Re: [symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
You can use new plugins based on Jquery working similar to link_to_remote.. On Fri, Apr 30, 2010 at 7:36 PM, Massimiliano Arione garak...@gmail.comwrote: On 29 Apr, 15:36, Gareth McCumskey gmccums...@gmail.com wrote: I know you are talking about ajax. So, for the sake of brevity i include an example of the way it could be done in symfony 1.0 using the helpers: symfony 1.0 is unsupported since a long time. Wonder why newer versions drop the ugly helpers like link_to_remote... cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
On 29 Apr, 09:17, Gareth McCumskey gmccums...@gmail.com wrote: Or return an array from the action to the template/partial and have php do: ul ?php foreach ($array as $array_item): ? li?php echo $array_item ?/li ?php endforeach; ? /ul We're talking about ajax. You just can't output any html anywhere, unless you want to use ugly innerHTML js function. cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
I know you are talking about ajax. So, for the sake of brevity i
include an example of the way it could be done in symfony 1.0 using
the helpers:
In a template:
?php echo link_to_remote('Link text', array(
url=module/action,
update=div_to_update
))
?
div id='div_to_update'/div
In actions.class.php
public function executeAction(sfWebRequest $request)
{
//Run whatever model class methods to get data you need
//and store that in an array eg:
$this-array_to_use = ModelNamePeer::getDataArray();
//Render to a partial
$this-renderPartial('partialName');
}
Now in _partialName.php:
ul
?php foreach ($array_to_use as $array_item): ?
li?php echo $array_item ?/li
?php endforeach; ?
/ul
That partial would display within the div_to_update div in the
template and is ajax.
On Thu, Apr 29, 2010 at 3:27 PM, Massimiliano Arione garak...@gmail.com wrote:
On 29 Apr, 09:17, Gareth McCumskey gmccums...@gmail.com wrote:
Or return an array from the action to the template/partial and have php do:
ul
?php foreach ($array as $array_item): ?
li?php echo $array_item ?/li
?php endforeach; ?
/ul
We're talking about ajax.
You just can't output any html anywhere, unless you want to use ugly
innerHTML js function.
cheers
Massimiliano
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Re: [symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
Thanks Both,
no point in making things harder if symfony gives you the tools especially
if javsacript is not a strong one which for me it isn't so i like the
partial example, that was what I was after - understanding how to link the
symfony elements together to make it nice and neat.
Really appreciate your insights.
On 29 April 2010 14:36, Gareth McCumskey gmccums...@gmail.com wrote:
I know you are talking about ajax. So, for the sake of brevity i
include an example of the way it could be done in symfony 1.0 using
the helpers:
In a template:
?php echo link_to_remote('Link text', array(
url=module/action,
update=div_to_update
))
?
div id='div_to_update'/div
In actions.class.php
public function executeAction(sfWebRequest $request)
{
//Run whatever model class methods to get data you need
//and store that in an array eg:
$this-array_to_use = ModelNamePeer::getDataArray();
//Render to a partial
$this-renderPartial('partialName');
}
Now in _partialName.php:
ul
?php foreach ($array_to_use as $array_item): ?
li?php echo $array_item ?/li
?php endforeach; ?
/ul
That partial would display within the div_to_update div in the
template and is ajax.
On Thu, Apr 29, 2010 at 3:27 PM, Massimiliano Arione garak...@gmail.com
wrote:
On 29 Apr, 09:17, Gareth McCumskey gmccums...@gmail.com wrote:
Or return an array from the action to the template/partial and have php
do:
ul
?php foreach ($array as $array_item): ?
li?php echo $array_item ?/li
?php endforeach; ?
/ul
We're talking about ajax.
