Re: [PHP] parse error
Looks like your problem is on line 24. See below.
-Steve
On Tuesday, April 30, 2002, at 12:48 PM, Jule wrote:
Hey guys, i'm writing this guestbook script for my site, and i'm
getting a
random parse error where i think everything is normal, it gives it on
line 26
which is
echo Your entry will be posted!;
my script follows
Jule
--SCRIPT--
?php
$Guestbook[dateadd] = date(F j, Y H:i:s);
$Guestbook[name] = trim($Guestbook[name]);
$Guestbook[town] = trim($Guestbook[town]);
$Guestbook[email] = trim($Guestbook[email]);
$Guestbook[website] = trim($Guestbook[website]);
$Guestbook[favsong] = trim($Guestbook[favsong]);
$Guestbook[comments] = trim($Guestbook[comments]);
$Guestbook[mailinglist] = trim($Guestbook[mailinglist]);
$Host = localhost;
$User = ;
$Password = *;
$DBName = blindtheory;
$TableName = guestbook;
$TableName2 = mailinglist;
$Pattern = .+@.+..+;
$Pattern2 = (http://)?([^[:space:]]+)([[:alnum:]\.,-_?/=]);
$Link = mysql_connect ($Host, $User, $Password);
$Query = INSERT into $TableName values('0', '$Guestbook[dateadd]',
'$Guestbook[name]', '$Guestbook[town]', '$Guestbook[email]',
'$Guestbook[website]','$Guestbook[favsong]', '$Guestbook[comments]');
$Link2 = mysql_connect ($Host, $User, $Password);
$Query2 = INSERT into $TableName2 values('0', '$Guestbook[dateadd]',
'$Guestbook[name]', '$Guestbook[email]');
You're missing a final double quote here ^.
if (mysql_db_query ($DBName, $Query, $Link)) {
echo Your entry will be added;
} else {
echo There was an error in during the posting, please contact
a
href=\mailto:[EMAIL PROTECTED]\;me/a and I will fix the
problem.br;
}
if (isset($Guestbook[mailinglist])) {
if (mysql_db_query ($DBName, $Query2, $Link2)) {
echo Your e-mail address was sucessfully added to
our mailinglist;
} else {
echo There was an error in during the posting, please
contact a
href=\mailto:[EMAIL PROTECTED]\;me/a and I will fix the
problem.br;
}
}
mysql_close ($Link);
mysql_close ($Link2);
?
--
Jule Slootbeek
[EMAIL PROTECTED]
http://blindtheory.cjb.net
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Re: [PHP] Cannot add header information
On Monday, April 29, 2002, at 12:02 PM, Bo Pritchard wrote: I know without the accompanying code there's no way to help me...But without having to get real specific what does the following message tell me is wrong? Thanks Warning: Cannot add header information - headers already sent by (output started at /home/omnidevi/omnidevices-www/s-cart/form.phtml:4) in /home/omnidevi/omnidevices-www/s-cart/shop-head.phtml on line 44 In shop-head.phtml on line 44 you're apparently trying to do something that sends an http header (like starting a session, setting a cookie, etc.), however, all http headers must be sent before any html is goes out and the error says html output already started in form.phtml on line 4. Note this is about http headers which are different than the html head stuff. -Steve -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array Question
On Thursday, April 18, 2002, at 04:38 PM, Jason Lam wrote:
$arr2 is a 2d array.
$arr1[0] = 1;
$arr1[1] = 10;
$arr2[0] = $arr1;
print $arr2[0][1];
Result will be 10
But,
$arr1[0] = 1;
$arr1[1] = 10;
$arr2[0] = $arr1;
$arr3 = each($arr2);
print $arr3[1];
What are you expecting? Check out the documentation for each() at
http://www.php.net/manual/en/function.each.php
At this point $arr3 should look like this (I think, but try
print_r($arr3) to be sure):
{
0 = 0,
1 = array (
0 = array (
0 = 1,
1 = 10
)
),
key = 0,
value = array (
0 = array (
0 = 1,
1 = 10
)
)
}
Result is not 10. So, function each is not taking the whole $arr2[0]
out..
My question is what function should I use to iterate array elements
(with
arrays in it)?
How about foreach()?
-Steve
Jay
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Re: [PHP] Please Help
Check out the bottom of each message... -Steve On Tuesday, April 16, 2002, at 10:43 AM, Omland Christopher m wrote: Can anyone tell me how to unsubscribe. There is just a bit too much volume for me. Thanks. -Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] What date/time was it 7 hours ago?
You could convert it to a timestamp using strtotime(), subtract 7*60*60, then convert it back to a string with strftime(). -Steve On Monday, April 15, 2002, at 09:50 AM, Torkil Johnsen wrote: What date/time was it 7 hours ago? I'm just trying to make a log using mysql/php This log is kinda supposed to show the time, local to the user. So I store datetime on the format -MM-DD HH:MM:SS in a datetime field. Using the php date function to get the date. This will store the time that right then ON THE SERVER. Now, when fetching data from the mysql table, I want to display what the time WAS, LOCALLY (where I'm at, not the server) when the log entry was made. So. How do I make a function that takes in -MM-DD HH:MM:SS and spits out the -MM-DD HH:MM:SS minus... for instance, 7 hours? What date/time was it 7 hours ago? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] calculating US holidays
You could port Date::Calc from perl... or just call a perl script to do
the calculation. Probably the easiest way to figure out Easter (for the
extreme example) that I can think of.
-Steve
On Monday, April 15, 2002, at 03:05 PM, Tom Beidler wrote:
That's fine for fixed dates, and I have that figured out, but presidents
day, memorial day, labor day and thanksgiving fall on different days
each
year. Presidents day is the third monday of February. How do I calculate
that?
From: Tyler Longren [EMAIL PROTECTED]
Organization: Captain Jack Communications
Date: Mon, 15 Apr 2002 14:48:15 -0500
To: Tom Beidler [EMAIL PROTECTED], php list
[EMAIL PROTECTED]
Subject: Re: [PHP] calculating US holidays
?
$month = date(m);
$day = date(d);
if ($month == 10 $day == 31) {
print It's Halloween!;
}
?
you could do something similar to that.
tyler
- Original Message -
From: Tom Beidler [EMAIL PROTECTED]
To: php list [EMAIL PROTECTED]
Sent: Monday, April 15, 2002 2:17 PM
Subject: [PHP] calculating US holidays
I need to calculate the date to see if it's a holiday, i.e. is today
presidents day, which happens to be the third monday of february. Can
someone point me to some code that can do that?
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Re: [PHP] How to sort by 3rd row in an 2d-Array
Or try the usort() function?
?php
...
myArray[1][firstname] = Joe;
myArray[1][lastname] = Smith;
myArray[1][company] = Bullock;
myArray[1][email] = [EMAIL PROTECTED];
myArray[2][firstname] = Jim;
myArray[2][lastname] = Cords;
myArray[2][company] = Jamen;
myArray[2][email] = [EMAIL PROTECTED];
...
function companyCmp ($a, $b) {
return strcmp($a[company],$b[company]);
}
usort ($myArray, companyCmp);
...
?
-Steve
On Friday, April 12, 2002, at 12:26 PM, Kevin Stone wrote:
This is a terribly inneficient way of handling your situation but I
believe
it would work.
// First we're going to make a list of all company values
for($i=0; $icount($myarray); $i++)
{
$company_values[] = $myarray[$i][company];
}
// Then we're going to order the array using a standard function.
natsort($company_values);
// Then we're going to go through $myarray looking for each matching
// value and build a new array based on the order of the sorted list.
for($i=0; $icount($company_values); $i++)
{
for ($j=0; $j=count($myarray); $j++)
{
if ($company_values[$i] == $myarray[$j][company])
{
$mynewarray[] = $myarray[$j];
}
}
}
// bada bing bada boom you gots your company sorted list... I think
$myarray = $mynewarray;
I wrote this off the top of my head in like three minutes so any and all
corrections would be most welcome. ;)
-Kevin
- Original Message -
From: SED [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, April 12, 2002 10:25 AM
Subject: [PHP] How to sort by 3rd row in an 2d-Array
Hi,
I'm trying to sort an array like following
myArray[1][firstname] = Joe;
myArray[1][lastname] = Smith;
myArray[1][company] = Bullock;
myArray[1][email] = [EMAIL PROTECTED];
myArray[2][firstname] = Jim;
myArray[2][lastname] = Cords;
myArray[2][company] = Jamen;
myArray[2][email] = [EMAIL PROTECTED];
etc...
by the company name. How can I do it?
