i have converted my data into date format like below:
day=as.Date(originaldate,%m/%d/%Y)
day[1:5]
[1] 2008-04-12 2011-07-02 2011-09-02 2008-04-12 2008-04-12
I wish to select only those observations from 2007 to 2009, how can I
select from this list?
[[alternative HTML version
Hi there,
This is the first time I use this forum, and I want to say from the start I am
not a skilled programmer. So please let me know if the question or code were
unclear!
I am trying to bootstrap an interaction (that is my test statistic) using the
package boot. My problem is that for
Hi,
Possibly, FAQ 7.31
Using the same example:
set.seed(24)
df- data.frame(x=sample(seq(0.25,4.25,by=.05),1e5,replace=TRUE),y=
sample(seq(0.10,1.05,by=.05),1e5,replace=TRUE),z=rnorm(1e5))
dfOld- df
df[,1:2]- lapply(df[,1:2],function(x) sprintf(%.2f,x))
x1- c(1.05,2.85,3.40,4.25,0.25)
y1-
Hi,
carbon.fit = expand.grid(list(x=seq(0, 5, 0.01), y=seq(0, 5, 0.01)))
dim(carbon.fit)
#[1] 251001 2
xtNew-sprintf(%.2f,xt)
ytNew- sprintf(%.2f,yt)
carbon.fit[]- lapply(carbon.fit,function(x) sprintf(%.2f,x))
res-do.call(rbind,lapply(seq_along(xtNew),function(i)
I want to do Agglomerative Hierarchical clustering using complete linkage
method in R using the function agnes or hclust.
1. Can i do a cluster analysis of h=(n+p+1)/2 out of n observation? note that
p=nomber of variables(dependent and independent)
2. Can i plot the dendrogram and get the
I have a method which is not so smart --use grep to match the pattern.
for example:
dates - c(02/27/92, 02/27/92, 01/14/92, 02/28/92, 02/01/91)
day - as.Date(dates, %m/%d/%y)
day:
[1] 1992-02-27 1992-02-27 1992-01-14 1992-02-28 1991-02-01
If I want to search for 1991, I can use:
grep(1991-*, day)
On Wed, 03 Jul 2013, Ye Lin ye...@lbl.gov writes:
Hey All,
I want to standardize my timestamp which is formatted as hh:mm:ss
My data looks like this:
Date Time
01/01/2013 00:09:01
01/02/2013 00:10:14
01/03/2013 00:11:27
01/04/2013 00:12:40
01/05/2013 00:13:53
01/06/2013
On 04/07/2013 08:04, Dante.py wrote:
I have a method which is not so smart --use grep to match the pattern.
for example:
dates - c(02/27/92, 02/27/92, 01/14/92, 02/28/92, 02/01/91)
day - as.Date(dates, %m/%d/%y)
day:
[1] 1992-02-27 1992-02-27 1992-01-14 1992-02-28 1991-02-01
If I want to search
Dear All,
I am playing with different models/packages (random forest, logistic
regression, gbm etc...) for a problem of binomial regression (i.e. the
outcome is 0/1, dead or alive etc...).
I have used in the past the multinom function from the nnet library which
uses the neural networks for
They are really good methods. Thank you very much.
Could I ask one more question. Is there obvious difference between these
two methods?
2013/7/4 Prof Brian Ripley rip...@stats.ox.ac.uk
On 04/07/2013 08:04, Dante.py wrote:
I have a method which is not so smart --use grep to match the
Thanks for the advise Prof Nash, but I'm not sure if I understood it right.
I managed to make a new model based on what I think you meant. What I did
is; I created 3 variables (cat1, cat2, cat3) one for each category with
either the value 1 or 0 and added these to the model so they work as
On 04/07/2013 11:36, Dante.py wrote:
They are really good methods. Thank you very much.
Could I ask one more question. Is there obvious difference between these
two methods?
Yes. It is obvious that the type of x differs.
2013/7/4 Prof Brian Ripley rip...@stats.ox.ac.uk
I am trying to download packages and the message I get is as follows
utils:::menuInstallPkgs()
--- Please select a CRAN mirror for use in this session ---
Warning: unable to access index for repository
http://cran.ms.unimelb.edu.au/bin/windows/contrib/3.0
Warning: unable to access index for
I am trying to download packages and the message I get is as follows
Warning: unable to access index for repository
http://cran.ms.unimelb.edu.au/bin/windows/contrib/3.0
Your internet connection is probably either not working or (more likely)
blocked by firewall or site access policies.
