On Mon, 13 Nov 2023 at 21:32, Bùi Gia Nghĩa wrote:
>
> Hi!
> I have used Sage Cell Server to integrate the function (ln(x)^2 - 1) / (x *
> ln(x)). It should resulted in (ln(x)^2) / 2 - |ln(ln(x))| + C, as noted by my
> textbook and Wolfram|Alpha, but instead resulted in 1/2*log(x)^2 -
>
Oh that's why! Thank you because that is exactly the problem!
On Tue, Nov 14, 2023, 4:54 AM John H Palmieri
wrote:
> Isn't log(log(x)^2) = 2 * log(log(x))? Is this your concern, or is it the
> absolute value?
>
> On Monday, November 13, 2023 at 1:32:11 PM UTC-8 Bùi Gia Nghĩa wrote:
>
>> Hi!
>>
Isn't log(log(x)^2) = 2 * log(log(x))? Is this your concern, or is it the
absolute value?
On Monday, November 13, 2023 at 1:32:11 PM UTC-8 Bùi Gia Nghĩa wrote:
> Hi!
> I have used Sage Cell Server to integrate the function (ln(x)^2 - 1) / (x
> * ln(x)). It should resulted in (ln(x)^2) / 2 -
Hi!
I have used Sage Cell Server to integrate the function (ln(x)^2 - 1) / (x *
ln(x)). It should resulted in (ln(x)^2) / 2 - |ln(ln(x))| + C, as noted by
my textbook and Wolfram|Alpha, but instead resulted in 1/2*log(x)^2 -
1/2*log(log(x)^2).
(I do notice that SageMath use log(a) to denote