I found the solution on php.net
(http://www.php.net/manual/en/function.array-multisort.php) but it
sorts
only the first row:
foreach ($myArray as $val) {
$sortarray[] = $val['nafn'];
echo $val['stadur'];
}
array_multisort($myArray, $sortarray);
Thanks in advance!
SED
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Re: [PHP] Wanting a better understanding of classes in PHP...
Well, start here probably: http://www.php.net/manual/en/language.oop.php -Steve On Friday, April 12, 2002, at 12:50 PM, Chuck PUP Payne wrote: Hi, I was up on freshmeat and I saw a TON of php classes. I like to know how can I use them? And is a class a bit of code that you are always using? If so, how can I create my own classes. Chuck PUP Payne Sr. System Administrator GDI Engineering, Inc. 2075-E West Park Place Blvd. Stone Mountain, GA 30087 --- (678) 476-0747 ext. 18 (Phone) (770) 498-1590 (Fax) (404) 451-3579 (Mobile) (800) 631-1371 (Alpha Page) [EMAIL PROTECTED] (Text Pager) [EMAIL PROTECTED] (E-Mail) --- http://www.gdieng.com http://www.gditelecommunication.com http://www.softmeta.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Classes??
Yeah, sure. -Steve On Thursday, April 4, 2002, at 10:42 AM, Gerard Samuel wrote: Maybe a simple question. But can one file contain 2 or more classes?? Thanks -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] English/Arabic Mysql problem...
Are you using unicode? I don't know the answer for you - maybe check the mysql site - but I'd be interested in hearing an answer as well if anyone has one. -Steve On Thursday, April 4, 2002, at 12:11 AM, Dhaval Desai wrote: Hello people, I am making a bilingual website English/Arabic. I am facing some problem with this. The problem is that I am not able to insert arabic lanaguage characters ionto Mysql databse. It gets junk characters...when I try to display it... Thank You Best Regards, Dhaval Desai _ Send and receive Hotmail on your mobile device: http://mobile.msn.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] objects handling objects
On Thursday, April 4, 2002, at 04:21 PM, Erik Price wrote:
I looked in the manual, but didn't see anything about this. I've read
that PHP isn't a true object-oriented language, but rather simulates
elements of object-oriented programming. Can I write a class that
performs operations and manipulates objects? Can objects be placed
into arrays etc?
Erik
The real hindrance I've come up against is that you can't do chained
method calls, otherwise objects perform pretty well as expected. Keep in
mind the difference between passing by reference and by copy, though, or
you'll find yourself updating a copy of an object somewhere instead of
the original.
-Steve
Here's some code I was just playing around with:
?php
class classA {
function method1() {
return 1;
}
function method2() {
return 2;
}
}
class classB {
function method1($num = 0) {
return $num + 10;
}
function method2($num = 0) {
return $num+20;
}
}
class classC {
function echoMethod($object) {
return $object;
}
}
class classD {
function otherMethod1($object) {
return $object-method1();
}
function otherMethod2($object) {
return $object-method2();
}
}
$a = new classA;
$b = new classB;
$c = new classC;
$d = new classD;
print(a1: . $a-method1() . br /\n);
print(a2: . $a-method2() . br /\n);
print(b1: . $b-method1($a-method1()) . br /\n);
print(b2: . $b-method2($a-method2()) . br /\n);
print(d1: . $d-otherMethod1($b) . br /\n);
print(d2: . $d-otherMethod2($c-echoMethod($a)) . br /\n);
// this next line would generate a parse error
// print(c:a1: . $c-echo($a)-method1() . br /\n);
// this outputs:
// a1: 1
// a2: 2
// b1: 11
// b2: 22
// d1: 10
// d2: 2
?
Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]
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Re: [PHP] objects handling objects
Doh, typo:
// this next line would generate a parse error
// print(c:a1: . $c-echo($a)-method1() . br /\n);
should read
// this next line would generate a parse error
// print(c:a1: . $c-echoMethod($a)-method1() . br /\n);
On Thursday, April 4, 2002, at 05:25 PM, Steve Cayford wrote:
On Thursday, April 4, 2002, at 04:21 PM, Erik Price wrote:
I looked in the manual, but didn't see anything about this. I've read
that PHP isn't a true object-oriented language, but rather simulates
elements of object-oriented programming. Can I write a class that
performs operations and manipulates objects? Can objects be placed
into arrays etc?
Erik
The real hindrance I've come up against is that you can't do chained
method calls, otherwise objects perform pretty well as expected. Keep
in mind the difference between passing by reference and by copy,
though, or you'll find yourself updating a copy of an object somewhere
instead of the original.
-Steve
Here's some code I was just playing around with:
?php
class classA {
function method1() {
return 1;
}
function method2() {
return 2;
}
}
class classB {
function method1($num = 0) {
return $num + 10;
}
function method2($num = 0) {
return $num+20;
}
}
class classC {
function echoMethod($object) {
return $object;
}
}
class classD {
function otherMethod1($object) {
return $object-method1();
}
function otherMethod2($object) {
return $object-method2();
}
}
$a = new classA;
$b = new classB;
$c = new classC;
$d = new classD;
print(a1: . $a-method1() . br /\n);
print(a2: . $a-method2() . br /\n);
print(b1: . $b-method1($a-method1()) . br /\n);
print(b2: . $b-method2($a-method2()) . br /\n);
print(d1: . $d-otherMethod1($b) . br /\n);
print(d2: . $d-otherMethod2($c-echoMethod($a)) . br /\n);
// this next line would generate a parse error
// print(c:a1: . $c-echo($a)-method1() . br /\n);
// this outputs:
// a1: 1
// a2: 2
// b1: 11
// b2: 22
// d1: 10
// d2: 2
?
Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]
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Re: [PHP] Loop, array, life....
On your first email you loop through all the news in the $newsfetch
resource. I think you need to then do a mysql_data_seek() call against
that to reset it for the next time through the loop. Otherwise you'll
just get a null result because you're already at the end of the data.
-Steve
On Wednesday, April 3, 2002, at 02:30 PM, Gerard Samuel wrote:
(made a correction in sudo code)
Ok, this one is breaking my back all day.
First some sudo-code -
fuction email_to_user() {
$sql = 'select distinct(email) from user';
$emailfetch = mysql_query($sql);
$sql = 'select news, date from news order by sid desc limit 10';
$newsfetch = mysql_query($sql);
while ($data = mysql_fetch_row($emailfetch)) {
$container = array();
$container[] = 'htmlheadtitle/headbody';
$message = 'Have a nice day';
$container[] = $message;
// PROBLEM IN THIS WHILE LOOP MAYBE //
while (list($news, $date) = mysql_fetch_row($newsfetch)) {
$container[] = 'a href='newslink.php'' . $news . '/a';
$container[] = 'brhrbr';
}
$container[] = '/body/html';
$message2 = '';
foreach($container as $foo) {
$message2 .= $foo;
}
mail(Send mail to $data[0], $message2);
unset($container);
}
}
Basically it grabs all the user's email addresses, then loop them.
On each loop grab all news items.
Then emails results to the user and moves on to the next user.
Im running this on my test box, that only has two users, but the 2nd
user never gets the expected results.
The first user get the message and the news.
The second only gets the message.
The code structure is pretty much unchanged from a working example till
I started using $container to hold array elements.
Could anyone see bad logic in the above code??
Thanks
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Re: [PHP] session
Try putting session_start() in your retief.php script as well as piet.php. -Steve On Wednesday, April 3, 2002, at 01:06 PM, R. Lindeman wrote: okay i've posted something before here are my scripts either you tell me what i do wrong or i'll go beserk you can check the outcome of the code on the following adress http://www.filenexus.com/piet.php here's the code for piet.php : ?php // open session and begin registering values session_start(); session_register(fubar1); session_register(fubar2); session_register(fubar3); $fubar1=Remko; $fubar2=Lindeman; $fubar3=I3M1I; header(Location: retief.php?.SID); ? here's the code for retief.php : ?php // begin the retrieval of propagated values $remko = $HTTP_SESSION_VARS[fubar1]; $lindeman = $HTTP_SESSION_VARS[fubar2]; $klas = $HTTP_SESSION_VARS[fubar3]; echo $remko; echo $lindeman; echo $klas; ? the problem is that the values don't get registered -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Parsing error
It looks like you've got a closing curly bracket } for your switch
statement, but not for your while statement.
