thanx for ur help :D On May 28, 5:22 pm, Satya <[EMAIL PROTECTED]> wrote: > since your input is of fixed size, your algorithm always runs in > constant time. If the # of students and # of courses are variable, the > algorithm is O(n^2). > > satya. > > On 5/28/07, sl7fat <[EMAIL PROTECTED]> wrote: > > > > > > > > > hi i have an algorthim code and i have to find the time complixcity of > > the code so can you plz help me ASAP the code is written done ,, > > # include <iostream.h> > > > void main() > > { > > > int a[10][4]= > > {{ 16,17,19,13}, > > {18,14,15,19}, > > {18,20,20,19}, > > {13,14,15,10}, > > {20,17,19,19}, > > {18,13,18,19}, > > {18,10,15,12}, > > {12,14,15,11}, > > {12,16,17,18}, > > {18,11,15,10}} ; > > > int i,j,max,min; > > float avg,sum; > > > for(i=0;i<10;i++) > > { > > > for(j=0;j<4;j++) > > { > > > cout << a[i][j] << " "; > > } > > cout << "\n"; > > } > > > for(i=0;i<4;i++) > > { > > max= a[0][i]; > > min= a[0][i]; > > sum=0; > > > for(j=1;j<10;j++) > > { > > > sum= sum+a[j][i]; > > if(a[j][i]>max) > > max=a[j][i]; > > > if(a[j][i]<min) > > min=a[j][i]; > > } > > > avg= sum/10; > > > cout << "The average Grade for Exam "<<i+1<< " is: "<< > > avg<<"\n"; > > cout << "The minimum Grade for Exam "<<i+1<< " is: "<< > > min<<"\n"; > > cout << "The maximum Grade for Exam "<<i+1<< " is: "<< > > max<<"\n\n"; > > > } > > > for(i=0;i<10;i++) > > { > > min= a[i][0]; > > sum=0; > > for(j=0;j<4;j++) > > { > > sum= sum+a[i][j]; > > if ( min>a[i][j]) > > min= a[i][j]; > > > } > > sum= sum-min; > > > cout << " The summation of the best 3 grades for student No > > "<< i > > +1<< " is: "<< sum<<"\n"; > > } > > > } > > > thanx alot :D > > -- > ...what's remarkable, is that atoms have assembled into entities which > are somehow able to ponder their origins. > --http://cs.uic.edu/~spopuri- Hide quoted text - > > - Show quoted text -
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