Yes:
advertisement_show:
url: /:sf_culture/advertisement/show/:id/:slug/*
class: sfPropelRoute
options: { model: Advertisement, type: object }
param: { module: advertisement, action: show }
requirements:
sf_method: [get, post]
sf_culture: (?:en|es|de|fr|nl)
On 14 jul, 15:32, Gábor Fási <maerl...@gmail.com> wrote:
> Is your route declared as sfPropelRoute/sfDoctrineRoute?
>
> On Wed, Jul 14, 2010 at 15:23, HAUSa
>
> <jeroen_heeft_behoefte_aan_r...@hotmail.com> wrote:
> > I can't use genUrl like this:
> > genUrl('advertisement_show', $Advertisement)
> > where $Advertisement is the object for the sfObjectRoute
>
> > The only way to do so is to call it like this:
> > genUrl('advertisement_show?id=' . $Advertisement->getId() . '&slug=' .
> > $Advertisement->getSlug())
>
> > But that, ofcourse, kills the flexibility of the routing system!
> > How can I do the top solution with getUrl?
>
> > --
> > If you want to report a vulnerability issue on symfony, please send it to
> > security at symfony-project.com
>
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>
--
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