in case of sets of sets of word we need to tokenize each set of word .
use
for(int i=0;(a[i]!='\0')||(a[i]=='\b');i++)
int a+=a[i];
once tokenize
we need to appedn them in a vector just line we use the type as string .we
need to use the brute force for it.

On Sat, Sep 6, 2008 at 6:03 PM, Dave <[EMAIL PROTECTED]> wrote:

>
> This is not a very general algorithm. For example, how would you use
> it to find the intersection of two sets of words?
>
> Dave
>
> On Sep 6, 3:50 am, sharad kumar <[EMAIL PROTECTED]> wrote:
> > in order t ofind intersection of 2 sets just
> > use counting principle of finding the the of times each element
> > ocucurs in each set .then we find check if 2 sets have a aprticular no
> > same times then we include it in the new set .
> > in case of union we use principle of merge sort in additon to this
> > above principle.
> > that is apart from commmon nos. we have to inlcude the other nos
> >
>

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