You just can't output any html anywhere, unless you want to use ugly
innerHTML js function.
cheers
Massimiliano
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[symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
Ho Both, Thanks for your thoughts on this. If you can spare the time, I have one further question about this I am currently returning the ul that the tree menu function needs from the action which calls a fetchTree function which is currently in the model. This was just for development purposes and I can see I shouoldn't be writing html in the model - I need to put it in the appropriate place. The function grabs the child folders and child files for the given parent and then writes the ul on this basis. What is the best way to separate this out in symfony - do I need to use a helper for this, maybe a partial? ( I don't yet fully understand these and when they should be used. ) and then pass the child folders and files to this which can output the html that is returned to the ajax function ? My assumption is that I should grab the child objects in the action by calling peer methods, assign them as variables and then call something that will take these values and output the ul which is then returned by the action to the ajax. Thanks, Paul -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
On 21 Apr, 15:14, Paul Burdon p...@clearintent.co.uk wrote: Could you clarify what the 'proper' way is please. Thanks. Of course. The proper way is to write html as if javascript wouldn't exist. Then, write javascript files that use the document load event to look into dom, modify the dom itself and add other events (that use ajax) cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
Massimiliano is right, but the right way or best paractices as it is known tends to be a moving goal post. When we started work on one of our large projects, embedded javascript (i.e. javascript on a link as an onClick event) wasn't seen as odd or strange. Now, its considered best practices to write Javascript that creates event listeners on dom elements instead. When I first started web development, table-based designs were the norm and taught at schools now CSS replaces that logic and table based designs are seen (rightfully) as layout hacks. My advice is just to try and keep clued up on this industry cos things tend to move very quickly and development (web or desktop) is still trying to find its feet and its best ways of doing things. Ultimately, even if its development is ugly, your end users wont care how its coded just that it works. Best practices are really only there to make our lives as devs easier over the long term in assisting us to write code thats easy to maintain and extend, hence the creation of symfony 3 On Fri, Apr 23, 2010 at 6:59 PM, Massimiliano Arione garak...@gmail.com wrote: On 21 Apr, 15:14, Paul Burdon p...@clearintent.co.uk wrote: Could you clarify what the 'proper' way is please. Thanks. Of course. The proper way is to write html as if javascript wouldn't exist. Then, write javascript files that use the document load event to look into dom, modify the dom itself and add other events (that use ajax) cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- Gareth McCumskey http://garethmccumskey.blogspot.com twitter: @garethmcc -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
On 19 Apr, 16:46, Tofuwarrior psbur...@googlemail.com wrote: As a general principle is my approach ( ie pull the data from an action into the jQuery) correct. I don't think your approach is fully correct. You should never mix javascript and php code. You should write php (and so html) as if javascript wouldn't exist. Then, in a second step, add user interface enhancement with pure javascript files. It's a matter of separation of concerns: html (php) for structure, css for presentation, javascript for behavior cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
Its not javascript code its just a JSON encoded string. On Wed, Apr 21, 2010 at 8:22 AM, Massimiliano Arione garak...@gmail.com wrote: On 19 Apr, 16:46, Tofuwarrior psbur...@googlemail.com wrote: As a general principle is my approach ( ie pull the data from an action into the jQuery) correct. I don't think your approach is fully correct. You should never mix javascript and php code. You should write php (and so html) as if javascript wouldn't exist. Then, in a second step, add user interface enhancement with pure javascript files. It's a matter of separation of concerns: html (php) for structure, css for presentation, javascript for behavior cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- Gareth McCumskey http://garethmccumskey.blogspot.com twitter: @garethmcc -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
