Às 18:40 de 02/06/2024, Rui Barradas escreveu:
Às 18:34 de 02/06/2024, Leo Mada via R-help escreveu:
Dear Shadee,
If you have a data.frame with the following columns:
n = 100; # population size
x = data.frame(
Sex = sample(c("M","F"), n, T),
Country = sample(c(
mented, minimal, self-contained, reproducible code.
Hello,
The following is simpler.
r2 <- xtabs(~ ., x) |> as.data.frame()
r2[-4L] # or r2[names(r2) != "Freq"]
Hope this helps,
Rui Barradas
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- Italy
Meteo Section
Snow Section
Via del Colle Ameno 5
60126 Torrette di Ancona, Ancona (AN)
Uff: +39 071 806 7743
E-mail: stefano.so...@regione.marche.it
---Oo-oO
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Da: Rui Barradas
Inviato: martedì 28 magg
rs
years <- Reduce(`:`, years)
# coerce to "Date"
from <- ISOdate(years, 5L, 2L, tz = "Etc/GMT-1")
to <- ISOdate(years, 10L, 30L, tz = "Etc/GMT-1")
# this logical index keeps only the dates between May, 2nd and Nov 1st.
keep <- data.frame(from, to) |
of the format = "%m-%d-%Y" argument.
Let scale_x_date take care of formating the date as you want it
displayed. Any of the two below is a valid date format.
ggplot(data = yyy[1:30,], aes(jdate, Sum)) +
geom_point() +
# scale_x_date(date_labels = "%b %d, %Y")
scale_x_d
Às 09:08 de 21/04/2024, Rui Barradas escreveu:
Às 08:55 de 21/04/2024, Hans W escreveu:
As we all know, in R indices for vectors start with 1, i.e, x[0] is not a
correct expression. Some algorithms, e.g. in graph theory or
combinatorics,
are much easier to formulate and code if 0 is an allowed
i + 1L
NextMethod()
}
as_zerobased <- function(x) {
class(x) <- c("zerobased", class(x))
x
}
x <- 1:10
y <- as_zerobased(x)
y[0]
#> [1] 1
y[1]
#> [1] 2
y[9]
#> [1] 10
y[10]
#> [1] NA
Hope this helps,
Rui Barradas
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) |>
which()
data.frame(Col = i, Unbalanced = Unbalanced)
}) |>
do.call(rbind, args = _)
}
# read the data disregardin g quoted strings
df1 <- read.csv(fl, quote = "")
# determine which strings have unbalanced quotes and
# where
unbalanced_dquotes(df1)
the most serious problem here.
Hoep this helps,
Rui Barradas
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lt;- 14e6
water_level(l = lev)
#> [1] 7056452
water_level(v = vol)
#> [1] 2480
Hope this helps,
Rui Barradas
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# note that the row names are still tapply's names vector
# and that the columns order is not Date/count. Both are fixed
# after the calculations.
res
You can see that the error message is on the pipe. Please, let me know
where I am missing it.
Thanks.
On Wed, Mar 27, 2024 at 10:45 PM Rui Barradas wrote:
Às 0
regards from
Ogbos
On Wed, Mar 27, 2024 at 8:44 AM Rui Barradas wrote:
Às 04:30 de 27/03/2024, Ogbos Okike escreveu:
Warm greetings to you all.
Using the tapply function below:
data<-read.table("FD1month",col.names = c("Dates","count"))
x=data$count
f<-factor(d
00
#> 4 2024-03-25 4.476190
#> 5 2024-03-26 6.538462
#> 6 2024-03-27 5.20
Also,
I'm glad to help as always but Ogbos, you have been an R-Help
contributor for quite a while, please post data in dput format. Given
the problem the output of the following is more than enough.
dput(h
at Windows can find R.exe and Rgui.exe without the full path name.
Hope this helps,
Rui Barradas
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and provide commented, minimal, self-contained, reproducible code.
Hello,
Thanks for the data but the code is missing from the attachment.
Can you please post your code? In an attachment or directly in the
e-mail body.
Rui Barradas
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ec <- sprintf("data%d.csv", 1:24)
data_list <- sapply(file_names_vec, read.csv, simplify = FALSE)
# access the 1st data.frame
data_list[[1L]]
# same as above
data_list[["data1.csv"]]
# same as above
data_list$data1.csv
Hope this helps,
Rui Barradas
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and provide commented, minimal, self-contained, reproducible code.
