---

$crdate = date(Y-m-d);
$result = mysql_query(SELECT * FROM sites WHERE creation_date = '$crdate'
AND status = 'T');

while ($sitedata = mysql_fetch_array($result)) {

echo $sitedata['name'] . 
;

}

---

Cheers

Simon


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[PHP] sorting and limitin sql in php pages??????

2002-01-05 Thread Mehmet Kamil ERISEN


Hi,

As the data grows I like to add the functionality that people see 30 lines of the 
result on one page. Also I like to give users the ability to sort per columns... 

I know this is done pretty much everwhere.  What's the best or easiest way of doing it?

 

 


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Re: [PHP] Re: php-general Digest 3 Jan 2002 12:22:53 -0000 Issue 1089

2002-01-04 Thread Mehmet Kamil ERISEN

you can aslo go to www.php.net and read the emails from
your browser.
--- Garth Dahlstrom [EMAIL PROTECTED] wrote:
 
 If you don't like getting 50 messages a day, I suggest
 using this list's digest mode, then you get 1 big message
 with your daily dose of 50 messages tucked away neatly 
 inside.  :)
 
   Matt Moreton 
  -  Re: [PHP] Holy Moly...
  -  Thu, 3 Jan 2002 03:03:02 -
  
  If you dont mind downloading ~50 messages a day, then
 I'd 
  recommend this
  group :]
  
  Regards
  
  Matt.
 
 
 
 
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Re: [PHP] php+mysql simple query help me pls! ty.

2002-01-03 Thread Mehmet Kamil ERISEN

I hope I am not wrong, but the problem is with the
mysql_result() functions.
Instead, I would use:
whilie ($myrow=mysql_fetch_array($result)) {
//put whatever you like here.
}

and instead of 
mysql_result($result,0,asl)
 $myrow[asl]

I hope this helps.

from the manual
http://www.php.net/manual/en/function.mysql-result.php

mysql_result() returns the contents of one cell from a
MySQL result set. The field argument can be the field's
offset, or the field's name, or the field's table dot field
name (tablename.fieldname). If the column name has been
aliased ('select foo as bar from...'), use the alias
instead of the column name. 

When working on large result sets, you should consider
using one of the functions that fetch an entire row
(specified below). As these functions return the contents
of multiple cells in one function call, they're MUCH
quicker than mysql_result(). Also, note that specifying a
numeric offset for the field argument is much quicker than
specifying a fieldname or tablename.fieldname argument. 

Calls to mysql_result() should not be mixed with calls to
other functions that deal with the result set. 

Recommended high-performance alternatives:
mysql_fetch_row(), mysql_fetch_array(), and
mysql_fetch_object(). 


--- louie miranda [EMAIL PROTECTED] wrote:
 Hi, can someone help me here! :(
 I can't query the data on my sql from php.
 db is fine, i couldnt see the prob in php!
 pls help, ty.
 
 
 
 # MSQL
 ###
 mysql desc members;

+--+-+--+-+-++
 | Field| Type| Null | Key | Default | Extra  
|

+--+-+--+-+-++
 | id   | tinyint(5)  |  | PRI | NULL|
 auto_increment |
 | ircname  | varchar(30) | YES  | | NULL|
|
 | email| varchar(30) | YES  | | NULL|
|
 | realname | varchar(40) | YES  | | NULL|
|
 | asl  | varchar(30) | YES  | | NULL|
|
 | info | varchar(70) | YES  | | NULL|
|

+--+-+--+-+-++
 
 
 
 # PHP
 
 html
 body
 
 ?php
 
 $db = mysql_connect(my_db_host, my_db_user,
 my_db_pass)
 or die(Could not connect);
 
 mysql_select_db(mydb,$db);
 
 $result = mysql_query(SELECT * FROM members,$db);
 
 printf(ircname: %sbrn,
 mysql_result($result,0,ircname));
 printf(email: %sbrn,
 mysql_result($result,0,email));
 printf(realname: %sbrn,
 mysql_result($result,0,realname));
 printf(asl: %sbrn, mysql_result($result,0,asl));
 printf(info: %sbrn, mysql_result($result,0,info));
 
 ?
 
 /body
 /html
 
 
 # ERROR


 
 
   Warning: Supplied argument is not a valid MySQL result
 resource in
 /mnt/host-users/cavite/irc/members/t2.php on line 13
 ircname:
 n
 Warning: Supplied argument is not a valid MySQL result
 resource in
 /mnt/host-users/cavite/irc/members/t2.php on line 14
 email:
 n
 Warning: Supplied argument is not a valid MySQL result
 resource in
 /mnt/host-users/cavite/irc/members/t2.php on line 15
 realname:
 n
 Warning: Supplied argument is not a valid MySQL result
 resource in
 /mnt/host-users/cavite/irc/members/t2.php on line 16
 asl:
 n
 Warning: Supplied argument is not a valid MySQL result
 resource in
 /mnt/host-users/cavite/irc/members/t2.php on line 17
 info:
 n
 
 
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Re: [PHP] printing php variable into html print $result; ?