Thanks for all input everyone. Finally got it working, had to mess around with the javascript aswell and that is always tricky for someone who really has never gone very far with it. Anyway, it looks and works great, who would have thought that old dirty javascript would turn out to be such a useful thing :-) On 21 April 2010 07:58, Gareth McCumskey gmccums...@gmail.com wrote: Its not javascript code its just a JSON encoded string. On Wed, Apr 21, 2010 at 8:22 AM, Massimiliano Arione garak...@gmail.com wrote: On 19 Apr, 16:46, Tofuwarrior psbur...@googlemail.com wrote: As a general principle is my approach ( ie pull the data from an action into the jQuery) correct. I don't think your approach is fully correct. You should never mix javascript and php code. You should write php (and so html) as if javascript wouldn't exist. Then, in a second step, add user interface enhancement with pure javascript files. It's a matter of separation of concerns: html (php) for structure, css for presentation, javascript for behavior cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- Gareth McCumskey http://garethmccumskey.blogspot.com twitter: @garethmcc -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
well i do: inside the controller: $this-hasLayout(false); inside the view: ?php echo json_encode($my_json_content_variable)? Alecs On Wed, Apr 21, 2010 at 2:51 PM, Paul Burdon p...@clearintent.co.uk wrote: Thanks for all input everyone. Finally got it working, had to mess around with the javascript aswell and that is always tricky for someone who really has never gone very far with it. Anyway, it looks and works great, who would have thought that old dirty javascript would turn out to be such a useful thing :-) On 21 April 2010 07:58, Gareth McCumskey gmccums...@gmail.com wrote: Its not javascript code its just a JSON encoded string. On Wed, Apr 21, 2010 at 8:22 AM, Massimiliano Arione garak...@gmail.com wrote: On 19 Apr, 16:46, Tofuwarrior psbur...@googlemail.com wrote: As a general principle is my approach ( ie pull the data from an action into the jQuery) correct. I don't think your approach is fully correct. You should never mix javascript and php code. You should write php (and so html) as if javascript wouldn't exist. Then, in a second step, add user interface enhancement with pure javascript files. It's a matter of separation of concerns: html (php) for structure, css for presentation, javascript for behavior cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- Gareth McCumskey http://garethmccumskey.blogspot.com twitter: @garethmcc -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- Have a nice day! Alecs Certified ScrumMaster There are no cannibals alive! I have ate the last one yesterday ... I am on web: http://www.alecslupu.ro/ I am on twitter: http://twitter.com/alecslupu I am on linkedIn: http://www.linkedin.com/in/alecslupu Tel: (+4)0722 621 280 -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
And if you had to create a restful api that returns content as JSON? Returning JSON using renderText is perfectly valid and does not break the seperation of concerns. The actions responsibility is to recieve a request, gather data needed for the response and pass that data to the template and/or requesting service. JSON is just a data format (well within the actions field of responsibilities) not Javascript. On Wed, Apr 21, 2010 at 2:00 PM, Alexandru-Emil Lupu gang.al...@gmail.com wrote: well i do: inside the controller: $this-hasLayout(false); inside the view: ?php echo json_encode($my_json_content_variable)? Alecs On Wed, Apr 21, 2010 at 2:51 PM, Paul Burdon p...@clearintent.co.uk wrote: Thanks for all input everyone. Finally got it working, had to mess around with the javascript aswell and that is always tricky for someone who really has never gone very far with it. Anyway, it looks and works great, who would have thought that old dirty javascript would turn out to be such a useful thing :-) On 21 April 2010 07:58, Gareth McCumskey gmccums...@gmail.com wrote: Its not javascript code its just a JSON encoded string. On Wed, Apr 21, 2010 at 8:22 AM, Massimiliano Arione garak...@gmail.com wrote: On 19 Apr, 16:46, Tofuwarrior psbur...@googlemail.com wrote: As a general principle is my approach ( ie pull the data from an action into the jQuery) correct. I don't think your approach is fully correct. You should never mix javascript and php code. You should write php (and so html) as if javascript wouldn't exist. Then, in a second step, add user interface enhancement with pure javascript files. It's a matter of separation of concerns: html (php) for structure, css for presentation, javascript for behavior cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- Gareth McCumskey http://garethmccumskey.blogspot.com twitter: @garethmcc -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- Have a nice day! Alecs Certified ScrumMaster There are no cannibals alive! I have ate the last one yesterday ... I am on web: http://www.alecslupu.ro/ I am on twitter: http://twitter.com/alecslupu I am on linkedIn: http://www.linkedin.com/in/alecslupu Tel: (+4)0722 621 280 -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- Gareth McCumskey http://garethmccumskey.blogspot.com twitter: @garethmcc -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