Also, have you read up on the switch statement? Keep in mind that if
something matches your case 1, it will also fall through and execute
case 2, case 3, etc... unless you include break statements. e.g. try
this:
switch ($row)
{
case 1:
{
$vignette = $data[$c];
break;
}
case 2:
{
$photo = $data[$c];
break;
}
...
...
...
-Steve
On Monday, April 1, 2002, at 10:44 AM, news.php.net wrote:
Hi,
I'm real new in php and trying to read a txt file
this is my code :
?php
$row = 1;
$fp = fopen (lecteurs.txt,r);
while ($data = fgetcsv ($fp, 1000, ;))
{
$num = count ($data);
$row++;
for ($c=0; $c$num; $c++)
switch ($row)
{
case 1 :
{
$vignette = $data[$c];
}
case 2 :
{
$photo= $data[$c];
}
case 3 :
{
$marque= $data[$c];
}
case 4 :
{
$nom = $data[$c];
}
case 5 :
{
$pdfproduit= $data[$c];
}
case 6 :
{
$commprod = $data[$c];
}
}
fclose ($fp);
echo $vignette;
echo $photo;
echo $marque;
echo $nom;
echo $pdfproduit;
echo $commprod;
?
and when i run it i get : Parse error: parse error in essai.php on line
45
here' my txt file (just 1 line for probe)
petitimage;photo;marque;Nom;lepdf;commproduit
Can someone help me to go thru
TIA
Hubert
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Re: [PHP] Where is php.ini on Mac OS X?
On mine it's in /usr/local/lib, but I seem to recall discussion earlier about some OSX installations lacking the ini file. -Steve On Tuesday, March 26, 2002, at 04:53 PM, Chuck PUP Payne wrote: Can some one please tell me where php.ini is located on Mac OS X? Thanks, Chuck Payne Magi Design and Support -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Driving me nuts, need one second of your time
It looks like your sql query failed, so the result is invalid.
Assuming that this is really the whole script, then you're counting on
the mysql_db_query function to open a connection to the database db
using the default connection values which (according to the manual) are
host: localhost, user: (whatever user is running the script, probably
'www', 'apache', or 'nobody' depending on your system), and password:
(blank). Do you really have your mysql database setup to allow access
with these defaults?
I'd recommend trying mysql_connect() first, then if that works continue
on to the mysql_query(). At least you'll know better which aspect failed.
-Steve
On Friday, March 15, 2002, at 05:14 PM, cosmin laslau wrote:
?
$query = SELECT * from mytable;
$result = mysql_db_query(db, $query);
while ($myarray = mysql_fetch_array($result))
{
$title = $myarray[title];
echo $titlebr;
}
?
Can someone PLEASE tell me why the coding above gives the following
error:
Warning: Supplied argument is not a valid MySQL result resource in
/var/web/somesite.com/html/index.php on line 5
It's absurd. It's driving me nuts. I'm about to introduce my computer
to the pavement 40 feet below.
Thanks in advance for whoever sees what I am sure is a glaring and
obvious flaw in the coding. I've been looking at it for an hours and
just can't get anything from where I'm standing, maybe a different
perpective will help.
_
Get your FREE download of MSN Explorer at
http://explorer.msn.com/intl.asp.
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Re: [PHP] contents of fetch array into a string
On Wednesday, March 6, 2002, at 12:13 PM, Kris Vose wrote:
I have a problem with reading the contents of $r[1] into a string
called = $mail. Does anyone have any suggestions? Any help is greatly
appreciated.
Kris Vose
if ($czero != )
{
$t = mysql_query(SELECT * FROM AddExisting);
$t is now a resource variable, not an array. If you want to know the
number of rows returned
use mysql_num_rows($t) not count($t)
$number_of_customers = count($t);
while($r = mysql_fetch_array($t))
Note: you'll loop through this section $number_of_customer times,
pulling one table row into $r
each time through.
{
extract($r);
Why are you using extract here?
for ($i = 0; $i$number_of_customers; $i++)
You're looping through $number_of_customers columns on each row in the
table. Is this what you want? Is your table really $number_of_customers
wide?
{
echo $r[1]., ;
Do you mean $r[$i] ?
}
}
Now you've dropped out of both loops. $r will be holding the last row
you retrieved from the database table.
$mail = ' ';
foreach($r[1] as $mailline)
$r[1] is not an array here. What are you trying to do?
{
$mail.=$mailline;
}
}
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Re: [PHP] Perl and PHP
If you're running a perl script on the command line you would use /path/to/perl/script.pl value1 value2 value3 ... In your perl script $ARGV[1] should hold value1, $ARGV[2] should hold value2, etc. -Steve On Wednesday, March 6, 2002, at 02:48 PM, [EMAIL PROTECTED] wrote: I need to pass a variable to Perl from a PHP script. I am somewhat know PHP but I do NOT know perlI am running my perl script off of the command line. I tried /path/to/somewhere/script.pl?var=var but it did not work. I would love any help you could provide me Thanks, Michael -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Perl and PHP
If the value you want to send back to php is an integer you could just say exit $number; from perl and that will be put into your $var. Otherwise use exec() instead of system. exec(/path/to/perlscript.pl, $scriptOutputArray, $scriptExitValue); Anything that gets printed from the perl script should show up in the $scriptOuputArray. -Steve On Wednesday, March 6, 2002, at 04:19 PM, Michael Hess wrote: Thanks, Ok, I got it to work.now how do I take a varaible back into PHP I do a $var = system(/path/to/cgi $varforCGI) and in the CGI script I do a print $varforPHP however it prints the varforPHP to the broswer, I need it saved it var Any (more) help would be great!! Michael On Wed, 6 Mar 2002, Steve Cayford wrote: If you're running a perl script on the command line you would use /path/to/perl/script.pl value1 value2 value3 ... In your perl script $ARGV[1] should hold value1, $ARGV[2] should hold value2, etc. -Steve On Wednesday, March 6, 2002, at 02:48 PM, [EMAIL PROTECTED] wrote: I need to pass a variable to Perl from a PHP script. I am somewhat know PHP but I do NOT know perlI am running my perl script off of the command line. I tried /path/to/somewhere/script.pl?var=var but it did not work. I would love any help you could provide me Thanks, Michael -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Is there Any way to call Non-Existent function in PHP
You could wrap your function calls, maybe. Like
function my_Draw_Image() {
if(function_exists('Draw_Image')) {
return Draw_Image(func_get_args());
} else {
// do whatever...
}
}
Haven't tested this at all, but it seems plausible. Might be possible to
wrap generic function calls like this using call_user_func() or eval().
Again, I haven't tested it.
-Steve
On Thursday, January 17, 2002, at 12:07 AM, S. Murali Krishna wrote:
Hi!
Thanks for your kind response. The solution given by u is fine.
But Iam asking just more than that. See whenever I call a function
like
Draw_Image();
( In language construct level )
Is there anything to checks this non-existence of Draw_Image() and call
some default function.
I don't want to manually check if it exist or not.
Thanks for Ur Solution.
On Wed, 16 Jan 2002, Neil Freeman wrote:
You can use function_exists() to check whether a function actually
exists:
eg:
if (function_exists('imap_open')) {
echo IMAP functions are available.br\n;
} else {
echo IMAP functions are not available.br\n;
}
HTH
Neil
S. Murali Krishna wrote:
Hai ALL
Is there any way to capture function call in PHP
and redirect to some other function if that function doesn't exists.
Perl programmers remind AUTOLOAD method in a package.
S.Murali Krishna
[EMAIL PROTECTED]
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- E. Stanley Jones
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Re: [PHP] variable variables
On Thursday, January 17, 2002, at 10:11 AM, Mike Krisher wrote:
I can not wrap my head around variable variables today, not awake yet or
something.