2002-01-03 Thread Mehmet Kamil ERISEN

use 
$sql = select .. ;
$result = mysql_query($sql);
echo $sql;

--- louie miranda [EMAIL PROTECTED] wrote:
 Hi, is it possible to print the sql query? i mean
 i want to print the output of the command SELECT * FROM
 members;
 and output it into html, i tried
 
 print $result; -- it gives me different output..
 
  Resource id #2
 
 
 ty,
 louie...
 
 # PHP SCRIPT
 ###
 
 html
 body
 
 ?php
 
 $db = mysql_connect(my_db_host, my_db_user,
 my_db_pass)
 or die(Could not connect);
 
 mysql_select_db(cavite,$db);
 
 $result = mysql_query(SELECT * FROM members,$db) or
 die(Error:.mysql_error()
 );
 
 printf(ircname: %sbr,
 mysql_result($result,0,ircname));
 printf(email: %sbr, mysql_result($result,0,email));
 printf(realname: %sbr,
 mysql_result($result,0,realname));
 printf(asl: %sbr, mysql_result($result,0,asl));
 printf(info: %sbr, mysql_result($result,0,info));
 
 print brbr;
 
 ?
 
 /body
 
 /html
 
 # PHP SCRIPT
 ###
 
 
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Re: [PHP] mysql_fetch_array

2001-12-30 Thread Mehmet Kamil ERISEN


 Hi,
In your SQL, you can say
select t1.col colt1, t2.col colt2
from table1 t1, table2 t2
where t1.something = t2.samething
In other words, you can name your columns differently in your select clause.
I
  Bogdan Stancescu [EMAIL PROTECTED] wrote: If everything else fails, you should consider 
using mysql_fetch_row() instead.

Bogdan

Greg Sidelinger wrote:

 Ok I have use mysql_fetch_array to dump the results of a select query with a
 join in it.
 if my tables contain a column with the same name how can I distinguish from
 them.


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[PHP] Time function question/

2001-12-27 Thread Mehmet Kamil ERISEN

Hi,
Can anybody suggest a function that will generate a random
date between 
01-Jan-1967
31-Dec-1985

thanks.


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Re: [PHP] Passing Logined in Name form One Form to other Page

2001-12-20 Thread Mehmet Kamil ERISEN


 Hi,
May I suggest that you take a look at the code library at zend.com, and devshed.com .  
I remember seeing a login application using the SESSIONS.
Alternatively, you can use cookies to let your browser know who is browsing.
 
  Jack [EMAIL PROTECTED] wrote: Dear all
I had create the Login Page for the User to login before they can open the
WebPage. What i want to do is to:

When the User had type the Username into the Inputbox, and click the submit
button, this Username will be memorized, and pass to other PHP Page.Then
when he go to some page which need to select data from MYSQL, it will read
the Username which passed from the Login Form and select the only Record to
him!

I heard about the Session, but how i can pass the Username to other page
using Session??

Pls Help!

Thx a lot !
jack
[EMAIL PROTECTED]



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Re: [PHP] How to backup records in mySQL DB?

2001-12-20 Thread Mehmet Kamil ERISEN


 Dear Friend,
If I were you, I would take my biz elsewhere.  BTW, which company is that?
Anyway, I will recommend you to use the phpMyAdmin.  It's a mysql database management 
tool written in PHP, free of charge of course, that lets you manage your database.  
One of the cool things it that it dumps your database into a flat file with table 
creation and INSERT commands, so that in case you need to restore you databases, you 
just run the sql.
I hope this helps.
Mehmet.
  Thomas Edison Jr. [EMAIL PROTECTED] wrote: Hi,

I'm having a touch situation on my hands. Last week
one of my site was shut down in what the Hosting
Company claimed to be a Policy Violation. However, it
was found out later that it wasn't so and they had to
re-host my site.

Unfortunately, they erased my mySQL database with my
account and we lost all our very important Data in the
tables there. It's horrible.

We're beggining again but i'm not scared about the
Data. The data is posted online by users. I need to
have a way to backup my mySQL data. If possible, on
some other site location or in Hard Copy (As in a
file) or something. I don't know how to do any of
this. I have no idea what to do about it. Can anyone
make any suggestions  help?

Regards,
T. Edison jr.


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Email : [EMAIL PROTECTED]
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[PHP] Translate question

2001-12-20 Thread Mehmet Kamil ERISEN

Hello,
I am trying to transalte entry in Turkish Characters to
English Characters.

