My bad ;) Okay, I will proceed with a Transformer approach. Thanks for the push in the right direction.
On Wednesday, September 3, 2014 10:04:30 AM UTC-4, √ wrote: > > That was not the thing you asked for, you had a single ByteString. :) > > If you want to do that then you need to create a Transformer and use the > `transform` method. > > > On Wed, Sep 3, 2014 at 3:55 PM, Chris Baxter <cba...@gmail.com > <javascript:>> wrote: > >> Viktor, how would this work if the delimiter was not in the current >> ByteString, meaning that it's coming in a subsequent ByteString and I need >> to buffer this ByteString until the next one comes through? >> >> >> On Wednesday, September 3, 2014 8:42:46 AM UTC-4, √ wrote: >> >>> def chop(find: Byte, in: ByteString, res: Seq[ByteString] = Nil): >>> Seq[ByteString] = in.indexOf(find) match { >>> case -1 => res >>> case x => >>> val chunk = in.take(x) >>> chop(find, in.drop(x + 1), if (chunk.isEmpty) res else res :+ chunk) >>> } >>> >>> scala> chop('.', ByteString("")) >>> res10: Seq[akka.util.ByteString] = List() >>> >>> scala> chop('.', ByteString("....")) >>> res11: Seq[akka.util.ByteString] = List() >>> >>> scala> chop('.', ByteString("Lorem Ipsum is simply.Dummy text of the >>> printing.And typesetting industry.")).map(_.utf8String) >>> res12: Seq[String] = List(Lorem Ipsum is simply, Dummy text of the >>> printing, And typesetting industry) >>> >>> Flow(data).mapConcat(bs => chop('.', bs)).etc >>> >>> >>> On Wed, Sep 3, 2014 at 2:15 PM, Chris Baxter <cba...@gmail.com> wrote: >>> >>>> Posted this on Stackoverflow but haven't seen any activity on it so I >>>> figured I'd post it here as well. >>>> >>>> I've been playing around with the experimental Akka Streams API a bit >>>> and I have a use case that I wanted to see how to implement. For my use >>>> case, I have a `StreamTcp` based `Flow` that is being fed from binding the >>>> input stream of connections to my server socket. The Flow that I have is >>>> based on `ByteString` data coming into it. The data that is coming in is >>>> going to have a delimiter in it that means I should treat everything >>>> before >>>> the delimiter as one message and everything after and up to the next >>>> delimiter as the next message. So playing around with a simpler example, >>>> using no sockets and just static text, this is what I came up with: >>>> >>>> import akka.actor.ActorSystem >>>> import akka.stream.{ FlowMaterializer, MaterializerSettings } >>>> import akka.stream.scaladsl.Flow >>>> import scala.util.{ Failure, Success } >>>> import akka.util.ByteString >>>> object BasicTransformation { >>>> def main(args: Array[String]): Unit = { >>>> implicit val system = ActorSystem("Sys") >>>> val data = ByteString("Lorem Ipsum is simply.Dummy text of the >>>> printing.And typesetting industry.") >>>> Flow(data). >>>> splitWhen(c => c == '.'). >>>> foreach{producer => >>>> Flow(producer). >>>> filter(c => c != '.'). >>>> fold(new StringBuilder)((sb, c) => sb.append(c.toChar)). >>>> map(_.toString). >>>> filter(!_.isEmpty). >>>> foreach(println(_)). >>>> consume(FlowMaterializer(MaterializerSettings())) >>>> }. >>>> onComplete(FlowMaterializer(MaterializerSettings())) { >>>> case any => >>>> system.shutdown >>>> } >>>> } >>>> } >>>> >>>> The main function on the `Flow` that I found to accomplish my goal was >>>> `splitWhen`, which then produces additional sub-flows, one for each >>>> message >>>> per that `.` delimiter. I then process each sub-flow with another >>>> pipeline >>>> of steps, finally printing the individual messages at the end. >>>> >>>> This all seems a bit verbose, to accomplish what I thought to be a >>>> pretty simple and common use case. So my question is, is there a cleaner >>>> and less verbose way to do this or is this the correct and preferred way >>>> to >>>> split a stream up by a delimiter? >>>> >>>> The link to the SO question is: http://stackoverflow.com/ >>>> questions/25631099/how-to-split-an-inbound-stream-on-a- >>>> delimiter-character-using-akka-streams >>>> >>>> -- >>>> >>>>>>>>>> Read the docs: http://akka.io/docs/ >>>> >>>>>>>>>> Check the FAQ: http://doc.akka.io/docs/akka/ >>>> current/additional/faq.html >>>> >>>>>>>>>> Search the archives: https://groups.google.com/ >>>> group/akka-user >>>> --- >>>> You received this message because you are subscribed to the Google >>>> Groups "Akka User List" group. >>>> To unsubscribe from this group and stop receiving emails from it, send >>>> an email to akka-user+...@googlegroups.com. >>>> To post to this group, send email to akka...@googlegroups.com. >>>> >>>> Visit this group at http://groups.google.com/group/akka-user. >>>> For more options, visit https://groups.google.com/d/optout. >>>> >>> >>> >>> >>> -- >>> Cheers, >>> √ >>> >> -- >> >>>>>>>>>> Read the docs: http://akka.io/docs/ >> >>>>>>>>>> Check the FAQ: >> http://doc.akka.io/docs/akka/current/additional/faq.html >> >>>>>>>>>> Search the archives: https://groups.google.com/group/akka-user >> --- >> You received this message because you are subscribed to the Google Groups >> "Akka User List" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to akka-user+...@googlegroups.com <javascript:>. >> To post to this group, send email to akka...@googlegroups.com >> <javascript:>. >> Visit this group at http://groups.google.com/group/akka-user. >> For more options, visit https://groups.google.com/d/optout. >> > > > > -- > Cheers, > √ > -- >>>>>>>>>> Read the docs: http://akka.io/docs/ >>>>>>>>>> Check the FAQ: >>>>>>>>>> http://doc.akka.io/docs/akka/current/additional/faq.html >>>>>>>>>> Search the archives: https://groups.google.com/group/akka-user --- You received this message because you are subscribed to the Google Groups "Akka User List" group. 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