For instance I trying something like this:
while ($i$loopcounter) {
$temp = size;
$valueofsize = $$temp$i;
try $valueofsize = ${$temp$i};
$i++;
}
this doesn't work obviously, $valueofsize ends up with a literal value
of
$size1. But I need it to equal the value of a variable named $size1.
Do I
need to use a eval() or something?
Thanks in advance,
» Michael Krisher
[EMAIL PROTECTED]
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Re: [PHP] Error
On Tuesday, January 8, 2002, at 09:37 AM, Dean Ouellette wrote:
Hi I am learning php with Sams leanr php in 24 hours.
This is one example
?php
function addNums($firstnum, $secondnum)
{
$result = $firstnum + $secondnum;
return $result;11: } // this is line 13
that should be:
return $result; }
what's the 11: doing in there?
-Steve
print addNums (3,5);
?
When I run it get error line 13
any ideas?
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Re: [PHP] counting with dates (help!)
Well, I'll chime in as well. I'd recommend doing all your calculations
in timestamps in seconds, then convert the results into days, dates, or
whatever. If you only have a date to start with then convert to a
timestamp, do the calculation, and convert back. You could wrap it in a
function like this:
?php
function dateDiffInDays($date1,$date2) {
$date1Tm = strtotime($date1);
$date2Tm = strtotime($date2);
$diff = abs($date1Tm - $date2Tm) / 86400;
return $diff;
}
$today = date(Ymd,mktime(0,0,0, date(m), date(d), date(Y)));
$last_week = date(Ymd, mktime(0,0,0, date(m), date(d)-7,
date(Y)));
print(today: $today br\n);
print(last_week: $last_week br\n);
print(diff in days: . dateDiffInDays($last_week, $today) . br\n);
?
On Thursday, February 7, 2002, at 04:21 PM, Sander Peters wrote:
Hello,
This is my problem:
$today = date(Ymd, mktime(0,0,0, date(m),date(d),date(Y)));
$last_week = date(Ymd, mktime(0,0,0, date(m),date(d)-7,date(Y)));
echo ($today - $last_week);
The result is a number like 8876 (20020107-20011231 = 8876)
But in date thinking it should be 7!
How can I let php count in real days/month/years in stead of numbers?
Maybe this is a silly question, but anyone who has the answer would help
me very much!
Thanks in advance!
--
Met vriendelijke groet / With Greetings,
Sander Peters
site: http://www.visionnet.nl/
email: mailto:[EMAIL PROTECTED]
webmail: mailto:[EMAIL PROTECTED]
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Re: [PHP] PHP Doesn't Crash but show blank page
Two other lines to look for in your php.ini file:
display_errors = On
log_errors = Off
If display_errors is on the error will be displayed on the web page, if
log_errors is on the error will be logged--assuming you're using Linux
check /var/log/messages, but you can change this with the
error_log = ... option.
-Steve
On Wednesday, January 2, 2002, at 05:11 AM, [@-!-%] wrote:
Hello everyone!
I'm having issues with my php pages. When I have errors, Instead of
crashing or showing errors, the browser shows a blank page.
For example, if I leave the left bracket in my if statement, like
if(blah blah)
---missing left bracket '{'
do this
}else {
do that
}
or, I leave the semiconlon at the end of a line, like
$myvar= this is my line -- missing ';'
PHP does not report the error.
My php.ini is configured as
error_reporting =
E_COMPILE_ERROR|E_ERROR|E_CORE_ERROR|E_USER_ERROR|E_USER_WARNING|E_USER_NOTICE
My system has
PHP 4.0.6, MySQL 3.23.46-nt, Win2000
Anyone knows why it's doing that?
-john
__John Monfort_
_+---+_
P E P I E D E S I G N S
www.pepiedesigns.com
The world is waiting, are you ready?
-+___+-
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Re: [PHP] Regular Expression
You can do as Jim says here or go back and read the manual section again
for eregi and ereg. What you're trying to do should be written more like
this:
?php
$str = 'body bgcolor=#ff';
$numMatches = eregi('(body)(.*)()',$str,$results);
print(numMatches: $numMatches br\n);
print(body contents: $results[2] br\n);
print(all results: );
print_r($results);
?
-Steve
On Thursday, January 3, 2002, at 12:15 PM, Jim Lucas [php] wrote:
I have seen this question reposted for the past week. now why don't you
just work with the entire thing.
get the body ...
now once you have that, do this
$str = preg_replace(body, , $str)
$str = preg_replace(, , $str)
now your $str var will only have the properties.
Jim
- Original Message -
From: [-^-!-%- [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, January 02, 2002 12:45 PM
Subject: [PHP] Regular Expression
Hello everyone!
I'm trying to get the text inside the BODY tag, using regular
expression.
$area = eregi('(body)(.*))',$str);
Where $str is the string containing
body bgcolor=#99 tex=#... ...
When I print $area, the string contains the entire content of $str. I
get something like:
body ...
p
.
.
.
/body
/html
__John Monfort_
_+---+_
P E P I E D E S I G N S
www.pepiedesigns.com
The world is waiting, are you ready?
-+___+-
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Re: [PHP] Error while calling a function
I don't know all the details about how PHP compiles a program, but
having your function definitions in an if-else statement that may not be
executed looks suspicious to me.
You've got
if(!$Phone)
{
do something
}
else
{
function is_phone() { ...blah, blah...}
}
is_phone($Phone);
If you don't hit the else block, your is_phone function is probably not
defined.
-Steve
On Tuesday, December 18, 2001, at 07:26 AM, J.F.Kishor wrote:
hi all,
I have got a problem, when I execute the following script it gives
a Fatal error, could any one tell me why is it ?, If this is a silly
problem please execuse me but, plz do reply me.
The script is
-
html
body
?
if(!$Phone)
{
?
form action=?echo $PHP_SELF? method=post
br
Telephone Number : input type=text name=Phone value=
br
input type=submit
script language=php
}
else
{
function is_allnumbers ($text)
{
if( (gettype($text)) == integer)
{
print the value is an integer;
return true;
}
$Bad = $this-strip_numbers($text);
if(empty($Bad))
{
print the value is empty;
return true;
}
return false;
}
function clear_error ()
{
$this-ERROR = this is an error;
}
function is_phone ($Phone =)
{
if($this-CLEAR)
{
$this-clear_error();
}
if(empty($Phone))
{
$this-ERROR = is_phone: No Phone number
submitted;
return false;
}
$Num = $Phone;
$Num = $this-strip_space($Num);
$Num = eregi_replace((\(|\)|\-|\+),,$Num);
if(!$this-is_allnumbers($Num))
{
$this-ERROR = is_phone: bad data in phone
number;
return false;
}
if ( (strlen($Num)) 7)
{
print the number is less then 7;
$this-ERROR = is_phone: number is too short
[$Num][$Phone];
return false;
}
if( (strlen($Num)) 13)
{
print the number is then 13;
$this-ERROR = is_phone: number is too long
[$Num][$Phone];
return false;
}
return true;
}
}
$result = is_phone($Phone);
if($result == true)
{
echo success;
}
else
{
echo failure;
}
/script
/body
/html
The error is
Fatal error: Call to undefined function: is_phone() in
/home/kuruvi1/kishor/public_html/IMS/ADMIN/test/is_phone.php on line 87
Thanks for your tolerance,
- JFK
kishor
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[PHP] Class methods and inheritance...
Hi. Is there a way to find the class name of a method when called in the class::method() format? If called on an object (eg. object-method()) I could just ask for get_class($this), but when called as class::method(), $this should not be defined. Anyway around this? Thanks. -Steve -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Date formatting
On Monday, December 10, 2001, at 09:35 PM, phantom wrote:
What would be an easy what to format a date value into month day year??
I want to specially display a date stored in mysql in date format
-MM-DD
The manual says: string date (string format, int [timestamp])
I tried $FormattedDate = date(F y, Y,${StoredDate})
try $FormattedDate = date(F y, Y,strtotime($StoredDate));
strtotime will convert your -MM-DD string into a unix timestamp.
1999-04-15 spit out December 31, 1969 when I had hoped for April 15,
1999.
Apparently -MM-DD is not a valid timestamp... i tried mysql formats
of timestamp(8) and timestamp(14) and that didn't work either
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Re: [PHP] Finding num of days b/t two dates.
