New command, Value type: $type:=Value type($col[0])
And note if you use the new For each loop in version 17, all collection elements must have the same type. John DeSoi, Ph.D. > On Apr 26, 2018, at 10:36 AM, Kirk Brooks via 4D_Tech <4d_tech@lists.4d.com> > wrote: > > If I'm iterating through a collection how can I get the type of an element? > Here are some results from current attempts: > $col:=New collection(New object;123;"XYZ";New collection) > $type:=Type($col) // type = 42 > $type:=Type($col[0]) // err: 4D was expecting a field or variable or > parameter > $type:=Type($col[1]) // err: 4D was expecting a field or variable or > parameter > C_OBJECT($obj) > $obj:=$col[0] > $type:=Type($obj) // 38 > $obj:=$col[1] > $type:=Type($obj) // err: argument types are incompatible ********************************************************************** 4D Internet Users Group (4D iNUG) FAQ: http://lists.4d.com/faqnug.html Archive: http://lists.4d.com/archives.html Options: https://lists.4d.com/mailman/options/4d_tech Unsub: mailto:4d_tech-unsubscr...@lists.4d.com **********************************************************************
