--- peternilsson42 wrote:
So you made absolutely _no_ change to the semantics of
that assignment!
I fixed the signal to make others happy.
You seem to be only interested in one class of machine.
why do you think that? Or,
do you think different values should be displayed?
My previous
--- I wrote:
It is mathematically obvious the Intel's approach. I thought it applied
wherever it is possible.
Correction:
I thought the mathematically obvious approach would be applied wherever
possible.
Following program is showing an error while running in turbo c :
undefined symbol for try
statement missing after try .
#includeconio.h
#includestdlib.h
#includeiostream.h
void main()
{
clrscr();
int a,b,c;
coutenter two valuesendl;
cinab;
try
{
if(b0)
{
coutresult(a/b)= a/bendl;
}
else
{
On Tue, Nov 25, 2008 at 3:10 PM, crystalcat_75
[EMAIL PROTECTED] wrote:
Following program is showing an error while running in turbo c :
undefined symbol for try
statement missing after try .
Turbo C is an ancient compiler that predates the current C++ standard.
This means that if you try to
On Tue, Nov 25, 2008 at 9:10 AM, crystalcat_75
[EMAIL PROTECTED] wrote:
Following program is showing an error while running in turbo c :
undefined symbol for try
statement missing after try .
I don't think Turbo C supports exceptions. You need to upgrade to a
modern compiler like Dev-C++ or MS
Hello,
I did a google for this, and came up with the wrong results.
I've got a line of code that reads:
str=i==1?is||are;
the compiler is choking; ideas would be great, not sure what Im messing up.
Thanks,
Tyler Littlefield
email: [EMAIL PROTECTED]
web: tysdomain-com
Visit for quality software
On Tue 2008-11-25 09:48:24 UTC-0700, Tyler Littlefield ([EMAIL PROTECTED])
wrote:
I've got a line of code that reads:
str=i==1?is||are;
the compiler is choking; ideas would be great, not sure what Im messing up.
I think you mean the ternary operator:
str = i == 1 ? is : are;
This is
On Tue, Nov 25, 2008 at 11:48 AM, Tyler Littlefield [EMAIL PROTECTED] wrote:
Hello,
I did a google for this, and came up with the wrong results.
I've got a line of code that reads:
str=i==1?is||are;
the compiler is choking; ideas would be great, not sure what Im messing up.
should be
str =
awesome, thanks. maybe that's why google wasn't turning up results. :)
Thanks,
Tyler Littlefield
email: [EMAIL PROTECTED]
web: tysdomain-com
Visit for quality software and web design.
skype: st8amnd2005
- Original Message -
From: Brett McCoy
To: c-prog@yahoogroups.com
Sent:
Pedro Izecksohn [EMAIL PROTECTED] wrote:
peternilsson42 wrote:
[ unsigned short int a;
a = USHRT_MAX; /* previously a = -1; */]
So you made absolutely _no_ change to the semantics of
that assignment!
I fixed the signal to make others happy.
You must be referring to Thomas'
--- peternilsson42 wrote:
Ah, then you've probably been fooled by the cliché that
C is just portable assembler.
If I could do just one modification to the standard, I'd add an overflow
macro, like errno.
Pedro Izecksohn [EMAIL PROTECTED] wrote:
--- peternilsson42 wrote:
Ah, then you've probably been fooled by the cliché that
C is just portable assembler.
If I could do just one modification to the standard,
I'd add an overflow macro, like errno.
The behaviour on integer overflow is
Brett McCoy [EMAIL PROTECTED] wrote:
str = i == 1 ? is : are;
It's known as the tertiary or ternary operator, BTW.
It should be known by its name: conditional operator.
--
Peter
u will know when u IM me [EMAIL PROTECTED] wrote:
I want to create an enum variable whose size is 4 byte in
32- machine and 8 bytes on 64 bit machines.
Your nearest bet is...
enum my_enum { my_enum_constant = INT_MAX; } my_enum_variable;
Basically, I want to knopw whether one can specify
--- I wrote:
If I could do just one modification to the standard, I'd add an overflow
macro, like errno.
--- peternilsson42 replied:
The behaviour on integer overflow is undefined. Hence,
implementations already have the freedom to do precisely
that if they so choose. [That they don't is
peternilsson42 wrote:
Pedro Izecksohn [EMAIL PROTECTED] wrote:
peternilsson42 wrote:
[ unsigned short int a;
a = USHRT_MAX; /* previously a = -1; */]
So you made absolutely _no_ change to the semantics of
that assignment!
I fixed the signal to make others happy.
You must
--- Thomas Hruska wrote:
There would also have been warnings on the next line of code with the
compiler complaining about a signed to unsigned conversion or
something like that. That would have been the more useful clue to the
OP that a weird conversion was happening behind the scenes.
Pedro Izecksohn wrote:
--- Thomas Hruska wrote:
There would also have been warnings on the next line of code with the
compiler complaining about a signed to unsigned conversion or
something like that. That would have been the more useful clue to the
OP that a weird conversion was
Pedro Izecksohn [EMAIL PROTECTED] wrote:
--- Thomas Hruska wrote:
peternilsson42 wrote:
Pedro Izecksohn [EMAIL PROTECTED] wrote:
peternilsson42 wrote:
[ unsigned short int a;
a = USHRT_MAX; /* previously a = -1; */ ]
So you made absolutely _no_ change to the semantics of
--- In c-prog@yahoogroups.com, crystalcat_75 [EMAIL PROTECTED]
Following program is showing an error while running in turbo c :
undefined symbol for try
statement missing after try .
snip
Upgrade your compiler please!
Regards,
Saurabh
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