I know this is somewhat of a troll answer, but:
This should be possible with some tweaks to core variables, but why in the
world would you want to do that? If your answer is that you know Smarty and
not CakeViews I'd suggest you take 4 hours of reading and you will be
pretty comfortable with
I would like to pass URL parameters in cakephp with URL that ends with xml
like below;
http://localhost/cp251/controller/api_get_info?page=1.xml
The controller function looks like this;
public function api_get_info(){
if($this-RequestHandler-responseType() == 'xml')
{
Have a look at
http://book.cakephp.org/2.0/en/development/routing.html#Router::parseExtensions
On 4 Jun 2014, at 10:41, Sam lightai...@gmail.com wrote:
I would like to pass URL parameters in cakephp with URL that ends with xml
like below;
Duplicate
of
http://stackoverflow.com/questions/24033937/extracting-url-parameters-in-cakephp-with-url-that-ends-with-xml
Am Mittwoch, 4. Juni 2014 11:41:56 UTC+2 schrieb Sam:
I would like to pass URL parameters in cakephp with URL that ends with xml
like below;
Hello all,
I'm pretty new to testing using mocks in cakephp and I'm having trouble
mocking models that have behavior objects. Is there a way when you create a
mock object to let cake know that you don't want the model to load any
behaviors? Perhaps with something passed into the constructor?
If this happens, start checking logs. CakePHP logs errors to /tmp/, and
your server access and error logs should also be reviewed. CakePHP depends
on an operating system, a web server, and a database server. Each of these
need to be up and running for Cake to do its thing.
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First you need to identify what makes a file unique. Is it the contents of
a row? a set of rows? a row ID? Second, you need to write code to query
your existing database to see if your uploaded file has already been added
(run a SELECT to see if the rows you are about to add have already been
I had a weird error once where the Config folder was renamed to config (lower
case c) after uploading some updates via FTP. The site just blanked out. After
searching and debugging for a few hours I went to the test page and it
presented the error to me. Might be worth a try.
On 4 Jun 2014, at
yes this work thankyou
$teacherid = $this-Teacher-field('id', array('Teacher.user_id' =
$currentuserid));
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Hi,
I just want to display fields from 3 tables which I have checked on how to
do this and I am not clear on this. Examples I have found concentrate on 2
fields or keyed in conditions on multiple tables.
I have models all related in some way.
I want the username from a tutorsession table and
Look at the Containable behaviour:
http://book.cakephp.org/2.0/en/core-libraries/behaviors/containable.html
On 4 Jun 2014, at 14:47, ajt jagguy...@gmail.com wrote:
Hi,
I just want to display fields from 3 tables which I have checked on how to do
this and I am not clear on this. Examples I
What kind of tests/queries are you guys doing? Just verifying that you can
connect or pulling back a bunch of rows?
On Tuesday, June 3, 2014 9:57:43 PM UTC-6, Dakota wrote:
I have no issues with MsSQL and Cakephp 2.5 (migrated to 3.0 dev though
now). Running sql 2012 and php 5.5.
You can
This doesnt work as I get an error when displaying the username from the
associated table.
I guess i am doing something wrong still.
$this-set('tutor', $this-Tutorsession-find('all',
array('conditions' = array('Teacher.user_id' = $id)
,array('contain' =
A couple of things...
Why find all when presumably there is only one expected teacher? The contain
statement doesn't go inside an array:
$this-set(
'tutor',
$this-Tutorsession-find(
'first',
array(
'conditions' =
We've got a full application, doing joins, inserts, etc. Also uses
FileStream. No issues, runs just as fast as MySQL
On Wednesday, 4 June 2014 15:58:20 UTC+2, Jordan Hopfner wrote:
What kind of tests/queries are you guys doing? Just verifying that you can
connect or pulling back a bunch of
Thanks for the help gentlemen, I'm at a loss here. Unfortunately upgrading
PHP to 5.5 isn't in the cards for our production server at the moment. My
only other option is to develop the application in C# and .NET (yuck, lol).
On Wednesday, June 4, 2014 8:38:52 AM UTC-6, Dakota wrote:
We've got
Hi,
I have my CakePHP site running really well on my dev environment as
http://domain/. When I moved it to a test site, on a production server, at
new.domain.com, it loads, controllers and such work, I see data being
pulled up, but my CSS and images from the webroot folder aren't working. I
This still doesnt work as I get an error when I reference the user table
which should be linked unless I need to do this another way?
view
echo 'td'. $item['User']['username'].'/td'; ///error user undefined
$this-set(
'tutor',
$this-Tutorsession-find(
'first',
array(
'conditions' =
You are referencing the $user variable when you have set a $tutor variable. Add
this to your view so you can inspect the shape of the $tutor variable and work
out how to access the key you are looking for:
die(debug($tutor));
It'll probably look something like this:
array(
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