> def start_service(service, machine):
> """Start a service"""
> win32serviceutil.StartService(service, machine)
> result = 1 #Service started successfully
>
> If I try to start a service and it is already running, I get the following
> error:
> api_error: (1056, 'StartService', 'An instance of the service is already
> running.')
>
> How would I use exception handling to catch this?
def start_service(service, machine):
"""Start a service"""
try:
win32serviceutil.StartService(service, machine)
result = 1 #Service started successfully
except win32service.error:
result = 0
Mark.
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