I wrote the following code.

  function translate_turkish($string) {
   $estring = strtr($string, ç, c);
   $estring = strtr($string, ç, c);

  $estring = strtr($estring, ð, g);
  $estring = strtr($estring, G, G);

  $estring = strtr($estring, þ, s);
  $estring = strtr($estring, S, S);

  $estring = strtr($estring, ý, i);
  $estring = strtr($estring, I, XX);  *


  $estring = strtr($estring, ü, u);
  $estring = strtr($estring, Ü, U);
  
  $estring = strtr($estring, ö, o);
  $estring = strtr($estring, Ö, O); 
  
  return ($estring)  ;
  }

Capital i (not I but it shows at the line where you see the
XX) is causing a problem. I can not translate. from cap i
to I.

Can you please suggest any help?

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[PHP] Book.

2001-12-19 Thread Mehmet Kamil ERISEN

Hi All,
I have a good understanding of PHP.  I like to read more
documentation advanced PHP topics and also some more
information on how to run PHP from Unix, as a cron job, how
can PHP scripts be called from Shell Scripts etc...

Any book or doc suggestions.

Thanks,
erisen.

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Re: [PHP] sessions var

2001-12-19 Thread Mehmet Kamil ERISEN

One problem that I have with sessions it that if your login
page is in www.yoursite.com and the you pop a page
yoursite.com I think the Session is not recognized.
just a hint.
--- William Sanchez Sanchez [EMAIL PROTECTED] wrote:
 
 
 I need some help with sessions. I need to pass variables
 to a page that will
 load 
 in a new browser window (window.open(,myWindow,) and
 form ...
 target=myWindow). 
 I used session_register and I tried using start_session 
 and still no luck.  Once I get the session vars
 registered, how do I 
 access them from the new window opened...
 
 
 thanks in advantage...
 
   
 
   William.  
 
 
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Re: [PHP] Book.

2001-12-19 Thread Mehmet Kamil ERISEN

Hi,
I think I'm misunderstood.  I do not want to run in cgi
mode.
Thanks,
Mehmet.
--- Martín Marqués [EMAIL PROTECTED] wrote:
 On Mié 19 Dic 2001 19:14, you wrote:
  Hi All,
  I have a good understanding of PHP.  I like to read
 more
  documentation advanced PHP topics and also some more
  information on how to run PHP from Unix, as a cron job,
 how
  can PHP scripts be called from Shell Scripts etc...
 
 You need to compile PHP without web-server support, for
 cgi. In that case you 
 will get a binary file, and you can use just like you use
 perl or bash for 
 making scripts.
 
 For the developers: Is there a posibility of adding some
 ability for 
 compilation of, for example, apache and binary stand
 alone php?
 
 -- 
 Porqué usar una base de datos relacional cualquiera,
 si podés usar PostgreSQL?

-
 Martín Marqués  |   
 [EMAIL PROTECTED]
 Programador, Administrador, DBA |   Centro de
 Telematica
Universidad Nacional
 del Litoral

-


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[PHP] How deep can I go with embedded if s.

2001-12-17 Thread Mehmet Kamil ERISEN

Hello All,
Is anybody aware of any limitations of php on embedded if
..else statements?
For example:

  if ($a$b) {
if ($c$d) {
this();
   } else {
 if ($gg==$dd) {
 echo 'ladooo';
   } else {
 echo 'bab';
   }
that();
   }
if ($e$f) {
   tthis();
  } else {
   tthat(); 
   }
   else {
echo Oooops;

}

would this work, 


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Re: [PHP] Opening a new window.

2001-12-14 Thread Mehmet Kamil ERISEN

I would use javascript for that.  
--- Brandon Orther [EMAIL PROTECTED] wrote:
 Does anyone know how I could have php open a new windows
 with the url I
 specify?
  
 Thanx,
 Brandon
 


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RE: [PHP] Opening a new window.

2001-12-14 Thread Mehmet Kamil ERISEN

that's a great point.  Can you specify the target browser
properties using html?
Lise the Location bar, or the toolbar?
I was actually using little popups with jscript. If I can
get rid of JS that would be great.
--- Mark Charette [EMAIL PROTECTED] wrote:
 I would use target=_blank in the anchor tag  so it
 would work just fine
 _without_ javascript ...
 
 Mark C.
 
 -Original Message-
 From: Mehmet Kamil ERISEN [mailto:[EMAIL PROTECTED]]
 
 I would use javascript for that.
 --- Brandon Orther [EMAIL PROTECTED] wrote:
  Does anyone know how I could have php open a new
 windows
  with the url I
  specify?
 
