You can sort of tell this on the server side by doing a query like this:

q actlog begind=-1 search=nodename

By looking that time entries for the hits you get if you see a definite time
pattern, say every six hours, you can probably assume polling.  If you see
only a single hit or perhaps none, you can either assume prompted (and the
client didn't start its scheduler in the previous 24 hours) or the client
scheduler daemon/service isn't running.

Not terribly scientific, but it helps to get you close to the answer.

Kelly J. Lipp
Storage Solutions Specialists, Inc.
PO Box 51313
Colorado Springs, CO 80949
[EMAIL PROTECTED] or [EMAIL PROTECTED]
www.storsol.com or www.storserver.com
(719)531-5926
Fax: (240)539-7175


-----Original Message-----
From: ADSM: Dist Stor Manager [mailto:[EMAIL PROTECTED]]On Behalf Of
Martin, Jon R.
Sent: Thursday, January 24, 2002 6:32 AM
To: [EMAIL PROTECTED]
Subject: Re: Identifying client schedule mode.


Sias,

What you are saying is accurate but if the client is using prompted, the
server somehow needs to know that.  The point being if you tell me to call
you I would need to have a system for remembering that.  If the client
requests to be prompted then the server must also have a way of
knowing/remembering that.

Jon M

-----Original Message-----
From: Sias Dealy [mailto:[EMAIL PROTECTED]]
Sent: Thursday, January 24, 2002 7:36 AM
To: [EMAIL PROTECTED]
Subject: Re: Identifying client schedule mode.


Jon,

Bad news, you can not see what the schedmode for the
client on the server.
Because the parameter is set in the dsm.sys file
(Unix) or the dsm.opt file (Windows).
If you do not see the schedmode parameter in the
file then the default is being used.
I believe the default is polling.

Sias Dealy




--- "Martin, Jon R." <[EMAIL PROTECTED]> wrote:
> Hello, this should be an easy one...
>
> The TSM Server has schedmode set to any.  What can I
> run from the server to
> see what mode a client is using?  I have been
> selecting from various tables
> but have not had any luck in finding the answer.
>
> Thanks,
> Jon


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