I found this on thevenins therom.. I am still trying to understand this
therom but it seems that this is a way to look at this.
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/thevenin.html
On 3/9/2017 7:22 PM, Chuck McCown wrote:
Nodal and Mesh but this is a simple single loop, so those techniques
are not needed.
I will give a hint, the solution is not linear.
*From:* Matt
*Sent:* Thursday, March 09, 2017 5:02 PM
*To:* [email protected]
*Subject:* Re: [AFMUG] Fw: Ohms law
Trying to remember DC Principles many many years ago. I am sure its
simple. This would be called circuit analysis. Nodal? What were the
other methods again?
On Thu, Mar 9, 2017 at 5:46 PM, Chuck McCown <[email protected]> wrote:
This all started with the VDSL2 ethernet line extenders. They are
a constant load of 6 watts. I want to power them over the pair of
wires that the VDSL signal is going over. So the question is, if
I put 48 volts on the pair at the house through a VDSL filter, can
I get enough power out at the far end to power that VDSL unit.
100 ohm loop. About 2000 feet of 24 gauge. The answer is yes.
Current is 0.12953 A
Voltage at the load is 46.322 V
You can brute force it with trial and error, that is how I got my
first estimate, but I wanted to know exactly. There is a formula.
Trying to visualize how I would use Thevenin. The battery is a
short, right? So from the load’s perspective you are seeing 100
ohms. Not sure what the Thevenin equivalent of a constant power
load is.
*From:* Chuck McCown
*Sent:* Thursday, March 09, 2017 4:28 PM
*To:* [email protected]
*Subject:* Re: [AFMUG] Ohms law
But what is the formula?
*From:* Dave
*Sent:* Thursday, March 09, 2017 4:20 PM
*To:* [email protected]
*Subject:* Re: [AFMUG] Ohms law
Current =.125A at load
Voltage=35.5 at load
If my current is correct then I should be on point.
Otherwise I would use Thevenins Therom to get closer.
On 03/09/2017 05:08 PM, Chuck McCown wrote:
The questions are:
What is the current and voltage on the load.�
�
*From:* Chuck McCown
*Sent:* Thursday, March 09, 2017 4:05 PM
*To:* [email protected]
*Subject:* [AFMUG] Ohms law
�
Had a fun afternoon.�
�
Solve this.... and give the general formula...
�
48 volt power supply
100 ohm wire resistance to the load.
6 watt load.
�
Took me some time.� Not trivial.�
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