Here's one way to do it by converting dates into timestamps. ?php $date1 = mktime(0,0,0,10,1,2001); // in the form (hours, minutes, seconds, month, day, year) $date2 = mktime(0,0,0,10,1,2000); $timedif = $date1 - $date2; print(strftime(date 1 is %b %d, %Y, $date1) . br\n); print(strftime(date 2 is %b %d, %Y, $date2) . br\n); print(the difference in seconds is . $timedif . br\n); print(the difference in days is . ($timedif / (60 * 60 * 24)) . br\n); ? -Steve On Friday, December 7, 2001, at 04:48 PM, Alex Fritz wrote: If somebody could help me with this, it would save me a lot of heartache. I thought that this would be simple, but I can't seem to find a function anywhere in PHP that has this capability and I can't seem to find any external libraries for anything actually. I need to be able to give PHP a start date and an end date and have it return the number of days between the dates. If the first date is more recent than the second, I need it to give me a negative number. Can somebody please help? Alex -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Display BLOB Image
This is what I used to do what you're trying:
header(Content-Type: image/ . $imagetype); // $imagetype is jpeg or gif
header(Content-Length: . strlen($image));
echo $image;
Note that Type is capitalized in Content-Type, and include the
Content-Length as well.
-Steve
On Thursday, December 6, 2001, at 02:45 PM, phantom wrote:
I have successfully placed images (jpg,gif,png) into a MySQL database
BLOB field, now I want to be able to pull the data out and diplay it.
based on tutorial at
http://www.zdnet.com/devhead/stories/articles/0,4413,2644827,00.html
after Querying the DB I have the following lines:
$ImgFile = mysql_result($Results,0,ImgFile); \\ image data;
$ImgType = mysql_result($Results,0,ImgType); \\ image type (image/jpeg,
image/gif);
header(Content-type: ${ImgType});
echo $ImgFile;
Problem: This method, when it pulls up an image, it shows no image but a
bunch of greek code. Example
http://www.phantomcougar.com/strawberrypie_com/mem/show_img.php?PNum=8
((be sure to view page source)
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Re: [PHP] Why are slashes automatically stripped from db result?
On Monday, December 3, 2001, at 06:16 PM, Tyler Longren wrote: I believe you're correct Martin. I think newer versions of MySQL automatically strip them out. Just use php's stripslashes() and addslashes() functions when you need them. Interesting. A bit unnerving at first, though. Thanks. -Steve Good luck Steve, Tyler Longren - Original Message - From: Martin Towell [EMAIL PROTECTED] To: 'Steve Cayford' [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Monday, December 03, 2001 6:04 PM Subject: RE: [PHP] Why are slashes automatically stripped from db result? maybe mysql is stripping the slashes and not php ?? -Original Message- From: Steve Cayford [mailto:[EMAIL PROTECTED]] Sent: Tuesday, December 04, 2001 10:57 AM To: [EMAIL PROTECTED] Subject: [PHP] Why are slashes automatically stripped from db result? Hey all. I'm storing some jpeg images in a mysql database using the PEAR classes. Before inserting the image into the db I call addslashes() on the data, I was, accordingly, calling stripslashes() on the data after pulling the image back out of the database, but the image was getting mangled. I finally realized that the slashes were already stripped from my query results so stripping them again was removing legitimate slashes. The question is: why are the slashes already stripped out of the db results? I call set_magic_quotes_runtime(0) at the beginning of the scripts to turn off magic quoting. What else would cause this? Thanks for any suggestions. -Steve -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: php-list- [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] 'Running' a file from PHP script
On Tuesday, December 4, 2001, at 02:22 AM, George Pitcher wrote: Hi all, I'm a PHP newbie, my main scipring being done in Blueworld's Lasso. I have used php fro time to time with Lasso to do some file handling. My question is: 'Can I run a file from a PHP script?' The file in question would be a Filemaker database file. I want to be able to open the file in the Filemaker application if the file is not already running. If you mean can you open the Filemaker application on the client's machine using PHP, then no. Keep in mind that PHP is only running on the server(*), all the client machine sees is the HTML output from your PHP script. Maybe you could use javascript to do this, but I haven't used javascript much. -Steve (*) Assuming you're using PHP in its normal web-server scripting mode. MTIA George in Edinburgh _ Do You Yahoo!? Get your free @yahoo.com address at http://mail.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Cannot use a scalar value as an array
On Tuesday, December 4, 2001, at 06:04 AM, Xavier Antoviaque wrote:
Hello all,
I have a problem with a php script, which I want to use to fetch two
data
(integer) from a MySQL table, divide the first by the second, and store
the
value resulting in an double array. That seems not very difficult, but I
always have the error 'Cannot use a scalar value as an array' when I
use my
script.
Here it is :
$result = mysql_query(SELECT timestamp_c,connectes,num FROM
stats_serveurs WHERE timestamp_c LIKE '.$date.%' AND serveur='.
$serveur.', $link);
$max = 0;
$reps = mysql_num_rows($result);
for($i = 1; $i=$reps; $i++){
$row = mysql_fetch_row($result);
$serveur[$i]['heure'] = $row[0];
$serveur[$i]['connectes'] = (int) ($row[1] / $row[2]); // Error!
$max = max($max, $serveur[$i]['connectes']);
}
How does the operator precedence work in the statement ($row[1] /
$row[2]) ? You might try (($row[1]) / ($row[2])) instead, or pull those
into scalar variables before trying the division.
-Steve
Any help is welcome ! :-)
--
Xavier.
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Re: [PHP] 'Running' a file from PHP script
Ah, well, can't help you there, sorry. -Steve On Tuesday, December 4, 2001, at 09:40 AM, George Pitcher wrote: Steve, Thanks for the response, but it's a server-side 'run' I'm looking for, not client-side (they get web access to the db). Basically I want to be able to test that the db is running and if it isn't then I want to 'run' it. Platform is NT, server is IIS4 George - Original Message - From: Steve Cayford [EMAIL PROTECTED] To: George Pitcher [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Tuesday, December 04, 2001 3:39 PM Subject: Re: [PHP] 'Running' a file from PHP script On Tuesday, December 4, 2001, at 02:22 AM, George Pitcher wrote: Hi all, I'm a PHP newbie, my main scipring being done in Blueworld's Lasso. I have used php fro time to time with Lasso to do some file handling. My question is: 'Can I run a file from a PHP script?' The file in question would be a Filemaker database file. I want to be able to open the file in the Filemaker application if the file is not already running. If you mean can you open the Filemaker application on the client's machine using PHP, then no. Keep in mind that PHP is only running on the server(*), all the client machine sees is the HTML output from your PHP script. Maybe you could use javascript to do this, but I haven't used javascript much. -Steve (*) Assuming you're using PHP in its normal web-server scripting mode. MTIA George in Edinburgh _ Do You Yahoo!? Get your free @yahoo.com address at http://mail.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: php-list- [EMAIL PROTECTED] _ Do You Yahoo!? Get your free @yahoo.com address at http://mail.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] Why are slashes automatically stripped from db result?
Hey all. I'm storing some jpeg images in a mysql database using the PEAR classes. Before inserting the image into the db I call addslashes() on the data, I was, accordingly, calling stripslashes() on the data after pulling the image back out of the database, but the image was getting mangled. I finally realized that the slashes were already stripped from my query results so stripping them again was removing legitimate slashes. The question is: why are the slashes already stripped out of the db results? I call set_magic_quotes_runtime(0) at the beginning of the scripts to turn off magic quoting. What else would cause this? Thanks for any suggestions. -Steve -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] query works in mysql, but not from php
You don't need to put in the final semi-colon when running a query from php. Take that out and you should be fine. -Steve On Monday, November 19, 2001, at 04:58 PM, Olav Drageset wrote: Hi $sql = SELECT user FROM persons WHERE user = '$firstName' and domain = '$domainName' ; ; $result = mysql_query($sql,$connection ) or die(mysql_error()); Calling above lines from php returns: You have an error in SQL syntax near ';' at line 1 Issuing the command SELECT user FROM persons WHERE user = 'fred' AND domain = 'company.net' ; in mysql give a proper result. Can anyone explain what might be causing the error??? regards Olav -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Anyone ever done this - sort a multi-dimensional array
You can roll your own fairly easily:
function mycmp($a,$b) {
return strcmp($a[1],$b[1]);
}
usort($array, 'mycmp');
...something like that at any rate.
