[snip]
However, the LEFT and RIGHT will take me a while to figure out.
[/snip]
FROM table a LEFT OUTER JOIN table b
ON(a.column = b.column)
Just follow the order tedd, a is on the left and b is on the right
LEFT OUTER - a - b (what may be in a might not be in b)
a - b - RIGHT OUTER (what may
On Monday 20 August 2007, tedd wrote:
Question -- is it redundant to say:
FROM table a LEFT OUTER JOIN table b
ON(a.column = b.column)
when table a appears first? Wouldn't that be the same as:
FROM table a OUTER JOIN table b
ON(a.column = b.column)
???
I'm trying to understand why
At 6:12 PM -0500 8/18/07, Jay Blanchard wrote:
[snip]
I know this is kinda crazy but I need it :P
I have one table that lists name's
and I have another table that has the name's and points
I want to know how to list the name's of the first table by the points
of the second table
[/snip]
Not
tedd wrote:
At 6:12 PM -0500 8/18/07, Jay Blanchard wrote:
[snip]
I know this is kinda crazy but I need it :P
I have one table that lists name's
and I have another table that has the name's and points
I want to know how to list the name's of the first table by the points
of the second table
[snip]
At 6:12 PM -0500 8/18/07, Jay Blanchard wrote:
[snip]
I know this is kinda crazy but I need it :P
I have one table that lists name's
and I have another table that has the name's and points
I want to know how to list the name's of the first table by the points
of the second table
[/snip]
On Sunday 19 August 2007, tedd wrote:
Not crazy, pretty standard from a database point of view;
SELECT a.name, b.points
FROM table a LEFT OUTER JOIN table b
ON(a.name = b.name)
This only works if the name in table a matches a name in table b.
Then why use a JOIN? It's my understanding
At 12:56 PM -0500 8/19/07, Larry Garfield wrote:
On Sunday 19 August 2007, tedd wrote:
Wouldn't this be simpler?
SELECT a.name, b.points
FROM table_name a, table_name_points b
WHERE a.name = b.name
There are various kinds of JOINs. The most common you'll actually use are
INNER JOIN
[snip]
However, the LEFT and RIGHT will take me a while to figure out.
[/snip]
FROM table a LEFT OUTER JOIN table b
ON(a.column = b.column)
Just follow the order tedd, a is on the left and b is on the right
LEFT OUTER - a - b (what may be in a might not be in b)
a - b - RIGHT OUTER (what may be
You might try sending this to a group that is more orientated towards data
basing.. Since that seems to be what your asking about...
On 8/18/07 3:53 PM, Nate [EMAIL PROTECTED] wrote:
I know this is kinda crazy but I need it :P
I have one table that lists name's
and I have another table that
[snip]
I know this is kinda crazy but I need it :P
I have one table that lists name's
and I have another table that has the name's and points
I want to know how to list the name's of the first table by the points
of the second table
[/snip]
Not crazy, pretty standard from a database point of
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