Hello,
From within RStudio you can always run the qualified names
from whithin
RStudio I close RStudio, write a script with the install.packages() call
and run it from a command window.
R -q -f "instscript.R"
This many times works better and it also works with Bioconductor's
BiocManager::install or with remotes'/devtools's install_github.
Hope
Sepal.Length, Sepal.Width, color = Species)) +
geom_point()
g + ylab(expression(paste(frac(
additive~HCO[3]^"-",
true~HCO[3]^"-"
Hope this helps,
Rui Barradas
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d this stranger, a call like the following
is expected.
tryCatch(stop("error"), error = function(e) e) |> str()
List of 2
$ message: chr "error"
$ call : language doTryCatch(return(expr), name, parentenv, handler)
- attr(*, "class")= chr [1:3] "simpl
theme(
panel.spacing = unit(0, "lines"),
strip.background = element_blank(),
strip.placement = "outside",
# this line was added by me, remove if not wanted
strip.text.x.bottom = element_text(face = "bold", size = 10),
axis.title.x = e
d linear regression for France", x = "Year", y
= "PISA score in mathematics") +
scale_y_continuous(limits=c(470,500),oob=scales::squish)
#
Le lundi 11 décembre 2023 à 23:38:06 UTC+1, Ben Bolker
a écrit :
On 2023-12-11 5:27 p.m., Daniel Nordlund w
ot;lm", formula = y ~ x) +
labs(
title = "Standard linear regression for France",
x = "Year",
y = "PISA score in mathematics"
) +
ylim(470, 500)
#> Warning message:
#> In max(ids, na.rm = TRUE) : no non-missing arguments to max;
returning -In
Às 16:30 de 07/12/2023, Rui Barradas escreveu:
Às 16:21 de 07/12/2023, Sorkin, John escreveu:
Colleagues,
I have a matrix of character data that represents date and time. The
format of each element of the matrix is
"2020-09-17_00:00:00"
How can I convert the elements into a valid R
as.POSIXct
Don't forget the underscore in the format.
as.POSIXct("2020-09-17_00:00:00", format = "%Y-%m-%d_%H:%M:%S")
Hope this helps,
Rui Barradas
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and provide commented, minimal, self-contained, reproducible code.
Hello,
Your link points to a GitHub repository, the package can be installed with
devtools::install_github(repo = "Sibada/sibadaR")
Hope this helps
Rui Barradas
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Às 17:57 de 30/11/2023, Rui Barradas escreveu:
Às 17:38 de 30/11/2023, Robert Baer escreveu:
I am having trouble using back ticks with the R extractor function
'predict' and an lm() model. I'm trying too construct some nice
vectors that can be used for plotting the two types of regression
ddle dataframe
arguement
CI.p = predict(mod2, newdata = newd, interval = 'prediction')# fail
Hope this helps,
Rui Barradas
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u", "Neu",
"Neu",
"Neu", "Neu", "Neu", "Neu", "Neu", "Neu", "Neu", "Neu",
"Pos",
"Pos", "Pos", "Pos", "Pos", "Pos&q
se_D, ymax = mean_D + se_D), fill =
"grey", alpha = 0.5) +
geom_line(aes(y = mean_D, color = C)) +
geom_point(aes(y = D, color = C)) +
scale_color_manual(name = "Concentration", values = clrs)
Hope this helps,
Rui Barradas
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code.
Hello,
Yes, CRAN is down.
I know last week there was an anouncement about a maintenance scheduled
but I cannot place that e-mail right now and don't remember the date
exactly so I cannot say for sure this is what is happening.
But it is probably a scheduled maintenance.
Rui Barradas
R file, rename it .txt?
See [1], section General Instructions for more on this
[1] https://www.r-project.org/mail.html#instructions
Hope this helps,
Rui Barradas
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e".