-Steve
On Thursday, November 15, 2001, at 10:07 AM, Richard S. Crawford wrote:
Of the type...
$array[0][0] = !row of c's;
$array[0][1] = ;
$array[1][0] = row of a's;
$array[1][1] = ;
$array[2][0] = a row of b's;
$array[2][1] = ;
such that you sort on the value of the y-column?
In this case, it would end up as:
+--+--+
| row of a's | |
| a row of b's | |
| !row of c's | |
+--+--+
Strange that I've been working with PHP this long and have never come
across this problem.
Sliante,
Richard S. Crawford
http://www.mossroot.com
mailto:[EMAIL PROTECTED]
AIM: Buffalo2K ICQ: 11646404 Y!: rscrawford
It is only with the heart that we see rightly; what is essential is
invisible to the eye. --Antoine de Saint Exupéry
Push the button, Max!
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Re: [PHP] very weird PHP behaviour...
Sure sounds like you're hitting this function twice by accident. Are you
sure you're only calling it once? That would explain why you only get
one output with the die(), but two without it.
-Steve
On Wednesday, November 14, 2001, at 10:34 AM, Christian Dechery wrote:
I don't know what it is... but PHP is acting very weird today... or I
am becoming crazy... can anyone tell me which one?
I have this function:
function
Upload($source_file,$source_filename,$dest_dir,$allowed_types=array())
{
global $upload_errmsg;
if( count($allowed_types) )
{
$file_ext=ArquivoExt($source_filename);
$ext_found=in_array($file_ext,$allowed_types);
//die(source=$source_filename);
//var_dump($ext_found);
//die;
if( !$ext_found )
{
$upload_errmsg=O arquivo \$source_filename\ não está entre os
tipos autorizados;
//die(errmsg=$upload_errmsg);
return false;
}
}
... some more code here ..
return true;
}
the first crazy behaviour is... I use a test file called something.jpg,
ArquivoExt() returns me the extension of a given filename, in this case
jpg. $allowed_types contains gif,jpg and png so that in_array()
should return true... and it does... but get this... if I uncomment
that var_dump() guess what it outputs?
bool(true) bool(false)
very weird... how can one var_dump() call gives me two outputs?
This double output doesn't occur if I uncomment the die after the
var_dump(). It only outputs bool(true) in that case.
Now for the second weird behaviour... since no matter what, $ext_found
will always be false (due to the previous weirdness) it will always
enter the IF... but the weird thing is when the caller of Upload()
prints $upload_errmsg it only outputs:
O arquivo não está entre os tipos autorizados
where is the filename? I've checked it tons of times... If I uncomment
the second die, right after the $upload_errmsg assignment, it outputs
ok, with the filename.
Now, can someone explain me this VERY WEIRD behaviour??
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Re: [PHP] Sessions Header PROBLEM again!
Don't know offhand what the problem is, but a couple thoughts:
1. Why are you using session_name(mysession) instead of
session_name('mysession')?
2. Assuming you have register_globals on, you're trying to pass $count
both as a session variable and a post variable. One of these is going to
get overwritten by the other if I'm not mistaken.
3. Why not have the page 1 form action point directly at page 2 instead
of being redirected through page 1? Do posted variables follow a
redirect?
4. If posted variables do follow a redirect then page 1 will see that
$submit is set and redirect to page 2, which will redirect to page 3,
which will redirect to page 1, etc... Can you get an infinite
redirection loop?
5. The form on page 1 includes a hidden count variable, page 2 and page
3 don't.
What happens when you run this?
-Steve
On Friday, November 2, 2001, at 08:49 AM, Alessandro BOSSI wrote:
Why in these 3 linked page the var count
does not go through the page if I have the browser sessions disabled???
Where is the mistake?
I see the session_id, changing at every page!
Someone can help me?
Many thank
Alessandro Bossi
-
?php /* First.php */
session_name(mysession);
session_start();
session_register (count);
if (isset($submit)){
header(Location: Seconda.php?.SID);
}else{
$count++;
}
print session_encode= .session_encode().BR;
?
!DOCTYPE HTML PUBLIC -//W3C//DTD HTML 4.0 Transitional//EN
HTMLHEADTITLE First Page/TITLE/HEAD
BODY BGCOLOR=#A2BBAF
H4First Page/H4
Hello visitor, you have seen this page ?=$count; ? times.p
count = ?= $HTTP_SESSION_VARS[count] ?BR
P
FORM METHOD=POST ACTION=?= $PHP_SELF ?
INPUT TYPE=hidden NAME=count value=?=$count?
INPUT TYPE=submit name=submit value=Go to the SECOND page
/FORM
/BODY/HTML
-
?php /* Second.php */
session_name(mysession);
session_start();
session_register('count');
if (isset($submit)){
header(Location: Third.php?.SID);
}
print session_encode= .session_encode().BR;
?
!DOCTYPE HTML PUBLIC -//W3C//DTD HTML 4.0 Transitional//EN
HTMLHEADTITLESecond Page/TITLE/HEAD
BODY BGCOLOR=#A2BBAF
H4Second Page/H4
Hello visitor, you have seen this page ?=$count; ? times.p
count = ?= $HTTP_SESSION_VARS[count] ?
P
FORM METHOD=POST ACTION=?= $PHP_SELF ?
INPUT TYPE=submit name=submit value=Go to the THIRD Page
/FORM
/BODY
/HTML
-
?php /* Third.php */
session_name(mysession);
session_start();
session_register (count);
if (isset($submit)){
header(Location: First.php?.SID);
}
print session_encode= .session_encode().BR;
?
!DOCTYPE HTML PUBLIC -//W3C//DTD HTML 4.0 Transitional//EN
HTML
HEAD
TITLEThird Page/TITLE
/HEAD
BODY BGCOLOR=#A2BBAF
H4Third Page/H4
Hello visitor, you have seen this page ?=$count; ? times.p
Count = ?= $HTTP_SESSION_VARS[count] ?
P
FORM METHOD=POST ACTION=?= $PHP_SELF ?
INPUT TYPE=submit name=submit value=Go to the FIRST Page
/FORM
/BODY
/HTML
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Re: [PHP] Re: header(Location:);
On Tuesday, October 30, 2001, at 11:41 AM, Henrik Hansen wrote:
[EMAIL PROTECTED] (Alberto) wrote:
Ok, it works fine for me, i can redirection, but I don't want the
browser to
load another page, I want to IF A THEN RUN A.PHP, IF B THEN RUN
B.PHP, I
know i can use include('a.php') or require('a.php') but I'm sure
theres a
way to say php parser to run one or another script without changing
URL to
the client.
use include as you say or html frames.
Yeah, why not
if($A) {
include('a.php');
} elseif ($B) {
include('b.php');
}
--
Henrik Hansen
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[PHP] Confused object in session variable.
Well, it's probably me that's confused. I have an authenticate()
function which should start a session and if the user is not logged in
then show the login screen otherwise return after storing and
registering a user object in a session variable. This object has
accessor methods to get the login name, access level, etc... This seems
to work okay--within the authenticate function I can access the object
in the HTTP_SESSION_VARS array. But as soon as I return to the main
script it's gone. I must be doing something wrong with the scoping, but
I can't see what. Any thoughts? Here's the code:
?php
/* - */
/* index.php */
/* - */
require_once('ucautho/ucautho.inc');
authenticate();
print(From index testUser: . $testUser-getLogin() . br\n);
print(From index HTTP_SESSION_VARS['ucAuthoUser']: );
print($HTTP_SESSION_VARS['ucAuthoUser']-getLogin() . br\n); //this
is line 12
?
?php
/* --- */
/* ucautho/ucautho.inc */
/* --- */
function authenticate($appName=) {
global $HTTP_SESSION_VARS, $HTTP_POST_VARS;
global $testUser;
session_name(UCAutho);
session_start();
if (isset($HTTP_SESSION_VARS['ucAuthoUser'])
$HTTP_SESSION_VARS['ucAuthoUser']-isValid()) {
return;
} else {
if (isset($HTTP_POST_VARS['authoSubmit'])) {
$HTTP_SESSION_VARS['ucAuthoUser'] =
new
UcAuthoUser($HTTP_POST_VARS['authoLogin'],$HTTP_POST_VARS['authoPword']);
if ($HTTP_SESSION_VARS['ucAuthoUser']-isValid()) {
session_register('ucAuthoUser');
$testUser = $HTTP_SESSION_VARS['ucAuthoUser'];
print(From authenticate testUser: .