On 21 Apr, 14:39, Gareth McCumskey gmccums...@gmail.com wrote: And if you had to create a restful api that returns content as JSON? Returning JSON using renderText is perfectly valid and does not break the seperation of concerns. The actions responsibility is to recieve a request, gather data needed for the response and pass that data to the template and/or requesting service. JSON is just a data format (well within the actions field of responsibilities) not Javascript. Of course, I didn't mean the json part when I spoke of separation. That part is perfect, and after all is the only way to use ajax. The wrong part is the use of jq_javascript_tag() helper, that implies writing javascript code into html. cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
Could you clarify what the 'proper' way is please. Thanks. On 21 April 2010 14:02, Massimiliano Arione garak...@gmail.com wrote: On 21 Apr, 14:39, Gareth McCumskey gmccums...@gmail.com wrote: And if you had to create a restful api that returns content as JSON? Returning JSON using renderText is perfectly valid and does not break the seperation of concerns. The actions responsibility is to recieve a request, gather data needed for the response and pass that data to the template and/or requesting service. JSON is just a data format (well within the actions field of responsibilities) not Javascript. Of course, I didn't mean the json part when I spoke of separation. That part is perfect, and after all is the only way to use ajax. The wrong part is the use of jq_javascript_tag() helper, that implies writing javascript code into html. cheers Massimiliano -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.comsymfony-users%2bunsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
Re: [symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
Its exactly the right approach so don't worry about that ;)
On Mon, Apr 19, 2010 at 4:46 PM, Tofuwarrior psbur...@googlemail.com wrote:
Thanks all, I knew about changing the template but not about the
render text. I'm just off to try these things out now.
Much appreciated.
As a general principle is my approach ( ie pull the data from an
action into the jQuery) correct.
Thanks,
Paul
On 19 Apr, 14:17, Gareth McCumskey gmccums...@gmail.com wrote:
In addition there are other things you can do too like tell it to use
a different template to the one that it will automatically look for
(great for re-using a template you've created before) by doing:
$this-setTemplate('templatefilename'); //Note no return word in fron
and no Success.php at the end of the template name
You can also instruct an action to load a partial instead for those
AJAX responses where you need content rendered:
return $this-renderPartial('partialname', array('variable1'=$variable1));
On Mon, Apr 19, 2010 at 2:43 PM, Tofuwarrior psbur...@googlemail.com wrote:
Hi,
If anyone can help me I would be very grateful, I'm over my head but I
think it is probably a simple thing i'm missing. I've got this far
using the jobeet tutorial and various jQuery and symfony resources but
I'm stuck.
I'm trying to get an ajax jQuery treeMenu to work in symfony and I
think I might be lacking basic understanding about how to set it up in
Symfony. I'm using 1.4 and have installed the jQueryReloaded plugin so
no problems there.
Currently I am doing this in the show template which is where the tree
should show.
?php echo javascript_include_tag('/js/jqueryFileTree/
jqueryFileTree') ;
echo jq_javascript_tag(
$(document).ready( function() {
$('#fileTreeDemo_1').css('background-color','#999');
$('#fileTreeDemo_1').fileTree({ root: '/',
script: '/folder/tree/
id/.$CmsFolder-getId().' }, function(file) {
alert(file);
});
});
);
?
This calls the jquery file tree thing fine. By interrupting the
process in the script I can see that the div gets updated with the
loading image so that's not the problem but looking in firebug I can
see that there is a 404 happening, it says:
POSThttp://www.domain.com/folder/tree/id/1
. If I access this action (which is the one supposed to return the
stuff for the ajax) I get a 500 error, no template found
(treeSuccess.php).