Then the grouped sums are computed.
suppressPackageStartupMessages(
library(dplyr)
)
dt1 %>%
mutate(date = as.Date(date, "%m/%d/%Y")) %>%
summarise(EnergykWh = sum(EnergykWh), .by = date)
#> date EnergykWh
#> 1 2016-01-14 11.98569
#> 2 2016-01-
ntercept = 130) +
scale_y_continuous(
name = "Blood glucose (mg/dL)",
breaks = seq(100, 230, by = 20)
) +
scale_shape_manual(
#name = "Conditions",
labels = c("Missed meds", "Missed exercise"),
values = c(20, 4),
na.translate = FALSE
5091
# keep the rows with values not NA
df_long <- df_long[complete.cases(df_long), , drop = FALSE]
# check the dimensions again
dim(df_long)
# [1] 15091
Hope this helps,
Rui Barradas
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, dfuture
# , lty = "dashed"
, lwd=2
, col = "black")
# if lines() is used for both the interpolated and extrapolated
# values you will have a gap between both fitted and predicted lines
# but it is closer to what you want
# get the fitted values first (interpo
th only
one row. But that is a very special case, the general case would be to
extract the column.
Hope this helps,
Rui Barradas
If you have another row in your x, say:
x <- data.frame(A=c(1,4), B=c(2,5), C=c(3,6))
then your code
x$C <- y[1]
returns an error.
If y has the same number of rows as x
nce, avoids repeated calls to ncol
nc <- ncol(agg)
cbind(agg[-nc], agg[[nc]])
#> A MeanS
#> 1 a 14.5 9.082951
#> 2 b 15.5 9.082951
#> 3 c 16.5 9.082951
# all is well
cbind(agg[-nc], agg[[nc]]) |> str()
#> 'data.frame':3 obs. of 3 variables:
#> $ A : c
g)
#> mydata$StepType: First
#> lm model parameter contrast
#>
#> Contrast S.E.LowerUppert df Pr(>|t|)
#> 1 2.99114 1.956013 -1.05518 7.037461 1.53 23 0.1399
#>
#> mydata$StepType: Second
#> lm model parameter contrast
#>
#&g
ct.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
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PLEASE do read the posting guide http://www.R-project.o
Às 19:35 de 18/10/2023, Leonard Mada escreveu:
Dear Rui,
On 10/18/2023 8:45 PM, Rui Barradas wrote:
split_chem_elements <- function(x, rm.digits = TRUE) {
regex <- "(?<=[A-Z])(?![a-z]|$)|(?<=.)(?=[A-Z])|(?<=[a-z])(?=[^a-z])"
if(rm.digits) {
stringr::s
about the workaround).
Q: My question focused if there is anything like is.numeric, but to
parse each element of a vector.
Sincerely,
Leonard
On 10/18/2023 6:53 PM, Rui Barradas wrote:
Às 15:59 de 18/10/2023, Leonard Mada via R-help escreveu:
Dear List members,
What is the best way to test
"CCl2CO2AlPO4SiO4Cl")
split_chem_elements(mol)
#> [[1]]
#> [1] "C" "Cl" "F"
#>
#> [[2]]
#> [1] "Li" "Al" "H"
#>
#> [[3]]
#> [1] "C" "Cl" "C" "O" "Al&q
Hello,
Given your date format, try
format = "%d.%m.%Y %H:%M"
Test with your date time:
x <- "2.11.2017 13:30"
as.POSIXct(x, format = "%d.%m.%Y %H:%M")
#> [1] "2017-11-02 13:30:00 WET"
as.POSIXct(su_seviyeleri_data$kayit_zaman, format = "%d.%m.%Y %
like it but
ifelse(rep(T, length(c(1,2,3))), c(1,2,3), c(5,6))
maybe you should use
max(length(c(1, 2, 3)), length(5, 6)))
instead, but it's still ugly.
Hope this helps,
Rui Barradas
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e were a couple of R files in there which I have since deleted but I am
still getting the same issue
Thankyou,
George
From: Rui Barradas
Sent: 10 October 2023 12:06
To: George Loftus ; r-help@r-project.org
Subject: Re: [R] Text showing when R is launched
Às 23:56
, reproducible code.
Hello,
Try deleting file
/Users/admin/.RData
It is restoring the previous session and this is many times a source for
problems.
Hope this helps,
Rui Barradas
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Às 10:09 de 06/10/2023, Chris Evans via R-help escreveu:
The reason I am asking is that I would like to mark areas on a plot
using geom_polygon() and aes(fill = variable) to fill various polygons
forming the background of a plot with different colours. Then I would
like to overlay that with
.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Hello,
RStudio is an IDE for R, not R itself.
