If you really want to print the buffer array outside the local scope
the declare it using a static specifier..
eg...'
#include<stdio.h>
char *modify (char *s)
{
#define MAX 15
static char buffer[MAX];
strcpy (buffer, s);
buffer[0] = 'H';
return buffer;
}
int
main ()
{
printf ("hello!!!\n\n");
printf ("%s ", modify ("hello!!!.."));
getch();
}
then you will get the desired output .. although I would not recommend
such method...
use call by reference instead.
Pratyush Tewari
On Tue, Jan 6, 2009 at 1:47 PM, daizi sheng <daizish...@gmail.com> wrote:
>
> there is no expected output of this program because it is obviously
> implement dependent. if you really want to know the results, try to
> run it. if you want to know why, dump the assemble code to check it
> manually.
>
> anyway, I do not think this topic is related to this group.
>
>
>
> On Tue, Jan 6, 2009 at 5:18 AM, tania hamid <tan3...@gmail.com> wrote:
>>
>>
>> Plz indicate the output of the following code and explain why is it so..
>>
>>
>> char *modify (char *s)
>> {
>> #define MAX 15
>> char buffer[MAX];
>> strcpy (buffer, s);
>>
>> buffer[0] = 'H';
>> return buffer;
>> }
>>
>> int
>> main ()
>> {
>> printf ("hello!!!");
>> printf ("%s ", modify ("hello!!!"));
>> }
>>
>> >
>>
>
> >
>
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