Hi,

I think this can be done like.
1)Consider a point and check all the points around it which are
different from it.
2)this can be done recursively...
3)if we get a pixel whose id is same as already visited one...don't
consider that.


On 4/15/07, elesser <[EMAIL PROTECTED]> wrote:
>
> Hello,
>
> In a program I am currently writing, I have a matrix (around 60000 x
> 3) containing information about the pixels in an image: every row of
> the matrix has information about 1 pixel. The first column contains
> the pixel id and the following two columns contain the x and y
> coordinates. If two rows have the same pixel id, this indicates that
> these two pixels have exactly the same RGB values.
>
> What I'm now trying to do is finding the smallest box in the image
> that contains ALL the colors in the image, that is, that contains
> every pixel with different RGB values at least one time. As far as I
> know, this is done by comparing all x and y coordinates of all the
> pixels with one another, looking for the smallest difference when
> substracting the xy values from each other. The problem is that from
> all identical pixel id's, one pixel has to be chosen that, overall, is
> the closest to all other pixels.
>
> Does anyone have any idea how to do this? I'm programming in MATLAB,
> but code in C or C++ is fine.
>
> Thanks.
>
>
> >
>


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