That is a RStudio error and RStudio technical support [1] is better
suited to solve your problem.
[1] https://community.rstudio.com/
Hope this helps,
Rui Barr
aes(x = eruptions, y = waiting, label = waiting),
vjust = -1
) +
theme_cowplot()
Hope this helps,
Rui Barradas
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My sympathies for your loss.
Jim Lemon was a dedicated contributor to the R community and his answers
were always welcome.
Jim will be missed.
Rui Barradas
Às 23:36 de 04/10/2023, Jim Lemon escreveu:
Hello,
I am very sad to let you know that my husband Jim died on 18th September. I
s with
calls to library() when using non-base functionality.
Hope this helps,
Rui Barradas
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t)
Hope this helps,
Rui Barradas
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, min
matrix(1, 4, 4)
z <- lower.tri(diag(4), TRUE)
z[] <- apply(z, 2, as.integer)
H(x)
H(y)
H(z)
Hope this helps,
Rui Barradas
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PLEASE do rea
le.
Without the formula and method arguments, geom_smooth will print a
message, they are now made explicit.
suppressPackageStartupMessages({
library(dplyr)
library(ggplot2)
})
d_sum %>%
mutate(md = paste("2023", md, sep = "-"),
md = as.Date(md)) %>
graphs, only data.
Can you post the code have you tried?
Hope this helps,
Rui Barradas
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PLEASE do read the posting guide http://www.R
lue of prop.trend.test, makes it easier for the users to determine
the existence of trending and its direction.
If there are any other ways to do this, please let me know.
Thomas Subia
On Thursday, September 7, 2023 at 10:31:27 AM PDT, Rui Barradas
wrote:
Às 14:23 de 07/09
rs, patients)$estimate
#>prop 1prop 2prop 3prop 4
#> 0.9651163 0.9677419 0.9485294 0.8536585
smokers/patients
#> [1] 0.9651163 0.9677419 0.9485294 0.8536585
plot(smokers/patients, type = "b")
Hope this helps,
Rui Barradas
RStudio questions to the RStudio support service, they
answer quickly and the answers are generally good.
It's written at the bottom of the attached image that the workspace was
loaded from file
C:/WSI/.RData
Close RStudio, remove this file and restart. See if it solved it.
Hope this he
replaced by the value in the column which is non zero..
I tried append and merge but fail to get what I want.
Hello,
That's a case for ?pmax:
x1 <- c(116,0,115,137,127,0,0)
x2 <- c(0,159,0,0,0,159,127)
pmax(x1, x2)
#> [1] 116 159 115 137 127 159 127
Hope this he
differently, even though they all
use mean(na.rm = TRUE) to calculate the group stats.
Best wishes,
Ivan
On 04/09/2023 13:46, Rui Barradas wrote:
Às 10:44 de 04/09/2023, Ivan Calandra escreveu:
Dear useRs,
I have just stumbled across a behavior in aggregate() that I cannot
explain. Any help
s of the other numeric
columns, just of those two.
# define a vector of columns of interest
cols <- c("Length", "Width", "RAWMAT")
# 1) Simple aggregation with 2 variables, select cols:
aggregate(cbind(Length, Width) ~ RAWMAT, data = my_data[cols], FUN =
me
,
It seems that you have data that in tabular form is one column per
answer, so you would end up with 30 columns, maybe an extra id column.
Can you post sample data? If not, make up the answers and post the
answers of the first 6 individuals or so.
Hope this helps,
Rui Barradas
and anyone
willing to check them can.
[1] https://cran.r-project.org/web/packages/
Hope this helps,
Rui Barradas
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PLEASE do read the posting
geom_line(data = fit, aes(x, ymax), linetype = "dashed", linewidth = 1)
Hope this helps,
Rui Barradas
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PLEASE do read the posti
generic to have methods processing
inputs of different classes in ways specific to those classes.
Hope this helps,
Rui Barradas
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PL
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Hello,
That erro
ked it but it's the slowest of the three, OP's, Iris' (the
fastest).