I don't want a template, I just want to get the raw output of this
action into this javascript function and I figure this is the
problem.
Just for reference.
The tree menu script is here:http://pastebin.com/R1yW0C9t
Thanks for taking a look, I'm tearing my hair out!
--
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twitter: @garethmcc
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http://garethmccumskey.blogspot.com
twitter: @garethmcc
--
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[symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
On 19 Apr, 14:43, Tofuwarrior psbur...@googlemail.com wrote:
I don't want a template, I just want to get the raw output of this
action into this javascript function and I figure this is the
problem.
So, you replied yourself: just skip the view in your action.
You can do it with return $this-renderText('your js stuff')
cheers
Massimiliano
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[symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
Thanks all, I knew about changing the template but not about the
render text. I'm just off to try these things out now.
Much appreciated.
As a general principle is my approach ( ie pull the data from an
action into the jQuery) correct.
Thanks,
Paul
On 19 Apr, 14:17, Gareth McCumskey gmccums...@gmail.com wrote:
In addition there are other things you can do too like tell it to use
a different template to the one that it will automatically look for
(great for re-using a template you've created before) by doing:
$this-setTemplate('templatefilename'); //Note no return word in fron
and no Success.php at the end of the template name
You can also instruct an action to load a partial instead for those
AJAX responses where you need content rendered:
return $this-renderPartial('partialname', array('variable1'=$variable1));
On Mon, Apr 19, 2010 at 2:43 PM, Tofuwarrior psbur...@googlemail.com wrote:
Hi,
If anyone can help me I would be very grateful, I'm over my head but I
think it is probably a simple thing i'm missing. I've got this far
using the jobeet tutorial and various jQuery and symfony resources but
I'm stuck.
I'm trying to get an ajax jQuery treeMenu to work in symfony and I
think I might be lacking basic understanding about how to set it up in
Symfony. I'm using 1.4 and have installed the jQueryReloaded plugin so
no problems there.
Currently I am doing this in the show template which is where the tree
should show.
?php echo javascript_include_tag('/js/jqueryFileTree/
jqueryFileTree') ;
echo jq_javascript_tag(
$(document).ready( function() {
$('#fileTreeDemo_1').css('background-color','#999');
$('#fileTreeDemo_1').fileTree({ root: '/',
script: '/folder/tree/
id/.$CmsFolder-getId().' }, function(file) {
alert(file);
});
});
);
?
This calls the jquery file tree thing fine. By interrupting the
process in the script I can see that the div gets updated with the
loading image so that's not the problem but looking in firebug I can
see that there is a 404 happening, it says:
POSThttp://www.domain.com/folder/tree/id/1
. If I access this action (which is the one supposed to return the
stuff for the ajax) I get a 500 error, no template found
(treeSuccess.php).
I don't want a template, I just want to get the raw output of this
action into this javascript function and I figure this is the
problem.
Just for reference.
The tree menu script is here:http://pastebin.com/R1yW0C9t
Thanks for taking a look, I'm tearing my hair out!
--
If you want to report a vulnerability issue on symfony, please send it to
security at symfony-project.com
You received this message because you are subscribed to the Google
Groups symfony users group.
To post to this group, send email to symfony-users@googlegroups.com
To unsubscribe from this group, send email to
symfony-users+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/symfony-users?hl=en
--
Gareth McCumskeyhttp://garethmccumskey.blogspot.com
twitter: @garethmcc
--
If you want to report a vulnerability issue on symfony, please send it to
security at symfony-project.com
You received this message because you are subscribed to the Google
Groups symfony users group.
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--
If you want to report a vulnerability issue on symfony, please send it to
security at symfony-project.com
You received this message because you are subscribed to the Google
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[symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
Hi all,
So, some progress but still, not working and 2 seperate issues I
think.
1) When I return renderText the output still been decorated by the
debug toolbar. This is when i access /folder/tree/id/1 directly.
