10101010 = 170 On Fri, Aug 14, 2009 at 8:04 PM, sharad kumar <aryansmit3...@gmail.com>wrote:
> boss will ur code work for 330 in binary 10101010?? > > On Fri, Aug 14, 2009 at 3:09 PM, Arun N <arunn3...@gmail.com> wrote: > >> take an number find its binary >> add all odd bits and even bits seperately >> now check if the difference is divisible by 3 >> if yes it is >> say 6 110 -----> 1+0 - 1 =0 >> 9 1001 -----> 1+0 - 0+1 = 0 >> 12 1100 ------> 1+0 - 1+0 = 0 >> Arun, >> >> On Fri, Aug 14, 2009 at 1:15 PM, richa gupta <richa.cs...@gmail.com>wrote: >> >>> >>> can we check the divisibility of a given number by 3 withoutusing >>> operators like '/' or '%'. >>> I want the efficient solution to this problem .. >>> >>> can someone help ?? >>> -- >>> Richa Gupta >>> (IT-BHU,India) >>> >>> >>> >> >> >> -- >> Potential is not what U have, its what U think U have!!! >> It is better to worn out than rust. >> >> >> >> >> > > > > -- Regards, Saurabh Aggarwal --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---
