On Thu, Mar 27, 2008 at 9:20 PM, Ian Kelly <[EMAIL PROTECTED]> wrote: > I think you're wrong. ceiling(50 - ((50N-1)/N)) = ceiling(1/N) = 1. Oh.. you're right. Well, in that case, you'd get positive sum, S > 50N. With zero-sum, it would only be possible for all parties to leave if each had exactly 50 VP; if anyone had 51 VP, there wouldn't be enough VP among the rest to go around; not so with positive-sum. That's not the end of the world, but I would prefer a real zero-sum game.
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- Re: DIS: Re: BUS: Vote Market - Broker's Repo... Ian Kelly
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- DIS: Re: BUS: Vote Market - Broker's Report Roger Hicks
- DIS: Re: BUS: Vote Market - Broker's Report Roger Hicks