Noah Spurrier wrote:
> You want to use map and lamdda. This works on your list:
> map(lambda x: x.replace('\n',''), MyList)
Why not list comprehensions? Most places where map/filter and lambda are
used, a list comp is easier and clearer (and usually faster):
MyList = [x.replace('\n','') for x in MyList]
> Also remember that Strings have their own replace method, so
> if you don't really need to do a regular expression substitution
> then String.replace() is faster.
This is definately true. String methods are faster and more convenient
than regexes, and usually less confusing. ;) Don't use regular
expressions unless string methods just can't do what you need.
> I always thought lambda expression were hard to read
> (mainly I think 'lambda' is an obscure name for most
> non-computer science majors) , but at any rate it is a
> useful syntax to learn.
It's worse than that -- the syntax just looks non-Pythonic. It's harder
to remember something that's inconsistent. Plus, a lambda costs as much
as a regular function def -- you still have to build the function object,
and you still get function-call costs, whereas list comprehensions avoid
(most of) those costs.
Jeff Shannon
Technician/Programmer
Credit International
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