  Thanx,
  Brandon
 
 
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Re: [PHP] Searching for a new provider

2001-12-12 Thread Mehmet Kamil ERISEN

Hi,
I use connecticut-web.com. Pretty good.  fast. The most
important value is that the customer service is excellent.
They provide email and icq service and very prompt in
returning requests.


--- R'twick Niceorgaw [EMAIL PROTECTED] wrote:
 take a look at aletia hosting (www.aletiahosting.com).
 Their low end is just
 $9.95 ( $7.95 if paid anually + free domain registration)
 and is feature
 rich ( 200Mb space, PHP 4.0.6 moving to 4.1 soon, My SQL
 (10 databases) 10GB
 bandwidth etc). I have moved to them few months back and
 their speed and
 support looks good to me.
 
 Regards
 R'twick
 
 - Original Message -
 From: Andy [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Wednesday, December 12, 2001 4:06 PM
 Subject: [PHP] Searching for a new provider
 
 
  Hi there, I am searching for a provider who fullfills
 those criterias and
  does not cost a fortune:
 
   - PHP = 4.06 bzw. PHP 4.x mit GDLibrary ab 2.0
 
   - GDLibrary = 2.0
 
- PHP installed as module
 
   - mind 5 Subdomains
 
   - mind 100 MB Speicherplatz
 
   - evtl. Java VM
 
   - MySQL
 
 
 
  Thanx andy
 
 
 
 
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Re: [PHP] Date

2001-12-12 Thread Mehmet Kamil ERISEN

what's your raw data. I mean, what is the value of
$row[mydatafield];

--- Max [EMAIL PROTECTED] wrote:
 Hi to all,
 
 I'm using this to get date from mySQL database:
 
 ...
 $p_datum = $row[mydatefield];
 $mydate = getdate($p_datum); 
 $month = $mydate['month']; 
 $mday = $mydate['mday']; 
 $year = $mydate['year']; 
 
 ..but I allways get 1/1/1970.
 
 Can anybody help me?
 
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Re: [PHP] session

2001-12-11 Thread Mehmet Kamil ERISEN

Hi,
I think you can include pages from other sites, servers.
SESSIONS (I think) are server specific, cuz the info is
kept on the server.  
If you tell me what u gonna be doing, I can give you ideas.
thx.
erisen
--- Jordan [EMAIL PROTECTED] wrote:
 is there anyway to drag session variables to another
 server or are they
 server specific?  If you can't drag a session can you do
 an include for a
 page on a different server giving it's URL?  Just
 curious.
 
 -Jordan
 
 
 
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[PHP] Redirect + SESSION question!!!

2001-12-10 Thread Mehmet Kamil ERISEN

Hello All,
I have switched hosting companies.  previous server was
php4.04pl1 now I am on a server that is php4.06.

I have a file (functions.php) that stores all my SESSION
and other functions.  A Header file, that has the general
feel and look of the site. In brief most of my pages have 
include(functions.php);
include(header.php);

I also use the Header(Location: mysite.com) kind of
functions a lot.

Well, it worked fine in the prev server, now it does not. I
read the documentation
(http://download.php.net/manual/en/function.header.php)
, and it suggests to use of the ob_start() and 
ob_end_clean() etc...  I used those. I can redirect, but
now, my SESSION does not work!!!

Anybody had a similar experience? Please help... 
thanks.
erisen

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Re: [PHP] Redirect + SESSION question!!!

2001-12-10 Thread Mehmet Kamil ERISEN

I am almost there folks.  The issue is being resolved by
using the ob_start(garbage); at the begining of the
login.php script, and ob_end_flush(); at the end of the
login.php script (in case the authentication fails and user
stays on the page), and also put ob_end_flush(); at the top
of the index.php page.
Woow. I guess the problem was all the sudden the $SESSION[]
operations were considered output bu Header().

Gurus, do you think I am filling up my pages with garbage,
or what I am saying is making sense?

Thanks.
Erisen
--- Mehmet Kamil ERISEN [EMAIL PROTECTED] wrote:
 Hello All,
 I have switched hosting companies.  previous server was
 php4.04pl1 now I am on a server that is php4.06.
 
 I have a file (functions.php) that stores all my SESSION
 and other functions.  A Header file, that has the general
 feel and look of the site. In brief most of my pages have
 
 include(functions.php);
 include(header.php);
 
 I also use the Header(Location: mysite.com) kind of
 functions a lot.
 
 Well, it worked fine in the prev server, now it does not.
 I
 read the documentation
 (http://download.php.net/manual/en/function.header.php)
 , and it suggests to use of the ob_start() and 
 ob_end_clean() etc...  I used those. I can redirect, but
 now, my SESSION does not work!!!
 
 Anybody had a similar experience? Please help... 
 thanks.
 erisen
 
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