Hope this helps,
Rui Barradas
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PLEASE do read the posting guide http://www.R-pro
atrix(dat2[match(dat1[,1], dat2[,1]),-1])
Res <- data.frame(ID = dat1[,1], Index = multiplication)
# this is what I find simpler
# the method being called is cbind.data.frame
Res2 <- cbind(dat1[1], Index = multiplication)
identical(Res, Res2)
#> [1] TRUE
Hope this helps,
Rui Barradas
__
e(
Year = rep((1990:1995),8),
Flow = round(rnorm(48,50,10),3),
Stat = rep(c(rep("Tweed",6), rep("Tay",6)),4),
Metric = rep(c("AMAX","Mean","AMIN","Median"),each=12)
)
ggplot(mock, aes(Year,Flow, group = factor(Stat), colour
coord_cartesian(ylim = c(0, 10)) +
geom_line()+
geom_point()+
scale_color_manual(name = "Stat", values = cb8[4:5])+
theme_bw()
Hope this helps,
Rui Barradas
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geom_point() +
stat_smooth(
formula = y ~ x,
method = glm,
method.args = list(family = binomial),
se = FALSE
)
Hope this helps,
Rui Barradas
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84
# http://home.brisnet.org.au/~bgreen/Data/Hanson2/
# 749
# matches the question's number
sum(lengths(success))
# [1] 833
Hope this helps,
Rui Barradas
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.
The fundamental machine is intelligence.
Fernando Pessoa, 1926
Revista de Comércio e Contabilidade, nº 4. Lisboa, 25-4-1926.
(Magazine of Commerce and Accounting, nº 4. Lisbon, 25-4-1926)
Rui Barradas
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lo,
Maybe this [1] is relevant.
[1]
https://community.rstudio.com/t/meaning-of-common-message-when-install-a-package-there-are-binary-versions-available-but-the-source-versions-are-later/2431
Hope this helps,
Rui Barradas
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(df, aes(x = Time, y = ddC, colour = mM, group = mM)) +
geom_line() +
geom_errorbar(aes(ymin = ddC - SD, ymax = ddC + SD), width = 0.1) +
geom_point(size = 6) +
geom_hline(aes(yintercept = 0)) +
scale_colour_manual(values = COLS) +
ggtitle("Exposure") +
cible code.
Hello,
I had tested the code with a couple of PDF's and it ran with no errors
or warnings.
That error is telling that a "}" is not balanced but in my code they all
are, RStudio checks it automatically.
Can you try to check in an editor with syntax highlighting?
Hope th
:file_path_sans_ext(files)
new_names <- paste(new_names, "txt", sep = ".")
setNames(x, new_names)
}
# apply function
# note that my test files are in "~/Temp"
txts <- convertpdf2txt(here::here("~", "Temp"))
names(txts)
Hope this helps,
Rui B
Às 20:55 de 03/07/2023, Rui Barradas escreveu:
Às 20:26 de 03/07/2023, Sorkin, John escreveu:
Jeff,
Again my thanks for your guidance.
I replaced dimnames(myvalues)<-list(NULL,c(zzz))
with
colnames(myvalues)<-zzz
and get the same error,
Error in dimnames(x) <- dn :
length of 'dim
g, name)
print(string)
}
#> [1] "xxx1"
#> [1] "xxx1" "xxx2"
# Now creation of xxx1 and xxx2 does work
string
#> [1] "xxx1" "xxx2"
# 2. create a vector of the appropriate length beforehand, my preferred
string <- character(2)
for (j i
d, minimal, self-contained, reproducible code.
Hello,
You don't need so many calls to paste, one is enough.
And you don't need the for loop at all, paste and paste0 are vectorized.
myvalues <- matrix(nrow=2,ncol=4)
cnames <- paste0("xxx&q
=Conc)) +
geom_point(size=6) +
geom_line(aes(group = Conc)) +
scale_colour_manual(values = c("darkslategray3", "darkslategray4",
"deepskyblue4")) +
ggtitle("Working example") +
xlab(expression(bold("Time (h)"))) +
ylab(expression(
tor(Annee)))+
geom_bar(position="dodge",stat="identity")+
ylab("Simulation Progress (%)") +
facet_wrap(~Type,nrow=3)
myplot + theme(panel.grid.major = element_blank(),
legend.title=element_blank(), panel.grid.minor = element_blank()
o? I expected the function to remove 3 rows of the
dataframe.
I do not know the reason.
