u r right I think 2006/5/1, Manu <[EMAIL PROTECTED]>: > > i think we should take two pointers and then move the second pointer to > n-1 places from the first and then move both the pointers > simultaneously when the second pointer becomes null we get the first > pointer as the final answer... > > but the confusion is whether to count the movement of the second > pointer n-1 places ahead as being counted in the pass or not... > > > correct me if i m wrong plzzzzzzzzzzz..... > > > > >
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