- Is this because I am not calling this with jq_remote_function ?(I
read somethign about ajax calls being automatically detected by
symfony and so it bypassing decorating with debug toolbar etc.
I'm just doing this
echo jq_javascript_tag(
$(document).ready( function() {
$('#fileTreeDemo_1').css('background-color','#999');
$('#fileTreeDemo_1').fileTree({ root: '/',
script: '/folder/tree/
id/.$CmsFolder-getId().' }, function(file) {
alert(file);
});
});
);
So will symfony still detect the xmlhttprequest status in the same
way.
2) When I call this url from the function firebug still shows JQuery
reporting receiving a 404 from the same url above that was accessed
fine directly - ?!?!? Erm.
You guys/gals got any ideas on how I couold proceed?
Cheers,
Paul
On 19 Apr, 15:46, Tofuwarrior psbur...@googlemail.com wrote:
Thanks all, I knew about changing the template but not about the
render text. I'm just off to try these things out now.
Much appreciated.
As a general principle is my approach ( ie pull the data from an
action into the jQuery) correct.
Thanks,
Paul
On 19 Apr, 14:17, Gareth McCumskey gmccums...@gmail.com wrote:
In addition there are other things you can do too like tell it to use
a different template to the one that it will automatically look for
(great for re-using a template you've created before) by doing:
$this-setTemplate('templatefilename'); //Note no return word in fron
and no Success.php at the end of the template name
You can also instruct an action to load a partial instead for those
AJAX responses where you need content rendered:
return $this-renderPartial('partialname', array('variable1'=$variable1));
On Mon, Apr 19, 2010 at 2:43 PM, Tofuwarrior psbur...@googlemail.com
wrote:
Hi,
If anyone can help me I would be very grateful, I'm over my head but I
think it is probably a simple thing i'm missing. I've got this far
using the jobeet tutorial and various jQuery and symfony resources but
I'm stuck.
I'm trying to get an ajax jQuery treeMenu to work in symfony and I
think I might be lacking basic understanding about how to set it up in
Symfony. I'm using 1.4 and have installed the jQueryReloaded plugin so
no problems there.
Currently I am doing this in the show template which is where the tree
should show.
?php echo javascript_include_tag('/js/jqueryFileTree/
jqueryFileTree') ;
echo jq_javascript_tag(
$(document).ready( function() {
$('#fileTreeDemo_1').css('background-color','#999');
$('#fileTreeDemo_1').fileTree({ root: '/',
script: '/folder/tree/
id/.$CmsFolder-getId().' }, function(file) {
alert(file);
});
});
);
?
This calls the jquery file tree thing fine. By interrupting the
process in the script I can see that the div gets updated with the
loading image so that's not the problem but looking in firebug I can
see that there is a 404 happening, it says:
POSThttp://www.domain.com/folder/tree/id/1
. If I access this action (which is the one supposed to return the
stuff for the ajax) I get a 500 error, no template found
(treeSuccess.php).
I don't want a template, I just want to get the raw output of this
action into this javascript function and I figure this is the
problem.
Just for reference.
The tree menu script is here:http://pastebin.com/R1yW0C9t
Thanks for taking a look, I'm tearing my hair out!
--
If you want to report a vulnerability issue on symfony, please send it to
security at symfony-project.com
You received this message because you are subscribed to the Google
Groups symfony users group.
To post to this group, send email to symfony-users@googlegroups.com
To unsubscribe from this group, send email to
symfony-users+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/symfony-users?hl=en
--
Gareth McCumskeyhttp://garethmccumskey.blogspot.com
twitter: @garethmcc
--
If you want to report a vulnerability issue on symfony, please send it to
security at symfony-project.com
You received this message because you are subscribed to the Google
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[symfony-users] Re: :-( please help. ajax problem - noob to ajax -probably simple
OK, I think I'm nearly there.
If i use the bundled php connector for the treeMenu script it works
fine so I know it works.
