It says:
The "/:sf_culture/advertisement/show/:id/:slug" route has some missing
mandatory parameters (:id, :slug).
This means it doesn't receive the object.
While I actually do give it (and url_for would accept it this way):
genUrl('advertisement_show', $oAdvertisement, true)
Thanks for thinking with me!
On 16 jul, 10:30, Gábor Fási <maerl...@gmail.com> wrote:
> What's the error message? Did you try removing the *?
>
> On Fri, Jul 16, 2010 at 10:19, HAUSa
>
> <jeroen_heeft_behoefte_aan_r...@hotmail.com> wrote:
> > Anyone?
>
> > On 14 jul, 15:39, HAUSa <jeroen_heeft_behoefte_aan_r...@hotmail.com>
> > wrote:
> >> Yes:
>
> >> advertisement_show:
> >> url: /:sf_culture/advertisement/show/:id/:slug/*
> >> class: sfPropelRoute
> >> options: { model: Advertisement, type: object }
> >> param: { module: advertisement, action: show }
> >> requirements:
> >> sf_method: [get, post]
> >> sf_culture: (?:en|es|de|fr|nl)
>
> >> On 14 jul, 15:32, Gábor Fási <maerl...@gmail.com> wrote:
>
> >> > Is your route declared as sfPropelRoute/sfDoctrineRoute?
>
> >> > On Wed, Jul 14, 2010 at 15:23, HAUSa
>
> >> > <jeroen_heeft_behoefte_aan_r...@hotmail.com> wrote:
> >> > > I can't use genUrl like this:
> >> > > genUrl('advertisement_show', $Advertisement)
> >> > > where $Advertisement is the object for the sfObjectRoute
>
> >> > > The only way to do so is to call it like this:
> >> > > genUrl('advertisement_show?id=' . $Advertisement->getId() . '&slug=' .
> >> > > $Advertisement->getSlug())
>
> >> > > But that, ofcourse, kills the flexibility of the routing system!
> >> > > How can I do the top solution with getUrl?
>
> >> > > --
> >> > > If you want to report a vulnerability issue on symfony, please send it
> >> > > to security at symfony-project.com
>
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--
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