Can you give your problem instead of a program? People will have hard time
understanding the C Program. It would be better if you can tell what is the
problem you are trying to solve.

regards,
Arun.

On Wed, Dec 17, 2008 at 7:23 AM, sharad kumar <[email protected]>wrote:

>
> hi,
> this is a part of source code for page ranking algo used for search
> engine.its similar to RIP and OSPF
> o/p:probabilities
>
>
> #include<iostream.h>
> #include<conio.h>
> #include<algorithms.h>
> int main()
> {
> int adj[10][10],prob1[10][10],prob2[9][9],adj1[9][9];
> int prob,i,j,k,l,c;
> cout<<endl;
> cout<<"nter dependency matrix"<<endl;
> for(i=0;i<10;i++)
> {
>  for(j=0;j<n;j++)
> {
> cout<<"nter 1 for dependency else 0";
> cin>>k;
> if(k)
> {
> adj[i][j]=1;
> c++;
> }
> else
> {
> adj[i][j]=0;
> continue;
> }
> }
>  for(l=0;l<n;l++)
> prob1[i][l]=(1/c);
> }
> for(i=0;i<n;i++)
>  {
> for(j=0;j<n;j++)
> {
> int max1=prob1[i][j];
> if(prob1[i][j]>max)
> max=prob1[i][j];
> else
> continue;
> }
> cout<<"the page for corresponding keyword searched is";
> //for  other pages
> }
>
> for(i=1;i<=n;i++)
>  for(j=1;j<=n;j++)
> adj1[i][j]=adj[i][j];
> for(k=0;k<n;k++)
>  for(i=0;i<n;i++)
>  for(j=0;j<n;j++)
> {
> if(prob1[i][j]<=1&&prob1[i][k]+prob1[k][j]<=1)
> {
> if(prob1[i][j]>prob1[i][k]+prob1[k][j])
> prob2[i][j]=min(prob1[i][j],prob1[i][k]+prob1[k][j]);
> adj1[i][j]=adj[i][j];
> }
> elseif(prob1[i][j]>1)
> {
> prob2[i][j]=1;
> adj1[i][j]=adj[i][j];
> }
> else
> {
> prob2[i][j]=1;
> adj1[i][j]=j;
> }
> max2=prob2[0][0];
> for(i=0;i<9;i++)
>  for(j=0;j<9;j++)
>  max1=max(max2,prob2[i][j]);
>  cout<<"the page for corresponding keyword searched is";
> //for  other pages call this routine recursively;
> }
>
> pls tell any dp solution for it
>
> >
>


-- 
===================================
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http"//ww.livejournal.com/users/arunachalam

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