Thanks Aakash, excellent work.
On Jan 25, 4:39 am, "aakash mandhar" <[EMAIL PROTECTED]> wrote:
> for(int i=0;i<=n/2;i++)
> {
> for(int j=0;j<=i;j++)
> {
> a[i][j]=='*';}for(int j=i+1;j<n;j++)
> {
> a[i][j]=='-';
>
> }
> }for(int i=n/2+1;i<n;i++)
> {
> for(int j=0;j<=(n-i);j++)
> {
> a[i][j]=='*';}for(int j=(n-i)+1;j<n;j++)
> {
> a[i][j]=='-';
>
> }
> }Where a is the result array
>
> R,
> Aakash
>
> On 1/24/07, delboy <[EMAIL PROTECTED]> wrote:
>
>
>
> > OK, I need to write an algorithm to populate a 2D array A(i,j) of size
> > n x n. There is 1 '*' in the 1st row, increasing to n/2 in the middle
> > row, this decreases back to 1'*' in the last row. We can also assume
> > that n is odd.
>
> > *----------
> > **---------
> > ***-------
> > ****------
> > *****-----
> > ****------
> > ***-------
> > **---------
> > *----------
>
> > Hope this clarifies things,
>
> > Del.
>
> > On Jan 24, 4:06 pm, "Sandesh" <[EMAIL PROTECTED]> wrote:
> > > Not clear,
> > > give the full explanation .........
> > > Sandesh Hegde
>
> > > On Jan 24, 8:32 pm, "delboy" <[EMAIL PROTECTED]> wrote:
>
> > > > Hi,
>
> > > > I'm trying to input the following values into a 2D array via some sort
> > > > of method / algorithm. Any ideas on the best way to approach this?
>
> > > > *----------
> > > > **---------
> > > > ***-------
> > > > ****------
> > > > *****-----
> > > > ****------
> > > > ***-------
> > > > **---------
> > > > *----------
>
> > > > Thanks,
> > > > Del
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