$testUser-getLogin() . br\n);
print(From authenticate
HTTP_SESSION_VARS['ucAuthoUser']: );
print($HTTP_SESSION_VARS['ucAuthoUser']-getLogin() .
br\n);
return;
}
}
showLogin($appName);
}
}
/* more functions and the class declaration snipped */
?
Here's what I get when I login as 'steve' with a good password:
From authenticate testUser: steve
From authenticate HTTP_SESSION_VARS['ucAuthoUser']: steve
From index testUser: steve
From index HTTP_SESSION_VARS['ucAuthoUser']:
Fatal error: Call to a member function on a non-object in
/home/httpd/html/ucdamage/index.php on line 12
Note the testUser works in both instances, the session var only works
inside the function.
-Steve
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Re: [PHP] Confused object in session variable.
An update...
I had register_globals turned off. Now that I've turned register_globals
on and changed my references from $HTTP_SESSION_VARS['ucAuthoUser'] to
$ucAuthoUser it works as I expect.
I'm not real happy with having register_globals on, though, and I'd like
to figure out what I was doing wrong.
Thanks for any suggestions.
-Steve
On Thursday, October 25, 2001, at 12:07 PM, Steve Cayford wrote:
Well, it's probably me that's confused. I have an authenticate()
function which should start a session and if the user is not logged in
then show the login screen otherwise return after storing and
registering a user object in a session variable. This object has
accessor methods to get the login name, access level, etc... This seems
to work okay--within the authenticate function I can access the object
in the HTTP_SESSION_VARS array. But as soon as I return to the main
script it's gone. I must be doing something wrong with the scoping, but
I can't see what. Any thoughts? Here's the code:
?php
/* - */
/* index.php */
/* - */
require_once('ucautho/ucautho.inc');
authenticate();
print(From index testUser: . $testUser-getLogin() . br\n);
print(From index HTTP_SESSION_VARS['ucAuthoUser']: );
print($HTTP_SESSION_VARS['ucAuthoUser']-getLogin() . br\n); //this
is line 12
?
?php
/* --- */
/* ucautho/ucautho.inc */
/* --- */
function authenticate($appName=) {
global $HTTP_SESSION_VARS, $HTTP_POST_VARS;
global $testUser;
session_name(UCAutho);
session_start();
if (isset($HTTP_SESSION_VARS['ucAuthoUser'])
$HTTP_SESSION_VARS['ucAuthoUser']-isValid()) {
return;
} else {
if (isset($HTTP_POST_VARS['authoSubmit'])) {
$HTTP_SESSION_VARS['ucAuthoUser'] =
new
UcAuthoUser($HTTP_POST_VARS['authoLogin'],$HTTP_POST_VARS['authoPword']);
if ($HTTP_SESSION_VARS['ucAuthoUser']-isValid()) {
session_register('ucAuthoUser');
$testUser = $HTTP_SESSION_VARS['ucAuthoUser'];
print(From authenticate testUser: .
$testUser-getLogin() . br\n);
print(From authenticate
HTTP_SESSION_VARS['ucAuthoUser']: );
print($HTTP_SESSION_VARS['ucAuthoUser']-getLogin() .
br\n);
return;
}
}
showLogin($appName);
}
}
/* more functions and the class declaration snipped */
?
Here's what I get when I login as 'steve' with a good password:
From authenticate testUser: steve
From authenticate HTTP_SESSION_VARS['ucAuthoUser']: steve
From index testUser: steve
From index HTTP_SESSION_VARS['ucAuthoUser']:
Fatal error: Call to a member function on a non-object in
/home/httpd/html/ucdamage/index.php on line 12
Note the testUser works in both instances, the session var only works
inside the function.
-Steve
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Re: [PHP] function names
On Thursday, October 25, 2001, at 02:08 PM, Martín Marqués wrote:
On Jue 25 Oct 2001 15:36, you wrote:
Hello php-general,
I have such code:
class A
{
var $xxx;
function print()
{
echo $xxx;
$xxx is internal to the print function. Instead you need $this-xxx
which
will give you the value of the $xxx of the A class.
}
}
And that's what I get:
Parse error: parse error, expecting `T_STRING' in xxx.php on line
nn
Php doesn't let any function or class member have a name which is
already used by another function (or only function from library),
am I right? Or maybe print has special status. Maybe that's
because print() is actually not a function? Can anyone tell me
something about that, please?
Th print function of PHP has nothing to do with this, just because
print is
internal to the A class, and has nothing with the PHPs internal print
function.
Hmm. I think you're wrong here. I made this test script:
?php
class test {
var $a;
function test() {
$this-a = hello;
}
function print() { // this is line 10
echo $this-a;
}
}
$obj = new test;
$obj-print();
?
Which gives this:
Parse error: parse error, expecting `T_STRING' in
/home/httpd/html/ucdamage/test.php on line 10
If I change the name of the print() method it works okay.
-Steve
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Re: [PHP] Setting A MySQL Column to NO DUPLICATES
I think you want UNIQUE. create table sometable ( somecolumn char(40), someothercolum int, unique somecolumn ) ...something like that. I haven't messed with it much. -Steve On Thursday, October 25, 2001, at 04:31 PM, Jeff Gannaway wrote: Does anyone know how to set a column in a MySQL table to disallow any duplicate entries. I've already got a PRIMARY KEY defined for this table. I tried setting the other field to a MUL KEY, hoping that it would not permit duplicates, but it does. I've searched the MySQL docs without success. I wish their site was a good as PHP.net. Later, Jeff Ganaway ___ Save 15% on 2002 Calendars and Holiday Cards! http://www.AvantGifts.com Discount Code: hopper22ct Offer Good Through October 31, 2001 ___ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Re: require include
So both include() and require() *are* subject to conditional statements
in the code? Guess I missed that.
Thanks.
-Steve
On Tuesday, October 23, 2001, at 01:00 AM, Rasmus Lerdorf wrote:
That's outdated. The only difference today is that if a file can't be
included/required for some reason it is a fatal error with require and a
warning with include.
-Rasmus
On Tue, 23 Oct 2001, Jason G. wrote:
From the manual:
Unlike include(), require() will always read in the target file, even
if
the line it's on never executes. If you want to conditionally include a
file, use include(). The conditional statement won't affect the
require().
However, if the line on which the require() occurs is not executed,
neither
will any of the code in the target file be executed.
Similarly, looping structures do not affect the behaviour of require().
Although the code contained in the target file is still subject to the
loop, the require() itself happens only once.
At 08:48 AM 10/23/2001 +0900, Yasuo Ohgaki wrote:
Jtjohnston wrote:
Coverting from perl ...
What's the differencw between require and include? Where, when, why?
I forgot from which version, but current PHP's require/include works
the
same way except
- require() raise fatal error, if it can't find file
- include() raise warning, if it can't find file
requrie_once()/include_once() works almost the same as
require()/include()
except they include file only once. (Hash table is used to determine
if
files are included or not)
See also get_{required|included}_files()
--
Yasuo Ohgaki
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Re: [PHP] require include
http://www.php.net/manual/en/function.require.php require() pulls in the target file when the source file is parsed/compiled, include() pulls in the target file when the source file is executed. So an include() nested in an if statement will only be included if the if statement evaluates to true, a require() nested in an if statement will be included regardless. Also check out include_once() and require_once(). -Steve On Monday, October 22, 2001, at 05:15 PM, jtjohnston wrote: Coverting from perl ... What's the differencw between require and include? Where, when, why? John? Email post reply always appreciated -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Array Elements While Loops
Where is the closing brace for your while loop?
