it looks great, thank you very much Jeff for your time and kind help !
On Wed, Jul 18, 2018 at 7:51 PM, Jeff Newmiller
wrote:
> The traditional (SQL) way to attack this problem is to make the data
> structure simpler so that faster comparisons can be utilized:
>
>
> A <-
The traditional (SQL) way to attack this problem is to make the data
structure simpler so that faster comparisons can be utilized:
A <- data.frame(z=c("a*b", "c*d", "d*e", "e*f"), t =c(1, 2, 3, 4))
B <- data.frame(z=c("a*b::x*y", "c", "", "g*h"), t =c(1, 2, 3, 4))
Dear Riley,
thank you very much for your help and solution. I got some inspiration from
stackoverflow website,
and I did use sqldf library. It looks that the formula below works too.
Thanks a lot !
sqldf("select B.*, A.* from B left join A on instr(B.z, A.z)")
On Wed, Jul 18, 2018 at 3:57
Thanks a lot ! It looks that I am getting the same results with :
B %>% regex_left_join(A, by = c(z = 'z'))
On Wed, Jul 18, 2018 at 3:57 PM, Riley Finn wrote:
> please may I ask for a piece of advise regarding merging two dataframes :
>> A <- data.frame(z=c("a*b", "c*d", "d*e", "e*f"), t =c(1,
Dear all,
please may I ask for a piece of advise regarding merging two dataframes :
A <- data.frame(z=c("a*b", "c*d", "d*e", "e*f"), t =c(1, 2, 3, 4))
B <- data.frame(z=c("a*b::x*y", "c", "", "g*h"), t =c(1, 2, 3, 4))
function of the criteria :
if "the elements in the 1st column of A could be
Hi
OTOH I wonder why cbind gives error as OP told us
x - data.frame(x = 1:5)
y - data.frame(y = 6:15)
merge(x,y)
cbind(x,y)
Gives different results but without any error.
Regards
Petr
On Thu, Aug 2, 2012 at 4:52 PM, Ayyappa Chaturvedula
ayyapp...@gmail.com wrote:
Michael,
Thank you
Dear All,
I want to create a dataset for a NONMEM simulation. I have a dataframe with
individual PK parameters and want to create a dosing sceinario in a second
dataframe. I want to merge them both so that every individiual's PK
parameters are combined with the dosing scenario into one. I do not
You can merge without a common variable:
x - data.frame(x = 1:5)
y - data.frame(y = 6:10)
merge(x,y)
works just fine (for one set of expectations)
If you need more help, please do make a reproducible example (as
requested of all R-help posts): the instructions here might help
On Thu, Aug 2, 2012 at 4:52 PM, Ayyappa Chaturvedula
ayyapp...@gmail.com wrote:
Michael,
Thank you for this , it worked. I was thinking by is a required argument
in merge function.
Well, it is required in a strict sense, but it has a default value
(defaulting to the shared names) so _you_
Dear R-ers,
I feel I am close, but can't get it quite right.
Thanks a lot for your help!
Dimitri
# I have 2 data frames:
x-data.frame(a=c(aa,aa,ab,ab,ba,ba,bb,bb),b=c(1:2,1:2,1:2,1:2),d=c(10,20,30,40,50,60,70,80))
Hi Dimitri,
Try creating a key for x and y and then merging the result by that
variable:
x$key - with(x, paste(a, b, sep = /))
y$key - with(y, paste(a2, b, sep = /))
merge(x, y, by = 'key')[, c(2:4, 8:9)]
HTH,
Jorge.-
On Wed, Jul 11, 2012 at 6:28 PM, Dimitri Liakhovitski wrote:
Dear R-ers,
Jorge, thank you!
that seems to be working, but unfortunately in real life I have
thousands of variables (except for a, a2, a3 and b) so that manually
selecting columns (as in c(2:4, 8:9)) would be too difficult...
Dimitri
On Wed, Jul 11, 2012 at 6:36 PM, Jorge I Velez jorgeivanve...@gmail.com
This should do the trick :
colnames(y)[1:2]=c(a,a)
y2=rbind(y[,-1], y[,-2]) #duplicating the y matrix so the identifiers
are only in 1 column
merged = merge(x,y2)
merged
a b d e1 e2
1 aa 1 10 100 101
2 aa 2 20 200 201
3 ab 1 30 100 101
4 ab 2 40 200 201
5 ba 1 50 300 301
6 ba 2 60 400
Hello,
About many columns like 'e1' and 'e2' I don't know but with the provided
example the following does NOT depend on them, only on 'a', 'b' and 'a2'
and 'a3'.
z - lapply(c(a2, a3), function(cc) merge(x, y, by.x=c(a, b),
by.y=c(cc, b)))
z - lapply(seq_along(z), function(i)
Thanks a lot, everyone for your helpful suggestions!
Eloi, this is very elegant - thank you!
I did not know 2 columns are allowed to have the same names! Always
good to learn something new.
Thanks again!
Dimitri
On Wed, Jul 11, 2012 at 6:58 PM, Mercier Eloi emerc...@chibi.ubc.ca wrote:
This
Not sure if its guaranteed but this sqlite join does seem to preserve
the order of the first data frame.
library(sqldf)
BOD
Time demand
118.3
22 10.3
33 19.0
44 16.0
55 15.6
67 19.8
BODrev - BOD[6:1,]; BODrev
Time demand
67 19.8
55 15.6
4
Hi All,
I want to merge two datasets by column ID and I don't want the result to
be sorted by ID. I am doing the following:
z = merge(x, y, by = ID, sort=F)
The result is not sorted by ID. But (as oppose to what I expected) it is
not even in the original order of either x or y.
Hi there,
You can add a order column on x or y and after use this field to order z.
Like
z-z[order(z$orderfield),]
To generate a order on x or y you can do something like
x$xorder-1:nrow(x)
cheers
milton
On Thu, Dec 24, 2009 at 2:26 PM, utkarsh.sing...@global-analytics.comwrote:
Hi All,
the order or what order is it
taking when I specified sort=F.
Regards
Utkarsh
Original Message
Subject: Re: [R] help in merging
From: milton ruser milton.ru...@gmail.com
Date: Fri, December 25, 2009 1:38 am
To: utkarsh.sing...@global-analytics.com
Cc
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