The results will travel to the Sink, so you'll have to not `ignore` the
result.
On Tue, Jun 9, 2015 at 9:15 AM, Владимир Морозов <greenhos...@gmail.com>
wrote:
> Hi,
>
> I play more with actorPublisher, yes it is great thing, but - when I have
> stream like this:
>
> val jobManagerSource = Source.actorPublisher[UserRegisterSource.
> RegisterUser](UserRegisterSource.props)
>
> val ref = Flow[UserRegisterSource.RegisterUser]
> .mapAsync(1)(callMe)
> .to(Sink.ignore)
> .runWith(jobManagerSource)
>
> ref ? UserRegisterSource.RegisterUser("test")
>
> And then ask it, like in previous message, in ask result I see what
> jobManagerSource answer me. I can't understand how I can send some value
> to actorPublisher source and then obtain result of flow execution
>
> понедельник, 8 июня 2015 г., 1:10:01 UTC+3 пользователь Владимир Морозов
> написал:
>
>> I solve this problem, but found new one:
>>
>> val ref = Flow[UserRegisterSource.RegisterUser]
>> .mapAsync(1)(callMe)
>> .to(Sink.ignore)
>> .runWith(jobManagerSource)
>>
>> val t = (ref ask
>> UserRegisterSource.RegisterUser("test")).mapTo[UserRegisterSource.RegisterUser]
>>
>> but t never complete, always end with Timeout exception
>>
>> воскресенье, 7 июня 2015 г., 23:13:29 UTC+3 пользователь Владимир Морозов
>> написал:
>>>
>>> Hi,
>>>
>>> I try but get error message:
>>>
>>> java.lang.IllegalStateException: onNext is not allowed when the stream
>>> has not requested elements, totalDemand was 0
>>>
>>> My code is:
>>>
>>> val jobManagerSource =
>>> Source.actorPublisher[UserRegisterSource.RegisterUser](UserRegisterSource.props)
>>>
>>> val ref = Flow[UserRegisterSource.RegisterUser]
>>> .mapAsync(1)(callMe)
>>> .to(Sink.ignore)
>>> .runWith(jobManagerSource)
>>>
>>> ref ! UserRegisterSource.RegisterUser("test")
>>>
>>>
>>> class UserRegisterSource extends
>>> ActorPublisher[UserRegisterSource.RegisterUser] {
>>>
>>> import akka.stream.actor.ActorPublisherMessage._
>>> import UserRegisterSource._
>>>
>>> val MaxBufferSize = 100
>>> var buf = Vector.empty[RegisterUser]
>>>
>>> override def receive: Receive = {
>>> case request: RegisterUser =>
>>> onNext(request)
>>> case Cancel =>
>>> context.stop(self)
>>> }
>>> }
>>>
>>>
>>> воскресенье, 7 июня 2015 г., 14:53:15 UTC+3 пользователь Akka Team
>>> написал:
>>>>
>>>> Hi,
>>>>
>>>> On Fri, Jun 5, 2015 at 7:53 PM, Владимир Морозов <green...@gmail.com>
>>>> wrote:
>>>>
>>>>> Yes, I know about mapAsync, but my problem with Source. A want to use
>>>>> single stream for processing some group of events
>>>>>
>>>>
>>>> I am not sure if I understand your question properly, but if you want
>>>> to run the stream *once* and then reuse the stream for all the requests,
>>>> then you can try to create an ActorPublisher as your Source, then run the
>>>> stream outside of the Http handler logic. You can then use "ask" on that
>>>> actor in the Http route.
>>>>
>>>> -Endre
>>>>
>>>>
>>>>>
>>>>> пятница, 5 июня 2015 г., 20:29:16 UTC+3 пользователь Paul Kinsky
>>>>> написал:
>>>>>
>>>>>> Use mapAsync: `def mapAsync[T](parallelism: Int)(f: (Out) ⇒
>>>>>> Future[T]): Repr[T, Mat]`.
>>>>>>
>>>>>> On Friday, June 5, 2015 at 9:23:24 AM UTC-7, Владимир Морозов wrote:
>>>>>>>
>>>>>>> Hi all,
>>>>>>>
>>>>>>> I have some simple application based on akka streams and http:
>>>>>>>
>>>>>>> My Flow items:
>>>>>>>
>>>>>>> val resultSink = Sink.head[String]
>>>>>>>
>>>>>>> val fl0 = Flow[String].map(_.toInt)
>>>>>>> val fl2 = Flow[Int].map{
>>>>>>> case value =>
>>>>>>> Thread.sleep(10000)
>>>>>>> value.toString
>>>>>>> }
>>>>>>> val fl3 = Flow[String].mapAsync(1)(callMe)
>>>>>>>
>>>>>>>
>>>>>>> Part of my akka-http route:
>>>>>>>
>>>>>>> val route = get {
>>>>>>> path("test") {
>>>>>>> path("register") {
>>>>>>> parameter('username) { case username: Username =>
>>>>>>>
>>>>>>> Source.single(username).via(fl0).via(fl2).via(fl3).runWith(resultSink):
>>>>>>> Future[String]
>>>>>>> }
>>>>>>> }
>>>>>>> }
>>>>>>>
>>>>>>> I want to use one flow : Source.single(username).
>>>>>>> via(fl0).via(fl2).via(fl3).runWith(resultSink) for processing all
>>>>>>> requests. I want this for use streams back-pressure. But I can't figure
>>>>>>> out
>>>>>>> how create Source that can accept values like call def proccess(
>>>>>>> username: String): Future[String] but with back-pressure, because,
>>>>>>> for example, a want long-call DB in fl2 step, and DB can't accept
>>>>>>> more than 1 request per time (only for example)
>>>>>>>
>>>>>>> With best regards, Vladimir.
>>>>>>>
>>>>>>> --
>>>>> >>>>>>>>>> Read the docs: http://akka.io/docs/
>>>>> >>>>>>>>>> Check the FAQ:
>>>>> http://doc.akka.io/docs/akka/current/additional/faq.html
>>>>> >>>>>>>>>> Search the archives:
>>>>> https://groups.google.com/group/akka-user
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>>>>>
>>>>
>>>>
>>>>
>>>> --
>>>> Akka Team
>>>> Typesafe - Reactive apps on the JVM
>>>> Blog: letitcrash.com
>>>> Twitter: @akkateam
>>>>
>>> --
> >>>>>>>>>> Read the docs: http://akka.io/docs/
> >>>>>>>>>> Check the FAQ:
> http://doc.akka.io/docs/akka/current/additional/faq.html
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--
Cheers,
√
--
>>>>>>>>>> Read the docs: http://akka.io/docs/
>>>>>>>>>> Check the FAQ:
>>>>>>>>>> http://doc.akka.io/docs/akka/current/additional/faq.html
>>>>>>>>>> Search the archives: https://groups.google.com/group/akka-user
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