-Steve
On Monday, October 1, 2001, at 07:04 AM, Tom Churm wrote:
hi,
my problem is this: i'm using a while loop to check elements in an
Array for valid email syntax. if $User[0] is a valid email address but
$User[1] is not, the code for $User[0] is still executed before the die
statement. i need my loop to finish checking ALL array elements for
validity, and to then die BEFORE any further code is executed. here's
what i have now (it doesn't work):
//loop to check for bad email addresses:
$j = 0;
$flag = 0;
while ($j count($User)){
if
(($User[$j]!=)!eregi(^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-
z0-9-]+(\.[a-z0-9-]+)*$,
$User[$j]))
{
$flag = 1;
$errorNo = $j + 1;
}
//die if flag is 1
if ($flag = 1) {
die (p align='center'bEmail #$errorNo is not a valid e-mail
address!/bbrbrbra
href='javascript:window.history.back();'Please return and correct
this./a/p);
}
else {
continue...
}
any suggestions would be great!
thanks much,
tom
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Re: [PHP] Getting my head around nulls
On Wednesday, September 26, 2001, at 02:48 AM, [EMAIL PROTECTED] wrote: Steve Cayford [EMAIL PROTECTED] on 25/09/2001 17:28:57 To: [EMAIL PROTECTED] cc: [EMAIL PROTECTED], [EMAIL PROTECTED] Subject: Re: [PHP] Getting my head around nulls On Tuesday, September 25, 2001, at 10:30 AM, [EMAIL PROTECTED] wrote: Just had a look at manual, ifnull() seems close to useless. However if they had NVL(), as Oracle douse NVL( column|litrel, '*null*' ) This takes a column or literal as its first arg and if arg is null returns 2nd arg otherwise returns arg. In other words if the column is null it is replaces by arg2 otherwise it is simply returned. Um, that's what ifnull() does. At least it works for me. -Steve Verry true, sorry, was looking at nullif. Also noticed the if function, can this have more than three parameters. i.e if ( col, 'A', 'Accept', 'C', 'Complete', 'Unknown' ) like Oracle decode. and if elseif else structure. Neb Looks like you want the CASE statement. I haven't used it but it looks pretty much like what you're asking. CASE value WHEN [compare-value] THEN result [WHEN [compare-value] THEN result ...] [ELSE result] END Guess this discussion should really be on php-db :) -Steve -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] Extract. Was Re: Feature?
Just looking up that extract function, the manual says it extracts into
the current symbol table. I assume that means that within foo() the
array would be extracted into local variables. Is that right?
-Steve
On Wednesday, September 26, 2001, at 06:50 AM, Alister wrote:
Follow up to my own message:
If you want to also skip even needing the empty 'array()' (new fianl
example) - check if it is an array, and only do the first extract of
the parameters if there's something there.
?php
function foo($p='')
{
$foodefault = array(
'foo_fred'= 'strongdefault fred/strong',
'foo_banana' = 'strongdefault bananananana/strong',
);
if (is_array($p))
extract ($p, EXTR_PREFIX_ALL, 'foo'); // get values
extract ($foodefault, EXTR_SKIP, foo);// get defaults
echo $foo_fred / $foo_banana;
}
echo Both in place: ;
foo(array('fred' = 'hello', 'banana' = 'world'));
echo br / Now with a missing param: ;
foo(array('fred' = 'hello'));
echo br / Now both missing params: ;
foo(array());
echo br / and with no array: ;
foo();
?
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Re: [PHP] Building Dynamic Value list using ohp
Also look for missing semicolons and unclosed braces in the lines above
22.
-Steve
On Wednesday, September 26, 2001, at 09:19 AM, Derek Mailer wrote:
oops...I was going to add...
2) -
$result = mysql_query($query, $mysql_link);
doesn't require the $mysql_link argument, try
$result = mysql_query($query);
Another general comment is that you have copied a bit of your code that
seems to include the root password to mysql. Not a good idea - you
should
check and edit your code if necessary before posting.
Hope this helps - good luck
Derek
- Original Message -
From: George Pitcher [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Wednesday, September 26, 2001 2:54 PM
Subject: Re: [PHP] Building Dynamic Value list using ohp
Thanks Gottfried, but that doesn't change the response I get.
Any more suggestions.
George P in Edinburgh
PS I am hoping to come over to Frankfurt for the conference in November
(boss might pay)
- Original Message -
From: [EMAIL PROTECTED]
To: George Pitcher [EMAIL PROTECTED]
Sent: Wednesday, September 26, 2001 2:46 PM
Subject: Re: [PHP] Building Dynamic Value list using ohp
hi!
try:
$query = select HEI from heronuser; // line 22
greetinx!
gottfried
Hi all,
I'm having a problem with dynamically building a value list.
My code:
?php
mysql_connect ('localhost', 'root', 'monty');
mysql_select_db ('Heronsql');
$query = (select HEI from heronuser); // LINE 22 on original
script
$result = mysql_query($query, $mysql_link);
if(mysql_num_rows($result)) {
// show all HEIs as options in select form
while($row = mysql_fetch_row($result))
{
print(option value=\$row[0]\$row[0]/option);
}
}
?
But this generates:
Parse error: parse error in c:\program files\apache
group\apache\htdocs\bizflyers\login.php on line 22
Any suggestions?
Regards
George
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Re: [PHP] Feature?
Maybe this? A bit verbose, but functional.
-Steve
?php
function foo($p)
{
if (empty($p['fred'])){
$p['fred'] = 'hello';
}
if (empty($p['banana'])){
$p['banana'] = 'world';
}
echo $p['fred'] . $p['banana'];
}
foo(array('fred' = 'hello', 'banana' = 'world'));
?
On Tuesday, September 25, 2001, at 06:25 AM, Andrey Hristov wrote:
Yeap, I know that. I thought about this bit of hack but this breaks the
conception on giving parameters. Also this trick cannot
solve the problem with default parameters. If I have function with 5
params and all of them have default values and I want to pass
value only to the second parameter what I have to do?
Andrey Hristov
IcyGEN Corporation
http://www.icygen.com
BALANCED SOLUTIONS
- Original Message -
From: [EMAIL PROTECTED]
To: Andrey Hristov [EMAIL PROTECTED]
Sent: Tuesday, September 25, 2001 1:14 PM
Subject: Re: [PHP] Feature?
On Tue, 25 Sep 2001 11:36:25 +0300, you wrote:
In the case when I've few parameters I've to remember their order, so
why not
$bar=foo('par2'=10);
I want to pass value to only one or more but not to all params.
Also this will make the code clearer I think.
Comments are welcome!
?php
function foo($p)
{
echo $p['fred'] . $p['banana'];
}
foo(array('fred' = 'hello', 'banana' = 'world'));
?
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Re: [PHP] Getting my head around nulls
On Tuesday, September 25, 2001, at 10:30 AM, [EMAIL PROTECTED] wrote: Thanks for correcting my misspelling, Andrey, IS NULL not IS_NULL. Another thing to look at, Ben, is IFNULL(). I would give you an example, but I never got it to work like I thought it should ;) I think it is supposed to return an alternate value for NULLs. Just had a look at manual, ifnull() seems close to useless. However if they had NVL(), as Oracle douse NVL( column|litrel, '*null*' ) This takes a column or literal as its first arg and if arg is null returns 2nd arg otherwise returns arg. In other words if the column is null it is replaces by arg2 otherwise it is simply returned. Um, that's what ifnull() does. At least it works for me. -Steve Next week I will sing the prases of the oracle decode statement -;) The week after that I will get all exited about MySQL freetext indexes, yum, yum. Neb -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] Querying an object's functions
Is there any way in PHP 4.0.6 to query an object for its member functions? For example I have a couple classes that have an htmlString() function to display themselves in some special way as html. I'd like to go through a list of various objects, find out if each can run htmlString() and if so use that, otherwise use some generic object-to-html function. I could just put a member variable in the object and check for that, but it would be more elegant to be able to check for the function directly. Thanks for any suggestions. -Steve -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Querying an object's functions
Thanks. Sorry for missing that. -Steve On Monday, September 24, 2001, at 05:54 PM, Rasmus Lerdorf wrote: http://www.php.net/manual/en/function.get-class-methods.php On Mon, 24 Sep 2001, Steve Cayford wrote: Is there any way in PHP 4.0.6 to query an object for its member functions? For example I have a couple classes that have an htmlString() function to display themselves in some special way as html. I'd like to go through a list of various objects, find out if each can run htmlString() and if so use that, otherwise use some generic object-to-html function. I could just put a member variable in the object and check for that, but it would be more elegant to be able to check for the function directly. Thanks for any suggestions. -Steve -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
