after a bit of actual thought, i think that NaN
is supposed to generate a note.  if you do catch
the note, the program should work fine.

e.g.

#include <u.h>
#include <libc.h>

void
note(void *, char *s)
{
        if(strncmp(s, "sys: fp: ", 8) == 0)
                noted(NCONT);
        noted(NDFLT);
}

void
main(void)
{
        double d;

        notify(note);
        d = NaN();
        print("%g\n", d);
}

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