Dear R users,
I have a dataset with two ordered variables, tr_x1 and tr_y1. A crosstable of
them can bee seen below.
tr_x1
tr_y1 -101
-1 629 100 629
0 1396 4353 1443
1 668 126 655
It is clear that if tr_x1 is 0, it has an effect on tr_y1. A chi-square
statistic
I often find myself (wanting t)o constructing lists or data.frames like so:
#Find files in subdirs
ii - 0
for (ix in id) {
ii - ii + 1
if (ii == 1) {
fl - list(basename(ix) = list.files(ix))
} else {
fl - c(fl, list(basename(ix) =
On 04/07/2013 12:59, Dániel Kehl wrote:
Dear R users,
I have a dataset with two ordered variables, tr_x1 and tr_y1. A crosstable of
them can bee seen below.
tr_x1
tr_y1 -101
-1 629 100 629
0 1396 4353 1443
1 668 126 655
It is clear that if tr_x1 is 0, it
I often find myself (wanting t)o constructing lists or
data.frames
Apologies; previous post should have said Read R inforno on 'Growing Objects'
and should have added the URL:
http://www.burns-stat.com/pages/Tutor/R_inferno.pdf
S Ellison
I often find myself (wanting t)o constructing lists or
data.frames:
Try something like
fl-list()
for (ix in id) {
fl[[basename(ix)]] - list.files(ix)
}
But read R Inferno on inrementing objects first. It isn't efficient in memory
terms (unless that's improved in recent versions of R)
Dear Prof Ripley,
could you be just a little more specific?
Thanks a lot
daniel
Feladó: Prof Brian Ripley [rip...@stats.ox.ac.uk]
Küldve: 2013. július 4. 14:14
To: Dániel Kehl
Cc: r-help
Tárgy: Re: [R] polr?
On 04/07/2013 12:59, Dániel Kehl wrote:
Dear
I often find myself (wanting t)o constructing lists or
data.frames
Apologies; previous post should have said Read R inforno on 'Growing
Objects' and should have added the URL:
http://www.burns-stat.com/pages/Tutor/R_inferno.pdf
S Ellison
On Jul 4, 2013, at 14:38 , Dániel Kehl wrote:
Dear Prof Ripley,
could you be just a little more specific?
He'll likely find that difficult.
It's sort of like if you had data like this
25 75
75 25
25 75
and did a trend test. The trend test _assumes_ that the effect is increasing,
and
Hello Folks,
I have a database of 2000+ days with 35 observations each. I am trying to
modeling a time series by day, but it seems a problem that I dont have the
time of the observation. I achieve something interesting by using the
barplot function, but I`d rather working with ggplot2, since I
Hi,
You could try:
day-as.Date(c(2008-04-12,2011-07-02,2011-09-02,2008-04-12,2008-04-12))
indx-gsub(-.*,,day)
day[indx=2007 indx=2009]
#[1] 2008-04-12 2008-04-12 2008-04-12
#or
library(xts)
xt1- xts(seq_along(day),day)
index(xt1[2007/2009])
#[1] 2008-04-12 2008-04-12 2008-04-12
#or
I think we need to see some of the original data. See ?dput for how to supply
data in a email.
We probably don't need all the data, I'd suggest perhaps 100 rows or so. Try
dput(head(yourdata, 100))
BTW what is last?
John Kane
Kingston ON Canada
-Original Message-
From:
Heres the function last
last
function (x, ...)
{
UseMethod(last)
}
environment: namespace:xts
I can share 100 rows if you want, but I don`t you will find it useful, since
I want to perform my time-series on a single row. Here`s one:
dezdiff.dt[nrow(dezdiff.dt),]
datetime
Thanks Alex but the idea is to use dput() for the data so that readers can
simply copy and paste it into R and have a working dataset. I have a very
small data.frame called dd.
Var1 Var2
1 A1
2 B1
3 C1
4 A2
5 B2
6 C2
7 A3
8 B3
9
Also
yrs - as.Date(c(2007-01-01, 2009-12-31))
day[day=yrs[1] day=yrs[2]]
[1] 2008-04-12 2008-04-12 2008-04-12
Should be fast if there are many days to process since it converts
the search criteria, not the data.