On Mon, Jun 12, 2023 at 5:16 PM Rui Barradas wrote:
Às 23:13 de 12/06/2023, javad bayat escreveu:
Dear Rui;
Many thanks for the email. I tried your codes and found that the length
of
the "Values" a
data3 = data2[!grepl(c("_esmdes","_Des Section","0"), data2$Layer),]
Warning message:
In grepl(c("_esmdes", "_Des Section", "0"), data2$Layer) :
argument 'pattern' has length > 1 and only the first element will be
used
How
Às 13:18 de 11/06/2023, Rui Barradas escreveu:
Às 22:54 de 11/06/2023, javad bayat escreveu:
Dear Rui;
Many thanks for your email. I used one of your codes,
"data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works
correctly for me.
Actua
2")] <- "Agri";
...
...
...
.
Is there any other way to expand the code in order to consider all of the
levels simultaneously? Like the below code:
data2$LU[which(data2$Layer == c("Level 1","Level 2", "Level 3", ...))] <-
c("Park", "Agri&qu
Layer == "Level 12")
data2$LU[i] <- "Park"
# equivalent one-liner
data2$LU[which(data2$Layer == "Level 12")] <- "Park"
Hope this helps,
Rui Barradas
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quot;Jan 2021" "Mar 2021" "Apr 2021"
Hope this helps,
Rui Barradas
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PLEASE do read the posting guide http://www.
r
data = w %>% filter(year(date) %in% 2010:2015)
# base R
data = subset(w, year(date) %in% 2010:2015)
Hope this helps,
Rui Barradas
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but like this it is not possible to do so.
Rui Barradas
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide
ve or not NA's by adding a
na.rm argument:
my_fun <- function(wd1, ws1, na.rm = FALSE) {
[...]
mean_u <- mean(u_component, na.rm = na.rm)
mean_v <- mean(v_component, na.rm = na.rm)
[...]
}
aggregate(wd ~ day + month, data=df, FUN = my_fun, ws1 = ws, na.rm = TRUE)
ate(name = factor(name, levels = c("K", "J"))) %>%
ggplot(aes(Year, value, color = name)) +
geom_smooth(
formula = y ~ x,
method = lm,
se = FALSE
) +
geom_point() +
scale_color_manual(values = c(J = "red", K = "b
//www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Hello,
Are you looking for something like this?
DFA <- data.frame(id = 1:2)
DFA[["ar"]] <- array(1:8, c(2,2,2))
DFA$ar[1, , ]
#> [,1] [,2]
#> [1,]1 5
#> [2,
uEl-Makarim Aboueissa, PhD*
*Professor, Mathematics and Statistics*
*Graduate Coordinator*
*Department of Mathematics and Statistics*
*University of Southern Maine*
On Sat, Apr 29, 2023 at 8:05 AM Rui Barradas wrote:
Às 14:09 de 28/04/2023, AbouEl-Makarim Aboueissa escreveu:
*R: *Grubbs Test to de
2.667 NA 1 486 217 275
# tried to use grubbs.test() on a single column of the dataframe, but
# still not working
grubbs.test(datafortest$X, type = 11)
#>
#> Grubbs test for two opposite outliers
#>
#> data: datafortest$X
#> G = 4.6640014, U = 0.0091756, p-value = 0.0286
-- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Hello,
Please post the output of
dput(datafortest)
your data is difficult to read int
ave a closer look...
Thanks for reporting this!
Achim
On Fri, 28 Apr 2023, Rui Barradas wrote:
Às 06:01 de 28/04/2023, Stevie Pederson escreveu:
Hi,
I'm not sure if this is a bug or a feature, but after updating to
Rv4.3, if
requesting two colours from hcl.colors() you now get the same colour
tw
datasets methods base
#
# loaded via a namespace (and not attached):
# [1] compiler_4.2.3
Hope this helps,
Rui Barradas
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PLE
Hello,
Às 09:42 de 21/04/2023, Jeff Newmiller escreveu:
0
Somewhat cryptic...
Rui Barradas
On April 21, 2023 4:08:08 AM GMT+09:00, Dr Eberhard W Lisse
wrote:
There is at least one outliers package on CRAN.
el
On 20/04/2023 20:43, AbouEl-Makarim Aboueissa wrote:
Dear All: *please
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