[algogeeks] Re: Obtaining each digit from an integer in Java.

Fri, 22 Sep 2006 07:22:17 -0700

Why do you have to convert n to String again and again in the loop, and doing a substring for only one character?  Can't you just store the string once in the very beginning of your program and just do charAt(i) - '0' in every loop?
 
No doubt it will work, though.

 
On 9/22/06, Mukul Gandhi <[EMAIL PROTECTED]> wrote:

This is a complete Java program doing this:

class X {

  public static void main(String[] args) {
      int n = 5732;
      int len = ((new Integer(n)).toString()).length();

      int[] array = new int[len];

      for (int i = 0; i < len; i++) {
         String x = ((new Integer(n)).toString()).substring(i, i + 1);
         array[i] = (new Integer(x)).intValue();
      }
  }

}

Regards,
Mukul

Bullislander05 wrote:
> Hello,
>
> I'm fairly new to these parts and I come to ask a question.
>
> If anyone here has some experience in programming in Java, I would be
> enlightened to find out if there is any way to extract each digit from
> an integer.
>
> Say there was an integer with a value of 5732, how should I proceed to
> extract the 5, 7, 3, and 2 from said integer and transfer those values
> into an integer array?
>
> If anybody could help me out A.S.A.P I would be very grateful.
>
> Thank you,
> Bullislander05



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