-
David L Carlson
Associate Professor of
Hi folks
I have implemented a model of a neuron using Hodgkin Huxley equations in
both R and MatLab. My preference is to work with R but R is not giving me
the correct results. I also can't use ode45 as it just seems to go into an
indefinite loop. However, the MatLab implementation work fine with
On 04-07-2013, at 17:15, Jannetta Steyn janne...@henning.org wrote:
Hi folks
I have implemented a model of a neuron using Hodgkin Huxley equations in
both R and MatLab. My preference is to work with R but R is not giving me
the correct results. I also can't use ode45 as it just seems to go
Berend Hasselman bhh at xs4all.nl writes:
On 04-07-2013, at 17:15, Jannetta Steyn jannetta at henning.org wrote:
Hi folks
I have implemented a model of a neuron using Hodgkin Huxley equations in
both R and MatLab. My preference is to work with R but R is not giving me
the
Hi Ben and others
I don't quite know how to explain the doesn't work in more detail without
any visual aid. When you run the two scripts it is easy to see the
difference. MatLab produces a line on x= -55. This is what I expect - a
more or less straight line. R on the other hand the result drops
Dear R users,
Please help me with some documentation for newbie about R programming,
algorithms, create iterative C++ function (like for, while, if , etc).
Thank you very much!
--
---
Catalin-Constantin ROIBU
Lecturer PhD, Forestry engineer
Forestry Faculty of Suceava
Str. Universitatii no.
On 04-07-2013, at 18:42, Jannetta Steyn janne...@henning.org wrote:
Hi Ben and others
I don't quite know how to explain the doesn't work in more detail without
any visual aid.
You said that R got into an indefinite loop, whatever that maybe.
When you run the two scripts it is easy to see
On Jul 4, 2013, at 19:11 , Berend Hasselman wrote:
On 04-07-2013, at 18:42, Jannetta Steyn janne...@henning.org wrote:
Hi Ben and others
I don't quite know how to explain the doesn't work in more detail without
any visual aid.
You said that R got into an indefinite loop, whatever
Dear List,
please provide some input on the following:
we have
a -c(0,1,2,3)
b -c(4,5,6,7)
d -cbind(a,b)
k -c(0,0,2,2,3,3,2)
k in this case consists of some values of d[,1] in a random sequence. What
I am trying to do is to create an object f that would have the values of
d[,2] in it based on
On 04-07-2013, at 19:56, peter dalgaard pda...@gmail.com wrote:
On Jul 4, 2013, at 19:11 , Berend Hasselman wrote:
On 04-07-2013, at 18:42, Jannetta Steyn janne...@henning.org wrote:
Hi Ben and others
I don't quite know how to explain the doesn't work in more detail without
any
I think this is what you are looking for
f - d[match(k, d[,1]), 2]
f
[1] 4 4 6 6 7 7 6
-
David L Carlson
Associate Professor of Anthropology
Texas AM University
College Station, TX 77840-4352
-Original Message-
From: r-help-boun...@r-project.org
Hi,
You could use:
d1- data.frame(a,b)
k1-data.frame(a=k)
library(plyr)
join(k1,d1,by=a)[,2]
#[1] 4 4 6 6 7 7 6
A.K.
- Original Message -
From: Andras Farkas motyoc...@yahoo.com
To: r-help@r-project.org
Cc:
Sent: Thursday, July 4, 2013 2:09 PM
Subject: [R] help on selecting values of
Dear Marc,
Let me see if I understand the type of data you have. You say that you have 5
experiments. And within each experiment, you have n subjects and for each
subject, you have data in the form described in your post. Now for each
subject, you want to calculate some kind of measure that
On Jul 4, 2013, at 20:14 , Berend Hasselman wrote:
On 04-07-2013, at 19:56, peter dalgaard pda...@gmail.com wrote:
On Jul 4, 2013, at 19:11 , Berend Hasselman wrote:
On 04-07-2013, at 18:42, Jannetta Steyn janne...@henning.org wrote:
Hi Ben and others
I don't quite know how to
Hello,
I have a dataset of 371 observations.
When I run coxph with numeric variables it works fine.
However, when I try to add factor variables it returns Ran out of
iterations and the model did not converge
There is something very strange with the factors - some of them should
actually be
Hi,
I'd like to draw a lattice barchart of means with error bars to show
the standard deviation. I have the barchart, how do I add the error
bars?
require(datasets)
require(lattice)
x - aggregate(weight ~ Diet, ChickWeight, function(x) c(mean=mean(x),
sd=sd(x)))
barchart(weight[,'mean'] ~ Diet,
Please (for crying out loud!) use a meaningful subject line!!! This
list is called r-help!!! Using a subject line of Help is completely
vacuous.
cheers,
Rolf Turner
On 04/07/13 20:33, Aboagye-sarfo, Patrick wrote:
I am trying to download packages and the message I get is as
Well, it implies either 2help or help^2, right? In this case, it
seems oddly appropriate, as really needing help getting packages is
sort of greater in a need hierarchy than coding help, as the latter
is largely useless without the former.
