Hi,
I have a use case where I have to pass message between actors and send a
response back to the caller.
Once I get a request I invoke Actor A, which will do some DB call and
return results. But in certain cases actor A has to invoke actor B and get
some results from Actor B. It then has to return that result back to the
guy who sent the request. I accomplished this by passing a reference to the
original sender in the message that I send to actor B as shown below :
App {
val actor1 = system.actorOf(A)
val actor2 = system.actorOf(B)
//I want actor 1 to process this request
actor1 ? new Request("process this")
}
case class HandleSpecialConition(sender : ActorRef)
case class SpecialConditionResponse(sender : ActorRef, response: String)
A extends Actor {
def receive = {
case req : Request => {
//Checks for special condition and if so sends a message to actor2 and
the message is embedded with a reference to the sender to whom we have to
respond back
if (some_special_condition) {
actor2 ! new HandleSpecialCondition(sender)
} else {
"sending_back_response"
}
}
//when we get the response from Actor B it will contain the reference to
the original sender and we reply back to him
case response : SpecialConditionResponse => {
response.sender ! response.response
}
}
}
B extends Actor {
def receive = {
case m : HandleSpecialCondition {
//reply back to actor 1
sender ! new SpecialConditionResponse(m.sender, "Response for special
condition")
}
}
}
I wanted to ask if there is better way to accomplish this without passing
the original sender's reference around. Is there something wrong with this
kind of approach.
Thanks,
Karthik
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