I just tried the following (on 2.0-M1): scala> Source(1 to 100).map{i ⇒ println(i); i}.grouped(10).runWith(Sink.head) 1 2 3 4 5 6 7 8 9 10 11 res10: scala.concurrent.Future[scala.collection.immutable.Seq[Int]] = scala.concurrent.impl.Promise$DefaultPromise@2df79942 12 13 14 15 16
scala> 17 18 19 20 21 22 23 24 res10.onComplete(println) Success(Vector(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)) A similar behavior can be seen for the take function: scala> Source(1 to 100).map{i ⇒ println(i); i}.take(10).runWith(Sink.fold(Vector[Int]())(_ :+ _)) ... As one can see, the stream processes more elements than it has to. It is not a problem for me, but I would like to know if this behavior is spec'ed anywhere? Shouldn't the stream be able to say, just by looking at the arguments for grouped, take and the sink, how many elements should be produced? -- >>>>>>>>>> Read the docs: http://akka.io/docs/ >>>>>>>>>> Check the FAQ: >>>>>>>>>> http://doc.akka.io/docs/akka/current/additional/faq.html >>>>>>>>>> Search the archives: https://groups.google.com/group/akka-user --- You received this message because you are subscribed to the Google Groups "Akka User List" group. To unsubscribe from this group and stop receiving emails from it, send an email to akka-user+unsubscr...@googlegroups.com. To post to this group, send email to akka-user@googlegroups.com. Visit this group at http://groups.google.com/group/akka-user. For more options, visit https://groups.google.com/d/optout.