At one point, I seem to recall discussion of whether
Shaun:
I understand that this type of plot is standard in many disciplines,
but it really is awful (google on 'Dynamite plots' for some more
erudite perspectives). Have you considered bwplot() for your
unaggregated data instead?
(No need to reply. It's July 4, and I'm just waving a little flag
Hi All
Thanks for all the comments. I have looked at everything you have pointed
out and this is the situation at the moment:
I don't think so.
In the R script you have
init = c(v_axon_AB=-55,mNa_axon_AB=1,hNa_axon_AB=0,mK_axon_AB=1)
That is not the same as in your Matlab script. To make
On Jul 3, 2013, at 4:54 PM, Erin Hodgess wrote:
Dear R People:
I am experimenting with S4 classes and methods but am having trouble with
setting up a class.
Here is an example:
buzz - setClass(buzz,slots=c(x=matrix),
+ validity - function(object) {
+
On Jul 3, 2013, at 7:19 PM, Sol Lago wrote:
Hi there,
This is the first time I use this forum, and I want to say from the start I
am not a skilled programmer. So please let me know if the question or code
were unclear!
I am trying to bootstrap an interaction (that is my test
On Jul 5, 2013, at 00:41 , Jannetta Steyn wrote:
Hi All
Thanks for all the comments. I have looked at everything you have pointed
out and this is the situation at the moment:
I don't think so.
In the R script you have
init = c(v_axon_AB=-55,mNa_axon_AB=1,hNa_axon_AB=0,mK_axon_AB=1)
xt- c(1.05, 2.85, 3.40, 4.25, 0.25, 3.05, 3.70, 0.20, 0.30, 0.70, 1.05,
1.20, 1.40, 1.90,
2.70, 3.25, 3.55, 4.60, 2.05, 2.15, 3.70, 4.85, 4.90, 1.60, 2.45, 3.20, 3.90,
4.45)
yt- c(0.25, 0.10, 0.90, 0.25, 1.05, 1.70, 2.05, 2.90, 2.35, 2.60, 2.55,
2.15, 2.75, 2.05,
2.70, 2.25, 2.55,
I'd like to preface this answer by suggesting that if you have multiple
measurements within subjects then you should possibly be thinking about
using mixed-effects models. Here you have a balanced design and seem
to be thinking about a constrained bootstrap, but I don't know whether
the resulting
I think that in the case of a 2*2 balanced, replicated design such as
this one, interpreting the interaction should be safe.
Cheers
Andrew
On Fri, Jul 5, 2013 at 9:38 AM, David Winsemius dwinsem...@comcast.net wrote:
On Jul 3, 2013, at 7:19 PM, Sol Lago wrote:
Hi there,
This is the first
Hi,
It is not the easiest to follow code, but when I was working at UCLA,
I wrote a page demonstrating a multilevel bootstrap, where I use a two
stage sampler, (re)sampling at each level. In your case, could be
first draw subjects, then draw observations within subjects. A strata
only option
Josh's comment prompted me to check mty go-to reference. Davison and
Hinckley (1997 Section 3.8) recommend sampling the Subjects, but not
within the Subjects.
Cheers
Andrew
On Thu, Jul 04, 2013 at 05:53:58PM -0700, Joshua Wiley wrote:
Hi,
It is not the easiest to follow code, but when I was
Dear Prof. Nash,
I tried to run nls with the nlxb function and as you mention it is fairly
slower in terms of running the code. However, if I would have used this
function earlier I would have saved a lot of time trying to find the start
values. The output looks a little bit sloppy but I think it
dear R users
is it appropriate to use a Log likelihood ratio (G-test) test of independence
when dealing with repeated categorical responses (e.g. 2 by 2 table) instead of
the McNemar test?
thanks
fer
[[alternative HTML version deleted]]
__
I have a character vector that I'm using to label ticks in a dotchart. Some
of the elements in the vector have an asterisk (*) where a Greek Delta
needs to be placed when the plot is generated. Here's a simple example:
x - 1:4
x.lab - c(a*a, bbb, c*c, ddd)
dotchart(x, labels = x.lab)
The first
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