$('#fileTreeDemo_1').fileTree({ root: '/', script: '/js/jqueryFileTree/
connectors/jqueryFileTree.php?id=.$CmsFolder-getId().' },
function(file) {
BUT when I substitute my own
$('#fileTreeDemo_1').fileTree({ root: '/', script: '/folder/tree/id/.
$CmsFolder-getId().' }, function(file) {
for the bundled one firebug shows a 404 error for that url.
I can access the url fine directly and it outputs the same format
ulliblah blah/li/ul as the bundled connector except
with the web debug attached to it but I presume that is because when i
access it directly xmlHttpRequest is false so symfony decorates it
with the debug stuff.
Anyone got any ideas of where to look?
Thanks,
TW
On 19 Apr, 15:46, Tofuwarrior psbur...@googlemail.com wrote:
Thanks all, I knew about changing the template but not about the
render text. I'm just off to try these things out now.
Much appreciated.
As a general principle is my approach ( ie pull the data from an
action into the jQuery) correct.
Thanks,
Paul
On 19 Apr, 14:17, Gareth McCumskey gmccums...@gmail.com wrote:
In addition there are other things you can do too like tell it to use
a different template to the one that it will automatically look for
(great for re-using a template you've created before) by doing:
$this-setTemplate('templatefilename'); //Note no return word in fron
and no Success.php at the end of the template name
You can also instruct an action to load a partial instead for those
AJAX responses where you need content rendered:
return $this-renderPartial('partialname', array('variable1'=$variable1));
On Mon, Apr 19, 2010 at 2:43 PM, Tofuwarrior psbur...@googlemail.com
wrote:
Hi,
If anyone can help me I would be very grateful, I'm over my head but I
think it is probably a simple thing i'm missing. I've got this far
using the jobeet tutorial and various jQuery and symfony resources but
I'm stuck.
I'm trying to get an ajax jQuery treeMenu to work in symfony and I
think I might be lacking basic understanding about how to set it up in
Symfony. I'm using 1.4 and have installed the jQueryReloaded plugin so
no problems there.
Currently I am doing this in the show template which is where the tree
should show.
?php echo javascript_include_tag('/js/jqueryFileTree/
jqueryFileTree') ;
echo jq_javascript_tag(
$(document).ready( function() {
$('#fileTreeDemo_1').css('background-color','#999');
$('#fileTreeDemo_1').fileTree({ root: '/',
script: '/folder/tree/
id/.$CmsFolder-getId().' }, function(file) {
alert(file);
});
});
);
?
This calls the jquery file tree thing fine. By interrupting the
process in the script I can see that the div gets updated with the
loading image so that's not the problem but looking in firebug I can
see that there is a 404 happening, it says:
POSThttp://www.domain.com/folder/tree/id/1
. If I access this action (which is the one supposed to return the
stuff for the ajax) I get a 500 error, no template found
(treeSuccess.php).
I don't want a template, I just want to get the raw output of this
action into this javascript function and I figure this is the
problem.
Just for reference.
The tree menu script is here:http://pastebin.com/R1yW0C9t
Thanks for taking a look, I'm tearing my hair out!
--
If you want to report a vulnerability issue on symfony, please send it to
security at symfony-project.com
You received this message because you are subscribed to the Google
Groups symfony users group.
To post to this group, send email to symfony-users@googlegroups.com
To unsubscribe from this group, send email to
symfony-users+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/symfony-users?hl=en
--
Gareth McCumskeyhttp://garethmccumskey.blogspot.com
twitter: @garethmcc
--
If you want to report a vulnerability issue on symfony, please send it to
security at symfony-project.com
You received this message because you are subscribed to the Google
Groups symfony users group.
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To unsubscribe from this group, send email to
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For more options, visit this group
athttp://groups.google.com/group/symfony-users?hl=en
--
If you want to report a vulnerability issue on symfony, please send it to
security at symfony-project.com
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